【模拟】【HDU1443】 Joseph】的更多相关文章

Joseph Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 1652    Accepted Submission(s): 1031 Problem Description The Joseph's problem is notoriously known. For those who are not familiar with th…
题目:改进的Joseph环.一圈人报数,报数上限依次为3,7,11,19,循环进行,直到所有人出列完毕. 思路:双向循环链表模拟. 代码: #include <cstdio> #include <cstdlib> #define N 20 typedef struct node { int id; struct node *next; struct node *pre; }Node, *pNode; //双向循环链表的构建 pNode RingConstruct (int n) {…
Joseph Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 2126    Accepted Submission(s): 1291 Problem Description The Joseph's problem is notoriously known. For those who are not familiar with th…
Joseph Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 2453    Accepted Submission(s): 1476 Problem Description The Joseph's problem is notoriously known. For those who are not familiar with the…
Lucky and Good Months by Gregorian Calendar Time Limit: 1000MS Memory Limit: 65536K Description Have you ever wondered why normally an year has 365 days, not 400 days? Why August have 31 days, but February have only 28 days? Why there are 7 days, not…
package Joseph;//约瑟夫环,m个人围成一圈.从第K个人开始报数,报道m数时,那个人出列,以此得到出列序列//例如1,2,3,4.从2开始报数,报到3剔除,顺序为4,3,1,2public class Joseph{ class node//结点类 {private int number;  private node next;  node(int num,node next){   this.number=num;   this.next=next;  } } private n…
Joseph Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 1512    Accepted Submission(s): 948 Problem Description   The Joseph's problem is notoriously known. For those who are not familiar with th…
 Joseph  The Joseph's problem is notoriously known. For those who are not familiar with the original problem: from among n people, numbered 1, 2, ..., n, standing in circle every mth is going to be executed and only the life of the last remaining per…
一:首先科普一下约瑟夫问题的数学方法 (1)  不管是用list实现还是用vector实现都有一个共同点:要模拟整个游戏过程,不仅程序写起来比較烦,并且时间复杂度高达O(nm),当n,m很大(比如上百万,上千万)的时候,差点儿是没有办法在短时间内出结果的.我们注意到原问题不过要求出最后的胜利者的序号,而不是要读者模拟整个过程.因此假设要追求效率,就要打破常规,实施一点数学策略. (2) 为了讨论方便,先把问题略微改变一下,并不影响原意:  问题描写叙述:n个人(编号0~(n-1)),从0開始报数…
约瑟夫环问题: 在一间房间总共有n个人(下标0-n-1),只能有最后一个人活命. 按照如下规则去杀人: 所有人围成一圈 顺时针报数,每次报到q的人将被杀掉 被杀掉的人将从房间内被移走 然后从被杀掉的下一个人重新报数,继续报q,再清除,直到剩余一人 要求模拟这个问题 #include<stdio.h> #include<malloc.h> void Joseph(int count,int doom); void Joseph(int count,int doom){ int ali…