MPI Maelstrom BIT has recently taken delivery of their new supercomputer, a 32 processor Apollo Odyssey distributed shared memory machine with a hierarchical communication subsystem. Valentine McKee's research advisor, Jack Swigert, has asked her to…

POJ 1502 MPI Maelstrom / UVA 432 MPI Maelstrom / SCU 1068 MPI Maelstrom / UVALive 5398 MPI Maelstrom /ZOJ 1291 MPI Maelstrom (最短路径) Description BIT has recently taken delivery of their new supercomputer, a 32 processor Apollo Odyssey distributed shar…

MPI Maelstrom Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 4017   Accepted: 2412 Description BIT has recently taken delivery of their new supercomputer, a 32 processor Apollo Odyssey distributed shared memory machine with a hierarchic…

传送门 MPI Maelstrom Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 5711   Accepted: 3552 Description BIT has recently taken delivery of their new supercomputer, a 32 processor Apollo Odyssey distributed shared memory machine with a hierar…

MPI Maelstrom Time Limit : 2000/1000ms (Java/Other)   Memory Limit : 20000/10000K (Java/Other) Total Submission(s) : 2   Accepted Submission(s) : 1 Problem Description BIT has recently taken delivery of their new supercomputer, a 32 processor Apollo…

MPI Maelstrom Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 6044   Accepted: 3761 Description BIT has recently taken delivery of their new supercomputer, a 32 processor Apollo Odyssey distributed shared memory machine with a hierarchic…

题目链接:http://poj.org/problem?id=1502 题意是给你n个点,然后是以下三角的形式输入i j以及权值,x就不算 #include <iostream> #include <cstdio> #include <cstring> #include <queue> using namespace std; ; const int INF = 1e9; typedef pair <int , int> P; struct da…

题目大意: 给你 1到n ,  n个计算机进行数据传输, 问从1为起点传输到所有点的最短时间是多少, 其实就是算 1 到所有点的时间中最长的那个点. 然后是数据 给你一个n 代表有n个点, 然后给你一个邻接矩阵, 只有一半,另一半自己补 下面是练习的代码. 分别用了Floyd 和 Dijkstra 还有 Spfa(邻接矩阵版) #include <iostream> #include <cmath> #include <cstring> #include <cst…

Description BIT has recently taken delivery of their new supercomputer, a 32 processor Apollo Odyssey distributed shared memory machine with a hierarchical communication subsystem. Valentine McKee's research advisor, Jack Swigert, has asked her to be…

题目: BIT has recently taken delivery of their new supercomputer, a 32 processor Apollo Odyssey distributed shared memory machine with a hierarchical communication subsystem. Valentine McKee's research advisor, Jack Swigert, has asked her to benchmark…

题目大意:求点1到所有点最短路径的最大值 思路:水题,单源最短路,网上解题清一色dijkstra,但是点数小于100显然floyd更简洁嘛 #include<cstdio> #include<string.h> #define maxn 101 #define inf 100000 using namespace std; int read(){ int f=1,x=0;char ch=getchar(); while(ch<'0'||ch>'9'){if(ch=='x…

MPI Maelstrom Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 5547   Accepted: 3458 Description BIT has recently taken delivery of their new supercomputer, a 32 processor Apollo Odyssey distributed shared memory machine with a hierarchic…

题目链接:http://poj.org/problem?id=1502 Description BIT has recently taken delivery of their processor Apollo Odyssey distributed shared memory machine with a hierarchical communication subsystem. Valentine McKee's research advisor, Jack Swigert, has ask…

题目链接:http://poj.org/problem?id=1502 题意:一个处理器给n-1个处理器发送广播,问最短时间.广播时并发,也就是各个路径就大的一方.输入如果是x的话说明两个处理器不能相互通信.输入是矩阵的左三角. 题解:一个最短路的裸题吧.输入的时候注意一下字符的转换.floyd爆一遍之后再对每个路径找最大值即可. 代码: #include<cstdio> #include<cstdlib> #include<cstring> #include<i…

题意 : 给出 N 个点,各个点之间的路径长度用给出的下三角矩阵表示,上上角矩阵和下三角矩阵是一样的,主对角线的元素都是 0 代表自己到达自己不用花费,现在问你从 1 到 N 的最短路,矩阵的 x 代表点间无法互相到达 分析 : 最短路模板…… 就是在输入的时候需要将字符串变成整数.自己写也可以,也可以使用 atoi(char *)函数,其作用是将字符串数组变成整数,复杂度为 O(n) #include<bits/stdc++.h> using namespace std; ; const i…

链接:http://poj.org/problem?id=1502 MPI Maelstrom Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 5249   Accepted: 3237 Description BIT has recently taken delivery of their new supercomputer, a 32 processor Apollo Odyssey distributed share…

MPI Maelstrom Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 6499   Accepted: 4036 Description BIT has recently taken delivery of their new supercomputer, a 32 processor Apollo Odyssey distributed shared memory machine with a hierarchic…

POJ-1502 MPI Maelstrom 迪杰斯特拉+题解 题意 题意:信息传输,总共有n个传输机,先要从1号传输机向其余n-1个传输机传输数据,传输需要时间,给出一个严格的下三角(其实就是对角线之下的不包括对角线的部分)时间矩阵,a[i][j]代表从i向j传输数据需要的时间,并规定数据传输之间并无影响,即第一个传输机可以同时向其余传输机传输数据.求所有所有的机器都收到消息(他们收到消息后也可以传输)所需的最短时间. 解题思路 这个可以用迪杰斯特拉来求第一台机器到其他所有机器传输消息的时间,…

MPI Maelstrom 总时间限制:  1000ms 内存限制:  65536kB 描述 BIT has recently taken delivery of their new supercomputer, a 32 processor Apollo Odyssey distributed shared memory machine with a hierarchical communication subsystem. Valentine McKee's research advisor…

MPI Maelstrom Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 12087   Accepted: 7464 Description BIT has recently taken delivery of their new supercomputer, a 32 processor Apollo Odyssey distributed shared memory machine with a hierarchi…

POJ 3080 Blue Jeans (求最长公共字符串) Description The Genographic Project is a research partnership between IBM and The National Geographic Society that is analyzing DNA from hundreds of thousands of contributors to map how the Earth was populated. As an IB…

题目链接:https://vjudge.net/problem/POJ-1502 dijkstra板子题,题目提供下三角情况,不包含正对角线,因为有题意都为0,处理好输入,就是一个很水的题. #include <iostream> #include <cstring> #include <algorithm> #include <cstdio> #include <string> #include <vector> using nam…

#include<cstdio> #include<cstdlib> #include<cstring> #include<iostream> using namespace std; ; const int INF = 0x3f3f3f3f; ]; int n; int f[N][N]; void init() { ; i <= n ; i++) ; j <= n ; j++) if(i == j) f[i][j] = ; else f[i][…

题意:给N,表示N个节点. 给半个邻接矩阵,本身到本身的距离是0,边是双向的.当两个节点之间没有直接的边连接的时候,用x表示. 问从第一个节点到其他所有节点至少花费的时间. 这题唯一的处理是处理邻接矩阵的时候处理先当作字符串读入,然后处理一下数据,变成数据格式. 最后是输出第一个节点到其他所有节点最短路的最大值. #include<stdio.h> #include<string.h> int n; ; ][]; ][]; ]; ]; void solve(int pos) { v…

题目链接:http://poj.org/problem?id=3020 题目大意:读入一张地图.其中地图中圈圈代表可以布置卫星的空地.*号代表要覆盖的建筑物.一个卫星的覆盖范围是其周围上下左右四个点.问最少需要几个卫星才能覆盖所有建筑物. 解题思路: 有点类似POJ 1328的覆盖题,不过那题比较简单可以贪心.这题你可以YY试试. 覆盖问题其实可以用图论解决.这题就属于最小路径覆盖,手动由一个点出发连一些路径,这样Hungry就能求出最少需要多少这样的中心点,就可以达成目标了. 本题最大的疑问是…

http://poj.org/problem?id=1502 刷一道模板题稳定一下心情... Dijkstra求单源最短路,就是输入的时候注意下,是按下三角输入的(无向图),输入字符x表示i与j不通. 可以这样输入: if(scanf("%d",&w)) map[i][j] = map[j][i] = w; else scanf("x"); #include<stdio.h> #include<string.h> const int…

题目大意: BIT最近要取会他们的超级计算机,32处理器阿波罗奥德赛与分层通信子系统分布式共享内存的机器(听着很高端大气),瓦伦丁*麦基的顾问杰克*斯威特告诉她基准测试的新系统.(没有明白什么意思) “因为阿波罗是一个分布的共享内存的机器,内存的访问和交流通信的时间是不统一的”瓦伦丁告诉斯威特......(受不了了,这什么破英语,又臭又长还对话!!!!) 直接说这道题的意思算求,就是给一个临街矩阵,这个邻接矩阵因为上三角跟下三角一样,所以只给了下三角,* 号代表两点不相连,然后求出来点1到达所有…

题目地址:http://poj.org/problem?id=1606 广度优先搜索的经典问题,倒水问题.算法不需要多说,直接BFS,路径输出采用递归.最后注意是Special Judge #include<cstdio> #include<iostream> #include<algorithm> #include<cstring> #include<queue> using namespace std; ; queue<int>…

题意:给你无向带权图,求次短路径 题解:加一个次短路的数组,用于距记录源点到此点的次短路长度,注意初始化是源点到自己的次短路是极大值 接着再使用dijkstra算法,它是每次选用现在连上(记录了)的点与其他点的最小权值的边去更新其他所有的点 就是在dij的算法上进行简单的修改,需要修改的是每次最短路更新之后再更新次短路,但是保证更新的次短路大于记录的次短路并小于记录的最短路 #include<cstdio> #include<cstring> #include<queue&g…

Time Limit: 1000MS Memory Limit: 10000K Description BIT has recently taken delivery of their new supercomputer, a 32 processor Apollo Odyssey distributed shared memory machine with a hierarchical communication subsystem. Valentine McKee's research ad…