//通过Map 类实现,通过键值对的方式,可以将输入的字符串的每一个字符,作为键,每个字符出现的次数作为值:如下: public class Find { public static void main(String[] args){ String scan=new Scanner(System.in).nextLine();//获取键盘上输入的字符串: Map<Character,Integer> map = new HashMap<Character,Integer>();//…
dic=dict() d={} s=set() s='helloworld' (1)d=dict() for x in s: if x not in d.keys(): d[x]=1 else: d[x]=d[x]+1 print(d) (2)d2=dict() for x in s: d2[x]=d2.get(x,0)+1 print(d2) (3)d3=dict() for x in s: d3[x]=s.count(x) print(d3) 上面一共给出了三种方法,均是以字典的形式输出,但…
1. 统计的对象words.txt,每个单词占一行(从简考虑了~) zjd@ubuntu:~/test$ cat word.txt used this count mysql count this used mysql linux this redis apple android redis apple 2. 统计每个单词的频率 方法1: zjd@ubuntu:~/test$ cat word.txt |awk '{a[$0]++}END{for(i in a) print i"="…
//There is no need to explain the code right? package com.hp.test; import java.util.HashMap; import java.util.List; import java.util.Map; import java.util.Set; public class CharacterCheck { public static void main(String[] args) { String str = "sdfwe…