Description Andy, 8, has a dream - he wants to produce his very own dictionary. This is not an easy task for him, as the number of words that he knows is, well, not quite enough. Instead of thinking up all the words himself, he has a briliant idea. F…
参考:https://www.cnblogs.com/yjlblog/p/6947747.html https://blog.csdn.net/hnust_taoshiqian/article/details/43448793 https://blog.csdn.net/liuke19950717/article/details/49450817 https://blog.csdn.net/fanyun_01/article/details/66967710 #include <iostream…
这道题主要用到了set容器和stringstream,用起来非常方便,我第一次见识到,觉得十分的炫酷…… 而且,竟然可以将自己写的单词按照字典序排列,真的太酷了. 下面是书上的代码,目前还处于初学状态,所以都是摘抄例题的代码,希望不久之后,我可以用学到的技能自己做出题来. 晚安啦. #include<iostream> #include<string> #include<set> #include<sstream> using namespace std;…
Andy's First Dictionary Description 不提英文了 直接上中文大意吧 XY学长刚刚立下了再不过CET就直播xx的flag,为了不真的开启直播模式,XY学长决定好好学习英语.于是他每天都读一篇只包含生词的英语文章,并以自己高达450的智商在一秒钟之内记忆下来. 现在给你一篇XY学长今天要读的文章,请你写一个程序,输出他都学习到了哪些单词.要求:如果文章中有相同的单词,那么仅仅输出一次:而且如果两个单词只有大小写不同,将他们视为相同的单词. Input 测试数据将输入…
这是悦乐书的第303次更新,第322篇原创 01 看题和准备 今天介绍的是LeetCode算法题中Easy级别的第171题(顺位题号是720).给出表示英语词典的字符串单词数组,找到单词中长度最长的单词,此单词可以通过数组中的其他单词一次次构建一个字符而得来.如果有多个可能的答案,则返回字典顺序最小的最长单词.如果没有答案,则返回空字符串.例如: 输入:words = ["w","wo","wor","worl","…
Andy, 8, has a dream - he wants to produce his very own dictionary. This is not an easy task for him, as the number of words that he knows is, well, not quite enough. Instead of thinking up all the words himself, he has a briliant idea. From his book…
题意:给出一段英文,里面包含一些单词,空格和标点,单词不区分大小写,默认都为小写.按照字典序输出这些单词(这些单词不能有重复,字母全部变成小写) stringstream:包含在头文件#include<sstream>中,能将一个字符串分割,用>>输出某些元素 #include <stdio.h> #include <string.h> #include <iostream> #include <algorithm> #include…
输入一个文本,找出所有不同的单词(连续的字母序列),按字典序从小到大输出.单 词不区分大小写. 样例输入: Adventures in Disneyland Two blondes were going to Disneyland when they came to a fork in the road. The sign read: "Disneyland Left." So they went home. 样例输出(为了节约篇幅只保留前5行): a adventures blond…
#include<bits/stdc++.h>using namespace std;set<string> dict;int main(){ string s, buf; while(cin >> s) { for(int i = 0;i < s.length();i++) { if(isalpha(s[i])) s[i] = tolower(s[i]); else s[i] = ' '; } stringstream ss(s); while(ss >&…
原题链接: https://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&page=show_problem&problem=1756 这道题用STL解答还是比较简单的,下面就给大家分享用 set 和 map 的 AC . 解法一(map): #include <iostream> #include <string> #include <map> using names…