Girls and Boys Time Limit: 5000ms Memory Limit: 10000KB This problem will be judged on PKU. Original ID: 146664-bit integer IO format: %lld      Java class name: Main     In the second year of the university somebody started a study on the romantic r…

Girls and Boys Time Limit: 1 Sec  Memory Limit: 256 MB 题目连接 http://poj.org/problem?id=1466 Description In the second year of the university somebody started a study on the romantic relations between the students. The relation "romantically involved&q…

Girls and Boys Time Limit: 20000/10000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 5565    Accepted Submission(s): 2481 Problem Descriptionthe second year of the university somebody started a study on the romanti…

Girls and Boys Time Limit: 20000/10000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 7577    Accepted Submission(s): 3472 Problem Description the second year of the university somebody started a study on the romant…

                                                            Girls and Boys Time Limit: 5000MS   Memory Limit: 10000K Total Submissions: 12192   Accepted: 5454 Description In the second year of the university somebody started a study on the romantic r…

http://poj.org/problem?id=1466 Girls and Boys Time Limit: 5000MS   Memory Limit: 10000K Total Submissions: 11085   Accepted: 4956 Description In the second year of the university somebody started a study on the romantic relations between the students…

Girls and Boys Time Limit: 20000/10000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 8470    Accepted Submission(s): 3890 Problem Description the second year of the university somebody started a study on the romant…

Girls and Boys Time Limit: 5000ms Memory Limit: 10000KB This problem will be judged on PKU. Original ID: 1466 64-bit integer IO format: %lld      Java class name: Main In the second year of the university somebody started a study on the romantic(浪漫的)…

Girls and Boys Time Limit: 20000/10000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 9245    Accepted Submission(s): 4240 Problem Description the second year of the university somebody started a study on the romant…

称号: Girls and Boys Time Limit: 20000/10000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 189 Accepted Submission(s): 127   Problem Description the second year of the university somebody started a study on the romanti…

Girls and Boys Time Limit: 20000/10000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) [Problem Description] the second year of the university somebody started a study on the romantic relations between the students. The relation “romant…

Girls and Boys Time Limit: 5000MS   Memory Limit: 10000K Total Submissions: 12747   Accepted: 5678 Description In the second year of the university somebody started a study on the romantic relations between the students. The relation "romantically in…

Girls and Boys Time Limit: 1 Sec  Memory Limit: 256 MB 题目连接 http://poj.org/problem?id=1466 Description In the second year of the university somebody started a study on the romantic relations between the students. The relation "romantically involved&q…

Girls and Boys Time Limit: 20000/10000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 6867    Accepted Submission(s): 3083 Problem Description the second year of the university somebody started a study on the romant…

Girls and Boys Time Limit: 20000/10000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 7044    Accepted Submission(s): 3178 Problem Description the second year of the university somebody started a study on the roman…

Girls and Boys Time Limit: 20000/10000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 12246    Accepted Submission(s): 5768 Problem Description the second year of the university somebody started a study on the roma…

Girls and Boys Time Limit: 5000MS   Memory Limit: 10000K Total Submissions: 10912   Accepted: 4887 Description In the second year of the university somebody started a study on the romantic relations between the students. The relation "romantically in…

Girls and BoysTime Limit: 20000/10000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 13556    Accepted Submission(s): 6385 Problem Descriptionthe second year of the university somebody started a study on the romanti…

Girls and Boys Time Limit: 5000MS   Memory Limit: 10000K Total Submissions: 11097   Accepted: 4960 Description In the second year of the university somebody started a study on the romantic relations between the students. The relation "romantically in…

题目描述: 给出一系列男女配对意愿信息.求一个集合中的最大人数,满足这个集合中两两的人不能配对. /* 二分图的最大独立集 因为没有给出具体的男生和女生,所以可以将数据扩大一倍,即n个男生,n个女生, 根据定理,最大独立集=总数-匹配数(本题应该除以2) */ #include<cstdio> #include<iostream> #include<cstring> #define N 510 using namespace std; int a[N][N],used[…

最大点独立集就是无向图中最多的两两不相邻的点集. 二分图最大点独立集=顶点数-二分图最大边独立集(二分图最大匹配) 这一题男女分别作YX部,如果x和y有浪漫关系则连边,如此构造二分图,答案显然就是最大点独立集.另外要先进行二分图染色,以确定每个id的性别. #include<cstdio> #include<cstring> #include<queue> #include<algorithm> using namespace std; #define IN…

有n个人, 其中有男生和女生,接着有n行,分别给出了每一个人暗恋的对象(不止暗恋一个) 现在要从这n个人中找出一个最大集合,满足这个集合中的任意2个人,都没有暗恋这种关系. 输出集合的元素个数. 刚开始想,把人看成顶点,若有暗恋的关系,就连一条边,构成一个图 独立集的概念:一个图中两两互不相连的顶点集合 所以这道题,就是要求最大独立集 有:最大独立集+最小顶点覆盖=|V|(顶点的总个数) 那就求最小顶点覆盖了 根据题意: 暗恋的对象性别不同,所以a暗恋b,b暗恋c,c暗恋a这种关系不可能存在 也…

题目:http://acm.hdu.edu.cn/showproblem.php?pid=1068 二分图的最大独立集数=节点数(n)— 最大匹配数(m) 另外需要注意的是: 本题求出的最大匹配数是实际的两倍需要m/2 #include<iostream> #include<stdio.h> #include<math.h> #include<string.h> #include<stdlib.h> using namespace std; ;…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1068 有n个同学,格式ni:(m) n1 n2 n3表示同学ni有缘与n1,n2,n3成为情侣,求集合中不存在有缘成为情侣的同学的最大同学数. 独立集(图的顶点集的子集,其中任意两点不相邻) 二分图中 最大独立集 = 顶点个数 - 最大匹配数 因为男女不知道,将一个人拆成两个性别,求最大匹配后,除以2就行了. 这种做法比较难理解. #include <iostream> #include <…

HDU 1068 :题目链接 题意:一些男孩和女孩,给出一些人物关系,然后问能找到最多有多少个人都互不认识. 转换一下:就是大家都不认识的人,即最大独立集合 #include <iostream> #include <cstdio> #include <cstdlib> #include <cstring> #include <algorithm> #include <math.h> #define init(a) memset(a,…

匈牙利算法,最开始暴力解不知道为什么就是wa,后来明白,一定要求最优解.查了一下匈牙利算法相关内容,大致了解. #include <stdio.h> #include <string.h> #define MAXNUM 505 int map[MAXNUM][MAXNUM]; int visit[MAXNUM]; int link[MAXNUM]; int dfs(int x, int n) { int i; ; i<n; ++i) { && map[x][i…

题目地址:http://acm.hdu.edu.cn/showproblem.php?pid=1068 本题求二分图最大独立点集.因为最大独立点集=顶点数-最大匹配数.所以转化为求最大匹配.因为没有给出男女,所以每个人都用了两遍,所以结果应该除以2. #include<cstdio> #include<iostream> #include<string.h> #include<algorithm> #include<math.h> #includ…

Description In the second year of the university somebody started a study on the romantic relations between the students. The relation "romantically involved" is defined between one girl and one boy. For the study reasons it is necessary to find…

求一个集合最多几个人,其之间任意两人没有暧昧关系. 二分图匹配 最大独立集 = 总点数 - 最大匹配数 匈牙利算法 因为每个同学都在二分图的两侧 当 A与B匹配时,B与A也匹配 所以 所求的最大匹配数要除以2 #include <iostream> #include <cstdio> #include <vector> #include <cstring> using namespace std; ; int n,a,m,b; vector<int&g…

题目大意:第一行输入一个整数n,表示有n个节点.在接下来的n行中,每行的输入数据的格式是: 1: (2) 4 6 :表示编号为1的人认识2个人,他们分别是4.6: 求,最多能找到多少个人,他们互不认识 解题思路:二分图的最大独立集. 1)最大独立集 =  节点数 - 最大匹配数/2: 2)令女生数= 男生数 = 总数 3)   1: (2)可以采用scanf("%d: (%d)",&a,&b);来输入 代码如下: /* * 1068_1.cpp * * Created…