思路:高精度乘法就可以了. 有两个错误以前没在意,1.成员属性定义时候不能进行初始化, vector<); 这样隐性调用了函数进行初始化的形式特别要注意,也是错误的: 2.容器类只有分配了空间时才能用=赋值,否则要用push_back之类函数插入元素. class Solution { public: void add(vector<int>& res, vector<int>& ans, int shift) { ; int i; ;j < shift…

# -*- coding: utf8 -*-'''__author__ = 'dabay.wang@gmail.com' 43: Multiply Stringshttps://leetcode.com/problems/multiply-strings/ Given two numbers represented as strings, return multiplication of the numbers as a string.Note: The numbers can be arbit…

这些题目是高精度加法和高精度乘法相关的,复习了一下就做了,没想到难住自己的是C++里面string的用法. 原题地址: 415 Add Strings:https://leetcode.com/problems/add-strings/description/ 67 Add Binary: https://leetcode.com/problems/add-binary/description/ 43 Multiply Strings:https://leetcode.com/problems/…

转载:43. Multiply Strings 题目描述 就是两个数相乘,输出结果,只不过数字很大很大,都是用 String 存储的.也就是传说中的大数相乘. 解法一 我们就模仿我们在纸上做乘法的过程写出一个算法. 个位乘个位,得出一个数,然后个位乘十位,全部乘完以后,就再用十位乘以各个位.然后百位乘以各个位,最后将每次得出的数相加.十位的结果要补 1 个 0 ,百位的结果要补两个 0 .相加的话我们可以直接用之前的大数相加.直接看代码吧. public String multiply(Stri…

Multiply Strings Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative. 将乘积逐位逆序存放在int数组result中. 记num1当前为第i位,num2当前为第j位,则乘积存放在result[(n1-1-i)+(n2-1-j…

Given two non-negative integers num1 and num2represented as strings, return the product of num1 and num2, also represented as a string. Example 1: Input: num1 = "2", num2 = "3" Output: "6" Example 2: Input: num1 = "123&q…

一天一道LeetCode系列 (一)题目 Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative. Converting the input string to integer is NOT allowed. You should NOT us…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 日期 题目地址:https://leetcode.com/problems/multiply-strings/description/ 题目描述 Given two non-negative integers num1 and num2 represented as strings, return the product of num1 and nu…

题目: Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative. 思路比较简单,不多说啦 几个需要注意的点: 1. 高位多个为0的,需要进行判断 2. 如果乘数为0的话,可以直接跳过,能节省不少时间 3. string 的两个使用 1) 创建有…

题目描述: Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative. 解题思路: 设置数组记录单个位置相乘的结果,最后负责相加进位. 代码如下: public class Solution { public String multiply(St…