109.Convert sorted list to BST

【109.Convert sorted list to BST】的更多相关文章

109.Convert sorted list to BST

/* * 109.Convert sorted list to BST * 2016.12.24 by Mingyang * 这里的问题是对于一个链表我们是不能常量时间访问它的中间元素的. * 这时候就要利用到树的中序遍历了,按照递归中序遍历的顺序对链表结点一个个进行访问,而我们要构造的二分查找树正是按照链表的顺序来的. * 思路就是先对左子树进行递归 * 然后将当前结点作为根,迭代到下一个链表结点,最后在递归求出右子树即可.整体过程就是一次中序遍历,时间复杂度是O(n),空间复杂度是栈空间O(…

108. Convert Sorted Array to Binary Search Tree 109. Convert Sorted List to Binary Search Tree -- 将有序数组或有序链表转成平衡二叉排序树

108. Convert Sorted Array to Binary Search Tree Given an array where elements are sorted in ascending order, convert it to a height balanced BST. /** * Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left; * TreeNode *ri…

【LeetCode】109. Convert Sorted List to Binary Search Tree 解题报告（Python）

[LeetCode]109. Convert Sorted List to Binary Search Tree 解题报告(Python) 标签(空格分隔): LeetCode 作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.me/ 题目地址:https://leetcode.com/problems/convert-sorted-list-to-binary-search-tree/description/ 题目描述: Given a s…

leetcode 108. Convert Sorted Array to Binary Search Tree 、109. Convert Sorted List to Binary Search Tree

108. Convert Sorted Array to Binary Search Tree 这个题使用二分查找,主要要注意边界条件. 如果left > right,就返回NULL.每次更新的时候是mid-1,mid+1. 自己推一下基本就可以验证了. class Solution { public: TreeNode* sortedArrayToBST(vector<int>& nums) { ,nums.size() - ); } TreeNode* ToBST(vecto…

【一天一道LeetCode】#109. Convert Sorted List to Binary Search Tree

一天一道LeetCode 本系列文章已全部上传至我的github,地址:ZeeCoder's Github 欢迎大家关注我的新浪微博,我的新浪微博欢迎转载,转载请注明出处 (一)题目 Given a singly linked list where elements are sorted in ascending order, convert it to a height balanced BST. (二)解题本题大意:给定一个单向链表,构造出平衡二叉搜索树解题思路:参考[一天一道Leet…

[LeetCode] 109. Convert Sorted List to Binary Search Tree 把有序链表转成二叉搜索树

Given a singly linked list where elements are sorted in ascending order, convert it to a height balanced BST. For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the two subtrees of every node never diffe…

Leetcode#109 Convert Sorted List to Binary Search Tree

原题地址跟Convert Sorted Array to Binary Search Tree(参见这篇文章)类似,只不过用list就不能随机访问了. 代码: TreeNode *buildBST(ListNode *head, int len) { ) return NULL; ListNode *p = head; ; < len) { p = p->next; leftLen++; } TreeNode *node = new TreeNode(p->val); node->…

leetcode 109 Convert Sorted List to Binary Search Tree ----- java

Given a singly linked list where elements are sorted in ascending order, convert it to a height balanced BST. 和上一题类似,把数组换成链表,所以可以两种做法: 1.把链表换成数组,然后用上一题的方法,这样会比较慢. 2.每次找到中间的点,作为节点,然后递归,其实原理还是二分查找. /** * Definition for singly-linked list. * public…

109. Convert Sorted List to Binary Search Tree

Given a singly linked list where elements are sorted in ascending order, convert it to a height balanced BST. ============== 题目:将升序的链表,转化为BST(note:此BST要求是高度平衡,就是树种左右子树高度差不超过1) 思路: def TreeNode* sortedListToBST(ListNode* head){ 按照slow/fast方式找到链表的中间节点m…

LeetCode OJ 109. Convert Sorted List to Binary Search Tree

Given a singly linked list where elements are sorted in ascending order, convert it to a height balanced BST. 涉及到二叉树的问题用递归的方法很容易理解.这个问题要求把一个升序排序的链表转换为一颗height balanced BST.转换的方式就是把链表的中间值作为树的根节点,中间值的左半部分转换为二叉树的左子树,中间值的右半部分转换为二叉树的右子树. 递归解决问题的步骤如下: 1. 如…