点击打开题目链接 题目意思就是自己实现一个atoi函数,也就是将字符串转换成int型. 关于INT_MAX和INT_MIN, 只是在<limits.h>文件中定义的宏..分别是int型可以表示的最大值和最小值 还有就是定义大整数常量的时候,会出现这种警告:warning: this decimal constant is unsigned only in ISO C90 c的标准写道: The C90 rule that the default type of a decimal intege…

Implement atoi to convert a string to an integer. Hint: Carefully consider all possible input cases. If you want a challenge, please do not see below and ask yourself what are the possible input cases. Notes: It is intended for this problem to be spe…

#include <iostream> #include <assert.h> using namespace std; int ato(const char *str) { ,e=,s=; ,min=-; ; ]={}; unsigned ; while(*str==' '){ //过滤掉连续空格 str++; } ')){ if(*str=='-'||*str=='+'){ //过滤掉正负号 if(*str=='-') f=-; str++; } ') //过滤掉前面的无用的0…

String to Integer (atoi) Implement atoi to convert a string to an integer. Hint: Carefully consider all possible input cases. If you want a challenge, please do not see below and ask yourself what are the possible input cases. Notes: It is intended f…

8. String to Integer (atoi) Total Accepted: 112863 Total Submissions: 825433 Difficulty: Easy Implement atoi to convert a string to an integer. Hint: Carefully consider all possible input cases. If you want a challenge, please do not see below and as…

String to Integer (atoi) time=272ms   accepted 需考虑各种可能出现的情况 public class Solution { public int atoi(String str) { int length=str.length(); long result=0; int flag=1; Boolean bFlag=false,bSpace=false,bNum=false; if(length<=0) return (int) result; else…

1.  String to Integer (atoi) Implement atoi to convert a string to an integer. Hint: Carefully consider all possible input cases. If you want a challenge, please do not see below and ask yourself what are the possible input cases. Notes: It is inte…

String to Integer (atoi) Implement atoi to convert a string to an integer. [函数说明]atoi() 函数会扫描 str 字符串,跳过前面的空白字符(例如空格,tab缩进等),直到遇上数字或正负符号才开始做转换,而再遇到非数字或字符串结束时('\0')才结束转换,并将结果返回. [返回值]返回转换后的整型数:如果 str 不能转换成 int 或者 str 为空字符串,那么将返回 0.如果超出Integer的范围,将会返回I…

题目String to Integer (atoi)(难度Medium) 大意是找出给定字串开头部分的整型数值,忽略开头的空格,注意符号,对超出Integer的数做取边界值处理. 方案1 class Solution { fun myAtoi(str: String): Int { val maxInt = " val maxIntS = "+2147483647" val minIntS = "-2147483648" val lengthMI = ma…

8. String to Integer (atoi) Total Accepted: 112863 Total Submissions: 825433 Difficulty: Easy Implement atoi to convert a string to an integer. Hint: Carefully consider all possible input cases. If you want a challenge, please do not see below and as…