A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list.   struct RandomListNode { int label; RandomListNode *next, *random; RandomListNode(int…

133. Clone Graph Clone an undirected graph. Each node in the graph contains a label and a list of its neighbors. OJ's undirected graph serialization: Nodes are labeled uniquely. We use # as a separator for each node, and , as a separator for node lab…

A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. 解题思路: 我们在Java for LeetCode 133 Clone Graph题中做过图的复制,本题和图的复制十分类似,JAVA实现如下: public Random…

A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. Example 1: Input: {"$id":"1","next":{"$id":"2&…

A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. 这道题的难点在于如何处理随机指针,由于每一个节点都有一个随机指针,这个指针可以为空,也可以指向链表的任意一个节点,如果在生成一个新节点给其随机指针赋值时,都去遍历原链表的话…

A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. 和第133题差不多,都是图的复制,区别在于这道题的label有可能是相同的,所以导致了map的key有可能相同,所以需要处理. 两种方法差不多.第二种更简洁. 1.在复制n…

A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. /** * Definition for singly-linked list with a random pointer. * struct RandomListNode…

题目: A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. 提示: 此题有两种方法,一种是按照原链表next的顺序依次创建节点,并处理好新链表的next指针,同时把原节点与新节点的对应关系保存到一个hash_map中,然后第…

A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. Approach #1: Java. /** * Definition for singly-linked list with a random pointer. * cl…

给出一个链表,每个节点包含一个额外增加的随机指针,该指针可以指向链表中的任何节点或空节点.返回一个深拷贝的链表. 详见:https://leetcode.com/problems/copy-list-with-random-pointer/description/ Java实现: /** * Definition for singly-linked list with a random pointer. * class RandomListNode { * int label; * Random…

python代码如下: # Definition for singly-linked list with a random pointer. # class RandomListNode(object): # def __init__(self, x): # self.label = x # self.next = None # self.random = None class Solution(object): def copyRandomList(self, head): ""&q…

作者: 负雪明烛 id: fuxuemingzhu 个人公众号:负雪明烛 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 日期 题目地址:https://leetcode-cn.com/problems/copy-list-with-random-pointer/ 题目描述 给你一个长度为 n 的链表,每个节点包含一个额外增加的随机指针 random ,该指针可以指向链表中的任何节点或空节点. 构造这个链表的 深拷贝. 深拷贝应该正好由 n 个 全…

原题地址 非常巧妙的方法,不需要用map,只需要O(1)的额外存储空间,分为3步: 1. 先复制链表,但是这个复制比较特殊,每个新复制的节点添加在原节点的后面,相当于"加塞"2. 根据原节点的 ramdon 指针构造新节点的 random 指针3. 恢复原链表结构,同时得到新复制链表 时间复杂度:O(n) 注意random有可能是NULL 代码: RandomListNode *copyRandomList(RandomListNode *head) { RandomListNode…

public RandomListNode copyRandomList(RandomListNode head) { /* 深复制,就是不能只是复制原链表变量,而是做一个和原来链表一模一样的新链表, 每一个节点都是新建的,而不是指向就节点 这个题的难点在于:随机节点. 随机节点有可能指向后边还没有建立的节点,这就没法指. 方法一:一一对应地记录每个新旧节点的映射关系,在常规节点建立后,就去查哈希表,找到对应 新节点的旧节点的random,就是新节点的random */ if (head==nu…

题目: A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. 题解: 如果要copy一个带有random pointer的list,主要的问题就是有可能这个random指向的位置还没有被copy到,所以解决方法都是多次扫描li…

类同:剑指 Offer 题目汇总索引第26题 Copy List with Random Pointer A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. 说明:分三步, 1. 每个节点复制其本身并链接在后面. 2, 复制…

Copy List with Random Pointer A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. 题目意思: 深拷贝一个给定的带random指针的链表,这个random指针可能会指向其他任意一个节点或者是为nu…

LintCode - Copy List with Random Pointer LintCode - Copy List with Random Pointer Web Link Description Code - C Tips Web Link http://www.lintcode.com/en/problem/copy-list-with-random-pointer/ Description A linked list is given such that each node con…

Copy List with Random Pointer 题解 原创文章,拒绝转载 题目来源:https://leetcode.com/problems/copy-list-with-random-pointer/description/ Description A linked list is given such that each node contains an additional random pointer which could point to any node in the…

/** * Definition for singly-linked list with a random pointer. * struct RandomListNode { * int label; * RandomListNode *next, *random; * RandomListNode(int x) : label(x), next(NULL), random(NULL) {} * }; */ class Solution {//为了可以高速定位某个节点,採用确定性映射的方式,将…

给定一个链表,每个节点包含一个额外增加的随机指针,该指针可以指向链表中的任何节点或空节点. 要求返回这个链表的深拷贝. A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. 示例: 输入: {"$id":"…

题目 A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. 分析 实现一个链表的深拷贝,返回拷贝后的新链表. 若是普通链表,逐个拷贝原始链表节点并连接即可,只需O(n)的时间复杂度:但是此题特殊的是,每个节点都有一个rando…

A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. 这道链表的深度拷贝题的难点就在于如何处理随机指针的问题,由于每一个节点都有一个随机指针,这个指针可以为空,也可以指向链表的任意一个节点,如果我们在每生成一个新节点给其随机指…

问题: A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list.   结点的定义如下: /** * Definition for singly-linked list with a random pointer. * class…

A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. Solution: Uses map to recorde node mapping between old linked list and new linked list…

A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. 分析: 这题的关键其实是如何copy random pointer,找到一个random pointer指向的node, time complexity is O(n).…

Total Accepted: 53943 Total Submissions: 209664 Difficulty: Hard A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list.  (M) Clone Graph   o(…

A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. 给定一个链表,每个节点包含一个额外增加的随机指针,该指针可以指向链表中的任何节点或空节点. 要求返回这个链表的深度拷贝. 1ms /** * Definition for…

问题: A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. 结点的定义如下: /** * Definition for singly-linked list with a random pointer. * class Ra…

A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. 分析: 我们知道如果是简单的copy List 的话,那么我们只需要从头到尾遍历下来,new出对应个数的Node,并把它们的连接关系设置好就可以了,但是这道题目中每个节点N…