【Rescue HDU1242 （BFS+优先队列） 标签： 搜索 2016-05-04 22:21 69人阅读 评论(0)】的更多相关文章

Rescue HDU1242 （BFS+优先队列） 标签： 搜索 2016-05-04 22:21 69人阅读 评论(0)

Description Angel was caught by the MOLIGPY! He was put in prison by Moligpy. The prison is described as a N * M (N, M <= 200) matrix. There are WALLs, ROADs, and GUARDs in the prison. Angel's friends want to save Angel. Their task is: approach Angel…

Prime Path 分类： 搜索 POJ 2015-08-09 16:21 4人阅读 评论(0) 收藏

Prime Path Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 14091 Accepted: 7959 Description The ministers of the cabinet were quite upset by the message from the Chief of Security stating that they would all have to change the four-digit r…

Eight(South Central USA 1998)（八数码） 分类： bfs 2015-07-05 22:34 1人阅读 评论(0) 收藏

The 15-puzzle has been around for over 100 years; even if you don't know it by that name, you've seen it. It is constructed with 15 sliding tiles, each with a number from 1 to 15 on it, and all packed into a 4 by 4 frame with one tile missing. Let's…

1.PHP站内搜索 分类： PHP开发实例 2015-07-31 22:48 4人阅读 评论(0) 收藏

PHP站内搜索:多关键字.加亮显示 1.SQL语句中的模糊查找 $sql = "SELECT * FROM `message` WHERE `content`like '%$k[0]%' and `content`like '%$k[0]%'"; 2.多个关键字搜索的原理和技巧 3.替换关键字高亮显示 $r[content] = preg_replace("/($_GET[key])/i", "<font color = red><b&g…

搜索 基础 AC 2014-01-14 15:53 170人阅读 评论(0) 收藏

题目网址:http://haut.openjudge.cn/xiyoulianxi1/1/ 1:晶矿的个数 查看 提交 统计 提问 总时间限制:  1000ms  内存限制:  65536kB 描述 在某个区域发现了一些晶矿,已经探明这些晶矿总共有分为两类,为红晶矿和黑晶矿.现在要统计该区域内红晶矿和黑晶矿的个数.假设可以用二维地图m[][]来描述该区域,若m[i][j]为#表示该地点是非晶矿地点,若m[i][j]为r表示该地点是红晶矿地点,若m[i][j]为b表示该地点是黑晶矿地点.一个晶矿是…

Red and Black(BFS or DFS) 分类： dfs bfs 2015-07-05 22:52 2人阅读 评论(0) 收藏

Description There is a rectangular room, covered with square tiles. Each tile is colored either red or black. A man is standing on a black tile. From a tile, he can move to one of four adjacent tiles. But he can't move on red tiles, he can move only…

HDU1372 Knight Moves（BFS） 2016-07-24 14:50 69人阅读 评论(0) 收藏

Knight Moves Problem Description A friend of you is doing research on the Traveling Knight Problem (TKP) where you are to find the shortest closed tour of knight moves that visits each square of a given set of n squares on a chessboard exactly once.…

save与Update的合并操作 标签： 关系映射 2017-07-13 15:11 7人阅读 评论(0) 收藏

做save与update的方法合并操作时,判断条件是主体对象的ID是否存在. 但是当页面中,涉及到多个主体对象的关联对象时,情况变得复杂起来,特总结项目中的几点 一.页面中的VO对象属性可以分为三类:1.需要在页面中显示的主体对象属性, 需要在页面中显示的主体关联对象的属性 ,不需要显示的隐藏属性(包括主体对象和关联对象的主键,不需要在页面显示的剩下的所有主体和关联对象的属性),简单说vo就是包括主体对象和关联对象的所有属性,但是在页面需要划分. 二.做保存,需要从vo对象转换为主体对象,这个操…

<a>标签中的href伪协议 标签： html 2016-12-24 22:38 365人阅读 评论(0)

<a id="jsPswEdit" class="set-item" href="javascript:;">修改密码</a> 如上代码,javascript:是表示在触发a标签默认动作时,执行一段JavaScript代码, 举个栗子,在script中写了个function test{--},如果a标签里的href="javascript:test()",那么点击这个链接就会执行test这个函数. 而…

获取元素属性中的[x] 标签： javascript 2016-12-24 22:35 105人阅读 评论(0)

<!DOCTYPE HTML> <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8"> <title>无标题文档</title> </head> <body> <div> javascript <p>javascript</p>…