【LeetCode】206. Reverse Linked List 解题报告(Python&C++&java)

【【LeetCode】206. Reverse Linked List 解题报告(Python&C++&java)】的更多相关文章

【LeetCode】206. Reverse Linked List 解题报告(Python&C++&java)

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录题目描述题目大意解题方法迭代递归日期 [LeetCode] 题目地址:https://leetcode.com/problems/reverse-linked-list/ Total Accepted: 105474 Total Submissions: 267077 Difficulty: Easy 题目描述 Reverse a singly linked list.…

LeetCode 206 Reverse Linked List 解题报告

题目要求 Reverse a singly linked list. Example: Input: 1->2->3->4->5->NULL Output: 5->4->3->2->1->NULL 题目分析及思路给定一个单链表,要求得到它的逆序.可以使用列表对链表结点进行保存,之后新建一个列表对链表的逆序进行保存.最后返回新建列表的第一个元素即可. python代码 # Definition for singly-linked list. #…

leetcode 206. Reverse Linked List(剑指offer16)、

206. Reverse Linked List 之前在牛客上的写法: 错误代码: class Solution { public: ListNode* ReverseList(ListNode* pHead) { if(pHead == NULL) return NULL; ListNode* p1 = pHead; ListNode* p2 = pHead->next; ListNode* p3 = pHead->next->next; pHead->next = NULL;…

[LeetCode] 206. Reverse Linked List 反向链表

Reverse a singly linked list. Hint: A linked list can be reversed either iteratively or recursively. Could you implement both? 反向链表,分别用递归和迭代方式实现. 递归Iteration: 新建一个node(value=任意值, next = None), 用一个变量 next 记录head.next,head.next指向新node.next,新 node.next…

Java for LeetCode 206 Reverse Linked List

Reverse a singly linked list. 解题思路: 用Stack实现,JAVA实现如下: public ListNode reverseList(ListNode head) { if(head==null) return null; Stack<ListNode> stack =new Stack<ListNode>(); ListNode temp=head; while(temp!=null){ stack.push(temp); temp=temp.ne…

Java [Leetcode 206]Reverse Linked List

题目描述: Reverse a singly linked list. 解题思路: 使用递归或者迭代的方法. 代码如下: 方法一:递归 /** * Definition for singly-linked list. * public class ListNode { * int val; * ListNode next; * ListNode(int x) { val = x; } * } */ public class Solution { public ListNode reverseLi…