describe("loadBranch()", function() {     beforeEach(function() {     this.newRows = "<tr data-tt-id='3' data-tt-parent-id='2'><td>N3</td></tr><tr data-tt-id='4' data-tt-parent-id='2'><td>N4</td><…

1. logback-spring.xml 配置 <appender name="STDOUT" class="ch.qos.logback.core.ConsoleAppender"> ... </appender> <appender name="ALL" class="ch.qos.logback.core.rolling.RollingFileAppender"> ... </…

Leetcode之深度优先搜索(DFS)专题-1080. 根到叶路径上的不足节点(Insufficient Nodes in Root to Leaf Paths) 这篇是DFS专题的第一篇,所以我会写下具体的解题步骤和过程,以及我当时的思路,有改进的地方,希望指正,共同进步. 给定一棵二叉树的根 root,请你考虑它所有 从根到叶的路径:从根到任何叶的路径.(所谓一个叶子节点,就是一个没有子节点的节点) 假如通过节点 node 的每种可能的 “根-叶” 路径上值的总和全都小于给定的 limit…

最近在写一个xml序列化及反序列化实现时碰到个问题,大致类似下面的代码: class Program { static void Main1(string[] args) { var test = new Test() { A = "test" }; var ms = new MemoryStream(); using (XmlWriter xmlWriter = XmlWriter.Create(ms, new XmlWriterSettings() { Encoding = Enc…

题目如下: Given the root of a binary tree, consider all root to leaf paths: paths from the root to any leaf.  (A leaf is a node with no children.) A node is insufficient if every such root to leaf path intersecting this node has sum strictly less than li…

http://www.geeksforgeeks.org/connect-nodes-at-same-level-with-o1-extra-space/ recursive: #include <iostream> #include <vector> #include <algorithm> #include <queue> #include <stack> #include <string> #include <fstrea…

去掉BOM头 writer = new XmlTextWriter(stream, new UnicodeEncoding(false,false)); 如果是UTF8 writer = new XmlTextWriter(stream, new UTF8Encoding(false));…

Given a binary tree, return the level order traversal of its nodes' values. (ie, from left to right, level by level). Given binary tree {3,9,20,#,#,15,7}, 3 / \ 9 20 / \ 15 7 return [ [3], [9,20], [15,7] ] For the problem given I decided to use BFS,…

题目来源 https://leetcode.com/problems/binary-tree-level-order-traversal-ii/ Given a binary tree, return the bottom-up level order traversal of its nodes' values. (ie, from left to right, level by level from leaf to root). 题意分析 Input: binary tree Output:…

题目来源 https://leetcode.com/problems/binary-tree-zigzag-level-order-traversal/ Given a binary tree, return the zigzag level order traversal of its nodes' values. (ie, from left to right, then right to left for the next level and alternate between). 题意分…

题目来源 https://leetcode.com/problems/binary-tree-level-order-traversal/ Given a binary tree, return the level order traversal of its nodes' values. (ie, from left to right, level by level). 题意分析 Input: 一个二叉树 Output:一个每层数值组合的list Conditions:层次遍历 题目思路 采用…

题目描述: Binary Tree Zigzag Level Order Traversal AC Rate: 399/1474 My Submissions Given a binary tree, return the zigzag level order traversal of its nodes' values. (ie, from left to right, then right to left for the next level and alternate between).…

题目: Given a binary tree, return the bottom-up level order traversal of its nodes' values. (ie, from left to right, level by level from leaf to root). For example:Given binary tree {3,9,20,#,#,15,7}, 3 / \ 9 20 / \ 15 7 return its bottom-up level orde…

Given a binary tree, return the level order traversal of its nodes' values. (ie, from left to right, level by level). For example:Given binary tree [3,9,20,null,null,15,7], 3 / \ 9 20 / \ 15 7 return its level order traversal as: [ [3], [9,20], [15,7…

Given a binary tree, return the bottom-up level order traversal of its nodes' values. (ie, from left to right, level by level from leaf to root). For example:Given binary tree [3,9,20,null,null,15,7], 3 / \ 9 20 / \ 15 7 return its bottom-up level or…

Given a binary tree rooted at root, the depth of each node is the shortest distance to the root. A node is deepest if it has the largest depth possible among any node in the entire tree. The subtree of a node is that node, plus the set of all descend…

Given a binary tree, return the bottom-up level order traversal of its nodes' values. (ie, from left to right, level by level from leaf to root). For example:Given binary tree [3,9,20,null,null,15,7], 3 / \ 9 20 / \ 15 7 return its bottom-up level or…

原题地址:http://oj.leetcode.com/problems/binary-tree-level-order-traversal-ii/ 题意: Given a binary tree, return the bottom-up level order traversal of its nodes' values. (ie, from left to right, level by level from leaf to root). For example:Given binary…

原题地址:http://oj.leetcode.com/problems/binary-tree-zigzag-level-order-traversal/ 题意: Given a binary tree, return the zigzag level order traversal of its nodes' values. (ie, from left to right, then right to left for the next level and alternate between…

Given a binary tree, return the zigzag level order traversal of its nodes' values. (ie, from left to right, then right to left for the next level and alternate between). For example: Given binary tree {3,9,20,#,#,15,7}, 3 / \ 9 20 / \ 15 7 return its…

http://www.patest.cn/contests/pat-a-practise/1094 A family hierarchy is usually presented by a pedigree tree where all the nodes on the same level belong to the same generation. Your task is to find the generation with the largest population. Input S…

题目 给定一个二叉树,返回其按层次遍历的节点值. (即逐层地,从左到右访问所有节点). 例如: 给定二叉树: [3,9,20,null,null,15,7], 3 / \ 9 20 / \ 15 7 返回其层次遍历结果: [ [3], [9,20], [15,7] ] 考点 思路 代码 newcoder /* struct TreeNode { int val; struct TreeNode *left; struct TreeNode *right; TreeNode(int x) : va…

作者: 负雪明烛 id: fuxuemingzhu 个人博客:http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 方法一:DFS 方法二:迭代 日期 [LeetCode] 题目地址:https://leetcode.com/problems/binary-tree-level-order-traversal-ii/ Total Accepted: 55876 Total Submissions: 177210 Difficulty: Easy 题目描述 Given…

作者: 负雪明烛 id: fuxuemingzhu 个人博客:http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 BFS DFS 日期 题目地址:https://leetcode.com/problems/binary-tree-level-order-traversal/ 题目描述 Given a binary tree, return the level order traversal of its nodes' values. (ie, from left…

1.根节点<configuration>包含的属性 scan: 当此属性设置为true时,配置文件如果发生改变,将会被重新加载,默认值为true. scanPeriod: 设置监测配置文件是否有修改的时间间隔,如果没有给出时间单位,默认单位是毫秒.当scan为true时,此属性生效.默认的时间间隔为1分钟. debug: 当此属性设置为true时,将打印出logback内部日志信息,实时查看logback运行状态.默认值为false. 例如: <configuration scan=&q…

#-*- coding: UTF-8 -*-#广度优先遍历# Definition for a binary tree node.# class TreeNode(object):#     def __init__(self, x):#         self.val = x#         self.left = None#         self.right = Noneclass Solution(object):    tmplist1=[]        def dfsDept…

# Definition for a binary tree node. # class TreeNode(object): # def __init__(self, x): # self.val = x # self.left = None # self.right = None class Solution(object): def levelOrder(self, root): """ :type root: TreeNode :rtype: List[List[int…

Given a Binary Search Tree (BST) with the root node root, return the minimum difference between the values of any two different nodes in the tree. Example : Input: root = [4,2,6,1,3,null,null] Output: 1 Explanation: Note that root is a TreeNode objec…

因公司ELK监控分析日志的需要,需要区分进程运行状态日志以及错误日志,以便能够根据日志级别(level)进行不同策略的预警,而现有的Nlog.Log4Net都没有Process这样的level,故针对这两个日志框架做了一些扩展,实现了自定义PROCESS LEVEL,因代码不多,故直接贴代码,有疑问的或好的建议可以下方评论留言交流,谢谢! NlogExtend.cs:(Nlog的扩展)文件代码内容如下: public static class NlogExtend { public static…

Log4net按照不同级别写入多个日志文件 2012-02-08 15:06 by Fred-Xu, ... 阅读, ... 评论, 收藏, 编辑 在一个Web应用项目中,我使用了Fluent NHibernate作为数据访问组件,Log4net来做日志记录.实际编码中,主要使用了INFO和ERROR这两个等级来记录日志,如果按照以下Log4net配置: <root> <level value="ALL"/> <appender-ref ref="…