IRRIGATION LINES Time Limit: 2000ms, Special Time Limit:5000ms, Memory Limit:65536KB Total submit users: 6, Accepted users: 6 Problem 13449 : No special judgement Problem description A plantation consists of several rectangular fields, and a field is…

Farm Irrigation Time Limit: 2 Seconds      Memory Limit: 65536 KB Benny has a spacious farm land to irrigate. The farm land is a rectangle, and is divided into a lot of samll squares. Water pipes are placed in these squares. Different square has a di…

Farm Irrigation Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 6590    Accepted Submission(s): 2838 Problem Description Benny has a spacious farm land to irrigate. The farm land is a rectangle…

Benny has a spacious farm land to irrigate. The farm land is a rectangle, and is divided into a lot of samll squares. Water pipes are placed in these squares. Different square has a different type of pipe. There are 11 types of pipes, which is marked…

意甲冠军  两个农田管内可直接连接到壳体  他们将能够共享一个水源   有11种农田  管道的位置高于一定  一个农田矩阵  问至少须要多少水源 DFS的连通块问题  两个相邻农田的管道能够直接连接的话他们就属于一个连通块  题目就是求连通块个数 #include<cstdio> #include<cstring> using namespace std; const int N = 55; char mat[N][N]; int type[11][4] = { //相应11种水管…

Farm Irrigation Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 4977    Accepted Submission(s): 2137 Problem Description Benny has a spacious farm land to irrigate. The farm land is a rectangle…

Farm Irrigation Time Limit : 2000/1000ms (Java/Other)   Memory Limit : 65536/32768K (Java/Other) Total Submission(s) : 6   Accepted Submission(s) : 3 Font: Times New Roman | Verdana | Georgia Font Size: ← → Problem Description Benny has a spacious fa…

Farm Irrigation Time Limit : 2000/1000ms (Java/Other)   Memory Limit : 65536/32768K (Java/Other) Total Submission(s) : 46   Accepted Submission(s) : 26 Font: Times New Roman | Verdana | Georgia Font Size: ← → Problem Description Benny has a spacious…

Farm Irrigation Time Limit: 2 Seconds      Memory Limit: 65536 KB Benny has a spacious farm land to irrigate. The farm land is a rectangle, and is divided into a lot of samll squares. Water pipes are placed in these squares. Different square has a di…

Farm Irrigation Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 4491    Accepted Submission(s): 1947 Problem Description Benny has a spacious farm land to irrigate. The farm land is a rectangle…

Farm Irrigation Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 11188    Accepted Submission(s): 4876 Problem Description Benny has a spacious farm land to irrigate. The farm land is a rectangle…

Farm Irrigation Time Limit : 2000/1000ms (Java/Other)   Memory Limit : 65536/32768K (Java/Other) Total Submission(s) : 38   Accepted Submission(s) : 24 Font: Times New Roman | Verdana | Georgia Font Size: ← → Problem Description Benny has a spacious…

题目链接: 啊哈哈,选我选我 思路是:首先依据图像抽象出联通关系.. 首先确定每一种图形的联通关系.用01值表示不连通与不连通... 然后从第1个图形进行dfs搜索.假设碰到两快田地能够联通的话那么标记..注意处理的过程中你的 搜索顺序要和你的每一个图形的连通性的顺序同样. .然后就是最后看上下. 左右是否能匹配.. . 看最后有几个不同的快,这就是答案,感觉跟并查集一样..并查集应该也能够做. . 题目: Farm Irrigation Time Limit: 2000/1000 MS (Ja…

题目网址:http://acm.hdu.edu.cn/showproblem.php?pid=1198 题目: Farm Irrigation Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 10132    Accepted Submission(s): 4464 Problem Description Benny has a spac…

extracting lines bases a list using awk awk 'NR==FNR{a[$1]=$0; next}($1 in a){print a[$1]"\n"$0}' file list 参考 http://521cto.blog.51cto.com/950229/945683…

画直线 题目大意:给定一些点集,要你找两点之间的连线不平行的有多少条 数据量比较少,直接暴力枚举,然后放到set查找即可 #include <iostream> #include <functional> #include <algorithm> #include <set> using namespace std; static struct _p_set { long double x, y; }points[]; set<long double&…

/** * 最多显示 $lineCount 行 * lines * * example: * @include lines; * @include lines(3); */ @mixin lines($lineCount: 2){ display: -webkit-box; -webkit-line-clamp: $lineCount; -webkit-box-orient: vertical; overflow: hidden; text-overflow: ellipsis; }…

After the last war devastated your country, you - as the king of the land of Ardenia - decided it washigh time to improve the defense of your capital city. A part of your fortication is a line of magetowers, starting near the city and continuing to t…

题意: 二维平面,给两条线段,判断形成的直线是否重合,或是相交于一点,或是不相交. 解法: 简单几何. 重合: 叉积为0,且一条线段的一个端点到另一条直线的距离为0 不相交: 不满足重合的情况下叉积为0 相交于一点: 直线相交的模板 代码: #include <iostream> #include <cstdio> #include <cstring> #include <cstdlib> #include <cmath> #include &l…

题意:给两条直线,判断相交,重合或者平行 思路:判断重合可以用叉积,平行用斜率,其他情况即为相交. 求交点: 这里也用到叉积的原理.假设交点为p0(x0,y0).则有: (p1-p0)X(p2-p0)=0 (p3-p0)X(p2-p0)=0 展开后即是 (y1-y2)x0+(x2-x1)y0+x1y2-x2y1=0 (y3-y4)x0+(x4-x3)y0+x3y4-x4y3=0 将x0,y0作为变量求解二元一次方程组. 假设有二元一次方程组 a1x+b1y+c1=0; a2x+b2y+c2=0…

13.1 Write a method to print the last K lines of an input file using C++. 这道题让我们用C++来打印一个输入文本的最后K行,最直接的方法是先读入所有的数据,统计文本的总行数,然后再遍历一遍打印出最后K行.这个方法需要读两遍文件,我们想使用一种更简便的方法,只需要读取一遍文本就可以打印出最后K行,这里我们使用一个循环数组Circular Array,原理是我们维护一个大小为K的字符串数组,当数组存满后,新进来的数据从开头开始…

LINK time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output The teacher gave Anton a large geometry homework, but he didn't do it (as usual) as he participated in a regular round on Codeforces. In…

题目传送门 题意:判断两条直线的位置关系,共线或平行或相交 分析:先判断平行还是共线,最后就是相交.平行用叉积判断向量,共线的话也用叉积判断点,相交求交点 /************************************************ * Author :Running_Time * Created Time :2015/10/24 星期六 09:08:55 * File Name :POJ_1269.cpp *********************************…

http://poj.org/problem?id=1269 我会说这种水题我手推公式+码代码用了1.5h? 还好新的一年里1A了---- #include <cstdio> #include <cstring> #include <cmath> #include <string> #include <iostream> #include <algorithm> #include <queue> #include <…

控制台程序. import javax.swing.JComponent; import java.util.*; import java.awt.*; import java.awt.geom.*; @SuppressWarnings("serial") public class SketcherView extends JComponent implements Observer { public SketcherView(Sketcher theApp) { this.theAp…

题意:给定4个点的坐标,前2个点是一条线,后2个点是另一条线,求这两条线的关系,如果相交,就输出交点. 题解:先判断是否共线,我用的是叉积的性质,用了2遍就可以判断4个点是否共线了,在用斜率判断是否平行,最后就是相交了,求交点就好了. 求交点的过程和高中知识差不多,用y=kx+c来求,只不过要注意斜率不存在的时候特殊处理,还有就是求斜率的时候一定要强制转换,(坑爹的我,调试了一小时才找到这个bug) AC代码: #include <map> #include <set> #incl…

题目链接:http://poj.org/problem?id=1269 题目大意:给出四个点的坐标x1,y1,x2,y2,x3,y3,x4,y4,前两个形成一条直线,后两个坐标形成一条直线.然后问你是否平行,重叠或者相交,如果相交,求出交点坐标. 算法:二维几何直线相交+叉积 解法:先用叉积判断是否相交,如果相交的话,设交点坐标为p0(x0,y0).向量(p0p1)和(p0p2)的叉积为0,有(x1-x0)*(y2-y0)-(y1-y0)*(x2-x0)=0;同理,求出p0和p3p4直线的式子.…

paste - merge lines of files 命令格式: paste [OPTION] ... [FILE] ... 说明: 输出每个文件的对应行组合而成的行,中间用tab分开,如果没有FILE, 读取标准输入 -d , 行拼接时的分隔符,而不用tab -s, 交换拼接的行和列.…

Intersecting Lines Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 8342   Accepted: 3789 Description We all know that a pair of distinct points on a plane defines a line and that a pair of lines on a plane will intersect in one of three…

<!DOCTYPE html> <html lang="en"> <head> <title>three.js canvas - lines - colors</title> <meta charset="utf-8"> <meta name="viewport" content="width=device-width, user-scalable=no, m…