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Longest Substring Without Repeating Characters - 哈希与双指针

题意很简单,就是寻找一个字符串中连续的最长包含不同字母的子串. 其实用最朴素的方法,从当前字符开始寻找,找到以当前字符开头的最长子串.这个方法猛一看是个n方的算法,但是要注意到由于字符数目的限制,其实这是个O(Cn)的算法,最长也不过是C长度.所以我觉得普通方法应该是能过的. 于是写了一个,字符数目最大也不超过256所以代码如下: class Solution { public: int lengthOfLongestSubstring(string s) { ; ;i<s.length();i…

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题目如下: Given a string, find the length of the longest substring without repeating characters. Example 1: Input: "abcabcbb" Output: 3 Explanation: The answer is "abc", with the length of 3. Example 2: Input: "bbbbb" Output: 1 E…

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Given a string, find the length of the longest substring without repeating characters. For example, the longest substring without repeating letters for "abcabcbb" is "abc", which the length is 3. For "bbbbb" the longest subst…

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题目中文:没有重复字符的最长子串 题目难度:Medium 题目内容: Given a string, find the length of the longest substring without repeating characters. Examples: Given "abcabcbb", the answer is "abc", which the length is 3. Given "bbbbb", the answer is &q…