Burst Balloons (Medium) 这题没有做出来. 自己的思路停留在暴力的解法, 时间复杂度很高: 初始化maxCount = 0. 对于当前长度为k的数组nums, 从0到k - 1逐个选取第i个气球扎破 计算扎破气球得到的金币数, count = nums[i - 1] * nums[i] * nums[i + 1]. 从nums中删掉nums[i]. 查询m[nums]是否存在, 不存在则递归调用maxCoins(nums)并插入m[nums]. count += m[num…

Burst Balloons Given n balloons, indexed from 0 to n-1. Each balloon is painted with a number on it represented by array nums. You are asked to burst all the balloons. If the you burst balloon i you will get nums[left] * nums[i] * nums[right] coins.…

lc 312 Burst Balloons 312 Burst Balloons Given n balloons, indexed from 0 to n-1. Each balloon is painted with a number on it represented by array nums. You are asked to burst all the balloons. If the you burst balloon i you will get nums[left] * num…

参考:LeetCode 312. Burst Balloons(戳气球) java代码如下 class Solution { //参考:https://blog.csdn.net/jmspan/article/details/51208865 public int maxCoins(int[] nums) { int[] balls = new int[nums.length+2]; balls[0] = 1; balls[balls.length - 1] = 1; int[][] coins…

870. Advantage Shuffle 思路:A数组的最大值大于B的最大值,就拿这个A跟B比较:如果不大于,就拿最小值跟B比较 A可以改变顺序,但B的顺序不能改变,只能通过容器来获得由大到小的顺序,并且必须存储相应的index,因为最终需要将选择的A的数值存入与这个B相对应的index下 class Solution { public: vector<int> advantageCount(vector<int>& A, vector<int>&…

[LeetCode]452. Minimum Number of Arrows to Burst Balloons 解题报告(Python) 标签(空格分隔): LeetCode 题目地址:https://leetcode.com/problems/minimum-number-of-arrows-to-burst-balloons/description/ 题目描述: There are a number of spherical balloons spread in two-dimensio…

Given n balloons, indexed from 0 to n-1. Each balloon is painted with a number on it represented by array nums. You are asked to burst all the balloons. If the you burst balloon i you will get nums[left] * nums[i] * nums[right] coins. Here left and r…

原题链接在这里:https://leetcode.com/problems/burst-balloons/ 题目: Given n balloons, indexed from 0 to n-1. Each balloon is painted with a number on it represented by array nums. You are asked to burst all the balloons. If the you burst balloon i you will get…

Given n balloons, indexed from 0 to n-1. Each balloon is painted with a number on it represented by array nums. You are asked to burst all the balloons. If the you burst balloon i you will getnums[left] * nums[i] * nums[right] coins. Here left and ri…

题目: Given n balloons, indexed from 0 to n-1. Each balloon is painted with a number on it represented by array nums. You are asked to burst all the balloons. If the you burst balloon i you will get nums[left] * nums[i] * nums[right] coins. Here left a…