https://vjudge.net/contest/66989#problem/C You have N integers, A1, A2, ... , AN. You need to deal with two kinds of operations. One type of operation is to add some given number to each number in a given interval. The other is to ask for the sum of…
A Simple Problem With Integers POJ-3468 这题是区间更新的模板题,也只是区间更新和区间查询和的简单使用. 代码中需要注意的点我都已经标注出来了,容易搞混的就是update函数里面还需要计算sum数组.因为这里查询的时候是直接用sum查询结点. //区间更新,区间查询 #include<iostream> #include<cstdio> #include<algorithm> #include<cstring> #inc…
POJ.3468 A Simple Problem with Integers(线段树 区间更新 区间查询) 题意分析 注意一下懒惰标记,数据部分和更新时的数字都要是long long ,别的没什么大坑. 代码总览 #include <cstdio> #include <cstring> #include <algorithm> #define nmax 200000 using namespace std; struct Tree{ int l,r; long lon…
Time Limit: 5000MS Memory Limit: 131072K Total Submissions: 115624 Accepted: 35897 Case Time Limit: 2000MS Description You have N integers, A1, A2, ... , AN. You need to deal with two kinds of operations. One type of operation is to add some give…
题目链接: http://poj.org/problem?id=3468 题意: 输入 n, m表初始有 n 个数, 接下来 m 行输入, Q x y 表示询问区间 [x, y]的和: C x y z 表示区间 [x, y] 内所有数加上 z : 思路: 线段树区间更新&区间求和模板: 代码: #include <iostream> #include <stdio.h> #define ll long long #define lson l, mid, rt <<…
A Simple Problem with Integers Time Limit: 5000MS Memory Limit: 131072K Total Submissions: 92632 Accepted: 28818 Case Time Limit: 2000MS Description You have N integers, A1, A2, ... , AN. You need to deal with two kinds of operations. One type of…
