problem 922. Sort Array By Parity II solution1: class Solution { public: vector<int> sortArrayByParityII(vector<int>& A) { int n = A.size(); , j=; i<n, j<n; ) { ==) i += ; ==) j += ; if(j<n) swap(A[i], A[j]); } return A; } }; 参考 1…

Given an array of integers nums, half of the integers in nums are odd, and the other half are even. Sort the array so that whenever nums[i] is odd, i is odd, and whenever nums[i] is even, i is even.  Return any answer array that satisfies this condit…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 使用奇偶数组 排序 奇偶数位置变量 日期 题目地址: https://leetcode.com/problems/sort-array-by-parity-ii 题目描述 Given an array A of non-negative integers, half of the integers in A are odd, and half of…

题目如下: 解题思路:非常简单的题目,引入两个变量oddInx = 1和evenInx = 0,和与A等长的结果数组res.然后遍历A,如果A[i]为偶数,则令res[evenInx] = A[i],evenInx += 2:否则令res[oddInx] = A[i],evenInx += 2. 代码如下: class Solution(object): def sortArrayByParityII(self, A): """ :type A: List[int] :rty…

problem 905. Sort Array By Parity solution1: class Solution { public: vector<int> sortArrayByParity(vector<int>& A) { vector<int> even, odd; for(auto a:A) { ==) even.push_back(a); else odd.push_back(a); } even.insert(even.end(), odd.…

package y2019.Algorithm.array; /** * @ProjectName: cutter-point * @Package: y2019.Algorithm.array * @ClassName: SortArrayByParityII * @Author: xiaof * @Description: 922. Sort Array By Parity II * Given an array A of non-negative integers, half of the…

922. Sort Array By Parity II 题目描述 Given an array A of non-negative integers, half of the integers in A are odd, and half of the integers are even. Sort the array so that whenever A[i] is odd, i is odd; and whenever A[i] is even, i is even. You may re…

题目如下: 解题思路:本题和[leetcode]75. Sort Colors类似,但是没有要求在输入数组本身修改,所以难度降低了.引入一个新的数组,然后遍历输入数组,如果数组元素是是偶数,插入到新数组头部,否则追加到尾部. 代码如下: class Solution(object): def sortArrayByParity(self, A): """ :type A: List[int] :rtype: List[int] """ res =…

Given an array A of non-negative integers, half of the integers in A are odd, and half of the integers are even. Sort the array so that whenever A[i] is odd, i is odd; and whenever A[i] is even, i is even. You may return any answer array that satisfi…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述: 题目大意 解题方法 自定义sorted函数的cmp 日期 题目地址:https://leetcode.com/problems/sort-array-by-parity/description/ 题目描述: Given an array A of non-negative integers, return an array consisting of all the…

题目要求 Given an array A of non-negative integers, half of the integers in A are odd, and half of the integers are even. Sort the array so that whenever A[i] is odd, i is odd; and whenever A[i] is even, i is even. You may return any answer array that sa…

https://leetcode.com/problems/sort-array-by-parity-ii/ Given an array A of non-negative integers, half of the integers in A are odd, and half of the integers are even. Sort the array so that whenever A[i] is odd, i is odd; and whenever A[i]is even, i…

Question 992. Sort Array By Parity II Solution 题目大意:给一个int数组,一半是奇数一半是偶数,分别对偶数数和奇数数排序并要求这个数本身是偶数要放在偶数位上 思路:把奇数数和偶数数筛选出来后对其分别排序,再按奇偶索引放到原数组上 Java实现: public int[] sortArrayByParityII(int[] A) { List<Integer> oddList = new ArrayList<>(); List<I…

Given an array A of non-negative integers, half of the integers in A are odd, and half of the integers are even. Sort the array so that whenever A[i] is odd, i is odd; and whenever A[i] is even, i is even. You may return any answer array that satisfi…

这是悦乐书的第354次更新,第379篇原创 01 看题和准备 今天介绍的是LeetCode算法题中Easy级别的第216题(顺位题号是922).给定非负整数的数组A,A中的一半整数是奇数,而剩下的一半是偶数. 对数组进行排序,以便每当A[i]为奇数时,i就是奇数; A[i]是偶数,i就是偶数. 你可以返回满足此条件的任何答案数组.例如: 输入:[4,2,5,7] 产出:[4,5,2,7] 说明:[4,7,2,5],[2,5,4,7],[2,7,4,5]也将被接受. 注意: 2 <= A.leng…

problem 896. Monotonic Array solution1: class Solution { public: bool isMonotonic(vector<int>& A) { int inc = true, dec = true; ; i<A.size(); ++i) { inc &= (A[i]>=A[i-]); dec &= (A[i]<=A[i-]); } return inc || dec; } }; solution2…

problem 665. Non-decreasing Array 题意:是否能够将数组转换为非减数组. solution: 难点在于理解如何对需要修改的元素进行赋值: class Solution { public: bool checkPossibility(vector<int>& nums) { , n = nums.size(); ; i<n; i++) { ]) { ) return false; || nums[i-] <= nums[i]) nums[i-]…

Given an array A of non-negative integers, half of the integers in A are odd, and half of the integers are even. Sort the array so that whenever A[i] is odd, i is odd; and whenever A[i] is even, i is even. You may return any answer array that satisfi…

""" Given an array A of non-negative integers, half of the integers in A are odd, and half of the integers are even. Sort the array so that whenever A[i] is odd, i is odd; and whenever A[i] is even, i is even. You may return any answer arra…

给定一个非负整数数组 A, A 中一半整数是奇数,一半整数是偶数. 对数组进行排序,以便当 A[i] 为奇数时,i 也是奇数:当 A[i] 为偶数时, i 也是偶数. 你可以返回任何满足上述条件的数组作为答案. 示例: 输入:[4,2,5,7] 输出:[4,5,2,7] 解释:[4,7,2,5],[2,5,4,7],[2,7,4,5] 也会被接受. 提示: 2 <= A.length <= 20000 A.length % 2 == 0 0 <= A[i] <= 1000 clas…

package y2019.Algorithm.array; /** * @ProjectName: cutter-point * @Package: y2019.Algorithm.array * @ClassName: SortArrayByParity * @Author: xiaof * @Description: 905. Sort Array By Parity * Given an array A of non-negative integers, return an array…

链接:https://leetcode.com/tag/sort/ [56]Merge Intervals (2019年1月26日,谷歌tag复习) 合并区间 Input: [[1,3],[2,6],[8,10],[15,18]] Output: [[1,6],[8,10],[15,18]] Explanation: Since intervals [1,3] and [2,6] overlaps, merge them into [1,6]. 题解:先按照interval的begin从小到大s…

905. Sort Array By Parity Given an array A of non-negative integers, return an array consisting of all the even elements of A, followed by all the odd elements of A. You may return any answer array that satisfies this condition. Example 1: Input: [3,…

[02][].slice和Array.prototype.slice 01,Array是一个构造函数.浏览器内置的特殊对象.   02,Array没有slice方法. 03,Array.prototype原型上有方法slice() 我们可以用Array.prototype.slice或者Array的实例[].slice都行,但不能Array.slice     04, Array.prototype.slice.call(arguments) 可以将类数组对象转成数组. 如: var a={le…

[LeetCode]659. Split Array into Consecutive Subsequences 解题报告(Python) 标签(空格分隔): LeetCode 作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 题目地址:https://leetcode.com/problems/split-array-into-consecutive-subsequences/description/ 题目描述: You are g…

Question 905. Sort Array By Parity Solution 题目大意:数组排序,偶数放前,奇数在后,偶数的数之间不用管顺序,奇数的数之间也不用管顺序 思路:建两个list,一个放偶数,一个放奇数,最后将两个list合并,转化为数组返回 Java实现: public int[] sortArrayByParity(int[] A) { List<Integer> evenList = new ArrayList<>(); List<Integer&g…

[BZOJ2589][SPOJ10707]Count on a tree II 题面 bzoj 题解 这题如果不强制在线就是一个很\(sb\)的莫队了,但是它强制在线啊\(qaq\) 所以我们就用到了另一个东西:树分块 具体是怎么分块的呢:根据深度,从最深的叶子节点往上分,同一子树内的节点在一个块 比如说上面那张图, 有\(7\)个点,那么我们每隔\(2\)的深度就分一块 但是我们又要保证同一子树内的在一块,且要从最深的叶子节点一直往下 所以最后分块的结果:\((1,2)(7,6,3)(4,5)…

[LGR-054]洛谷10月月赛II luogu 成功咕掉Codeforces Round #517的后果就是,我\(\mbox{T4}\)依旧没有写出来.\(\mbox{GG}\) . 浏览器 \(\mbox{popcount}\)为\(0\)的乘上\(\mbox{popcount}\)为\(1\)的就是答案. 因为两个数异或以后二进制位\(1\)的个数的奇偶性不会变. 至于计算\(\mbox{popcount}\),预处理到根号,\(O(1)\)计算即可. #include<cstdio>…

title: [概率论]3-6:条件分布(Conditional Distributions Part II) categories: Mathematic Probability keywords: Multiplication Rule for Distributions 乘法法则 Bayes' Theorem 贝叶斯理论 Law of Total Probability for Random Variables 随机变量的全概率公式 toc: true date: 2018-03-12 0…

[LeetCode]95. Unique Binary Search Trees II 解题报告(Python) 标签(空格分隔): LeetCode 作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.me/ 题目地址:https://leetcode.com/problems/unique-binary-search-trees-ii/description/ 题目描述: Given an integer n, generate all s…