题目链接:http://codeforces.com/contest/734/problem/E E. Anton and Tree time limit per test 3 seconds memory limit per test 256 megabytes input standard input output standard output Anton is growing a tree in his garden. In case you forgot, the tree is a…
E. Anton and Tree time limit per test: 3 seconds memory limit per test :256 megabytes input:standard input output: standard output Anton is growing a tree in his garden. In case you forgot, the tree is a connected acyclic undirected graph. There are …
E. Anton and Tree 题目连接: http://codeforces.com/contest/734/problem/E Description Anton is growing a tree in his garden. In case you forgot, the tree is a connected acyclic undirected graph. There are n vertices in the tree, each of them is painted bla…
E. Anton and Tree time limit per test 3 seconds memory limit per test 256 megabytes input standard input output standard output Anton is growing a tree in his garden. In case you forgot, the tree is a connected acyclic undirected graph. There are n v…
Anton and Tree 题目链接:http://codeforces.com/contest/734/problem/E DFS/BFS 每一次操作都可以使连通的结点变色,所以可以将连通的点缩成一个点(由于Python的栈空间过小,这个操作只能用bfs:其他语言如c++可以直接dfs). 由于缩点后的树的结点是黑白相间的,将整棵树变成相同颜色的最小操作数为:在树的中点不断操作将整棵树变成相同颜色所需要的操作数,也就是整棵树的最大半径. 求树的最大半径可以用一次dfs求得: def getA…
题目链接: Anton and Tree 题意:给出一棵树由0和1构成,一次操作可以将树上一块相同的数字转换为另一个(0->1 , 1->0),求最少几次操作可以把这棵数转化为只有一个数字的一棵数. 题解:首先一次可以改变一片数字,那么进行缩点后就变成了每次改变一个点.缩完点后这棵数变成了一棵相邻节点不同,0和1相交叉的一棵树.然后一棵树的直径上就是 这种情况,相当于从中间开始操作,总共操作(L+1)/2次.关于其他的分支一定会在直径的改变过程中完成改变. #include<bits/s…
js数组的操作 用 js有非常久了,但都没有深究过js的数组形式.偶尔用用也就是简单的string.split(char).这段时间做的一个项目.用到数组的地方非常多.自以为js高手的自己竟然无从下手,一下狠心,我学.呵呵.学了之后才知道,js数组的功能强大非常.远比VB,C#强多了,大家慢慢看吧 1.数组的创建 var arrayObj = new Array(); //创建一个数组 var arrayObj = new Array([size]); //创建一个数组并指定长度.注意不是上限,…
time limit per test3 seconds memory limit per test256 megabytes inputstandard input outputstandard output Anton is growing a tree in his garden. In case you forgot, the tree is a connected acyclic undirected graph. There are n vertices in the tree, e…
这个题的题意还是很劲的.搞了好久才知道是怎么变得. (假设已经缩好了点,每次边中间颜色不同的,然后和就和他外面的相同,继续再变这个大的,依次类推,最多就是树的直径D/2) (还是英语水平太弱了(吐槽++,数学考得还没英语高,还是找个地方撞死吧2333)) #include<bits/stdc++.h> #define lowbit(x) x&(-x) #define LL long long #define N 200005 #define M 1000005 #define mod…
［抄题］: Given an array where elements are sorted in ascending order, convert it to a height balanced BST. For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the two subtrees of every node never differ by m…
