Given an Iterator class interface with methods: next() and hasNext(), design and implement a PeekingIterator that support the peek() operation -- it essentially peek() at the element that will be returned by the next call to next(). Here is an exampl…

原题链接在这里:https://leetcode.com/problems/peeking-iterator/ 题目: Given an Iterator class interface with methods: next() and hasNext(), design and implement a PeekingIterator that support the peek() operation -- it essentially peek() at the element that wi…

Description: Given an Iterator class interface with methods: next() and hasNext(), design and implement a PeekingIterator that support the peek() operation -- it essentially peek() at the element that will be returned by the next call to next(). Here…

Given an Iterator class interface with methods: next() and hasNext(), design and implement a PeekingIterator that support the peek() operation -- it essentially peek() at the element that will be returned by the next call to next(). Here is an exampl…

Given an Iterator class interface with methods: next() and hasNext(), design and implement a PeekingIterator that support the peek() operation -- it essentially peek() at the element that will be returned by the next call to next(). Here is an exampl…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 题目地址:https://leetcode.com/problems/peeking-iterator/description/ 题目描述: Given an Iterator class interface with methods: next() and hasNext(), design and implement a PeekingIterator that support t…

题目: Given an Iterator class interface with methods: next() and hasNext(), design and implement a PeekingIterator that support the peek() operation -- it essentially peek() at the element that will be returned by the next call to next(). Here is an ex…

题目 Given an Iterator class interface with methods: next() and hasNext(), design and implement a PeekingIterator that support the peek() operation – it essentially peek() at the element that will be returned by the next call to next(). Here is an exam…

Given two 1d vectors, implement an iterator to return their elements alternately. For example, given two 1d vectors: v1 = [1, 2] v2 = [3, 4, 5, 6] By calling next repeatedly until hasNext returns false, the order of elements returned by next should b…

原题链接在这里:https://leetcode.com/problems/zigzag-iterator/ 题目: Given two 1d vectors, implement an iterator to return their elements alternately. For example, given two 1d vectors: v1 = [1, 2] v2 = [3, 4, 5, 6] By calling next repeatedly until hasNext ret…

题目: Given an Iterator class interface with methods: next() and hasNext(), design and implement a PeekingIterator that support the peek() operation -- it essentially peek() at the element that will be returned by the next call to next(). Here is an ex…

Given an Iterator class interface with methods: next() and hasNext(), design and implement a PeekingIterator that support the peek() operation -- it essentially peek() at the element that will be returned by the next call to next(). Example: Assume t…

Given an Iterator class interface with methods: next() and hasNext(), design and implement a PeekingIterator that support the peek()operation -- it essentially peek() at the element that will be returned by the next call to next(). Here is an example…

Question Given an Iterator class interface with methods: next() and hasNext(), design and implement a PeekingIterator that support the peek() operation -- it essentially peek() at the element that will be returned by the next call to next(). Here is…

终于将LeetCode的免费题刷完了,真是漫长的第一遍啊,估计很多题都忘的差不多了,这次开个题目汇总贴,并附上每道题目的解题连接,方便之后查阅吧~ 477 Total Hamming Distance 44.10% Meidum 475 Heaters  30.20% Easy 474 Ones and Zeroes  34.90% Meidum 473 Matchsticks to Square  31.80% Medium 472 Concatenated Words 29.20% Hard…

Implement an iterator to flatten a 2d vector. For example,Given 2d vector = [ [1,2], [3], [4,5,6] ] By calling next repeatedly until hasNext returns false, the order of elements returned by next should be: [1,2,3,4,5,6]. Hint: How many variables do y…

刷题备忘录,for bug-free leetcode 396. Rotate Function 题意: Given an array of integers A and let n to be its length. Assume Bk to be an array obtained by rotating the array A k positions clock-wise, we define a "rotation function" F on A as follow: F(k…

请点击页面左上角 -> Fork me on Github 或直接访问本项目Github地址:LeetCode Solution by Swift    说明:题目中含有$符号则为付费题目. 如:[Swift]LeetCode156.二叉树的上下颠倒 $ Binary Tree Upside Down 请下拉滚动条查看最新 Weekly Contest!!! Swift LeetCode 目录 | Catalog 序        号 题名Title 难度     Difficulty  两数之…

刷题备忘录,for bug-free 招行面试题--求无序数组最长连续序列的长度,这里连续指的是值连续--间隔为1,并不是数值的位置连续 问题: 给出一个未排序的整数数组,找出最长的连续元素序列的长度. 如: 给出[100, 4, 200, 1, 3, 2], 最长的连续元素序列是[1, 2, 3, 4].返回它的长度:4. 你的算法必须有O(n)的时间复杂度 . 解法: 初始思路 要找连续的元素,第一反应一般是先把数组排序.但悲剧的是题目中明确要求了O(n)的时间复杂度,要做一次排序,是不能达…

突然很想刷刷题,LeetCode是一个不错的选择,忽略了输入输出,更好的突出了算法,省去了不少时间. dalao们发现了任何错误,或是代码无法通过,或是有更好的解法,或是有任何疑问和建议的话,可以在对应的随笔下面评论区留言,我会及时处理,在此谢过了. 过程或许会很漫长,也很痛苦,慢慢来吧. 编号 题名 过题率 难度 1 Two Sum 0.376 Easy 2 Add Two Numbers 0.285 Medium 3 Longest Substring Without Repeating C…

LeetCode算法题目解答汇总 本文转自<四火的唠叨> 只要不是特别忙或者特别不方便,最近一直保持着每天做几道算法题的规律,到后来随着难度的增加,每天做的题目越来越少.我的初衷就是练习,因为一方面我本身算法基础并不好,再一方面是因为工作以后传统意义上所谓算法的东西接触还是太少.为了题目查找方便起见,我把之前几篇陆陆续续贴出来的我对LeetCode上面算法题的解答汇总在下面,CTRL+F就可以比较方便地找到.由于LeetCode上的题在不断更新,因此我也会不定期地更新.下面表格里面的Accep…

All LeetCode Questions List(Part of Answers, still updating) 题目汇总及部分答案(持续更新中) Leetcode problems classified by company 题目按公司分类(Last updated: October 2, 2017) .   Top Interview Questions # Title Difficulty Acceptance 1 Two Sum Medium 17.70% 2 Add Two N…

All LeetCode Questions List 题目汇总 Sorted by frequency of problems that appear in real interviews. Last updated: October 2, 2017Google (214)534 Design TinyURL388 Longest Absolute File Path683 K Empty Slots340 Longest Substring with At Most K Distinct C…

源代码地址:https://github.com/hopebo/hopelee 语言:C++ 24.Swap Nodes in Pairs Given a linked list, swap every two adjacent nodes and return its head. For example,Given 1->2->3->4, you should return the list as 2->1->4->3. Your algorithm should u…

终于将LeetCode的免费题刷完了,真是漫长的第一遍啊,估计很多题都忘的差不多了,这次开个题目汇总贴,并附上每道题目的解题连接,方便之后查阅吧~ 如果各位看官们,大神们发现了任何错误,或是代码无法通过OJ,或是有更好的解法,或是有任何疑问,意见和建议的话,请一定要在对应的帖子下面评论区留言告知博主啊(如果不方便注册博客园的话,可以下载下文提到的APP,在Feedback中给博主发邮件交流哈),同时也请大家踊跃地,大量地,盲目地提供各个题目的follow up一起讨论哈,多谢多谢,祝大家刷得愉快…

链接:https://leetcode.com/tag/design/ [146]LRU Cache [155]Min Stack [170]Two Sum III - Data structure design (2018年12月6日,周四) Design and implement a TwoSum class. It should support the following operations: add and find. add - Add the number to an inter…

LinkedIn(39) 1 Two Sum 23.0% Easy 21 Merge Two Sorted Lists 35.4% Easy 23 Merge k Sorted Lists 23.3% Hard 33 Search in Rotated Sorted Array 30.2% Hard 34 Search for a Range 29.1% Medium 46 Permutations 35.7% Medium 47 Permutations II 28.0% Medium 50…

Flatten 2D Vector 要点: 这题是2d的iterator,一般对于1d的情况,hasNext()是不需要做移动的.而2d不同,core iterator是j向的,而i向要在hasNext()中移动以保证call next()的时候j是available的. hasNext()如何移动?首先的思路是not j.hasNext()是触发i移动的条件,同时j本身也可能是None(比如Null 2d list).简单的说就是不算移动i直到j没超界,如果i都超界了,那么return Fal…

Zigzag Iterator 要点: 实际不是zigzag而是纵向访问 这题可以扩展到k个list,也可以扩展到只给iterator而不给list.结构上没什么区别,iterator的hasNext和计数殊途同归. 一种方法利用queue,进queue的顺序就是下一个要访问的元素index和v,实际就是level order traversal 另一种是用一个list存每个v的当前位置(or iterator).然后track count:当前列访问完了(即list访问一遍),reset co…

［抄题］: 设计实现一个带有下列属性的二叉查找树的迭代器: 元素按照递增的顺序被访问(比如中序遍历) next()和hasNext()的询问操作要求均摊时间复杂度是O(1) 对于下列二叉查找树,使用迭代器进行中序遍历的结果为 [1, 6, 10, 11, 12] 10 / \ 1 11 \ \ 6 12 ［思维问题］: ［一句话思路］: 有next就全部进入stack并设末尾为空,同时有没有和stack的结果相反. 弹出一个点的同时,next要设置成cur.right,重新入栈.因为next需要…