华中农业大学第五届程序设计大赛网络同步赛-L

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华中农业大学第五届程序设计大赛网络同步赛-L

L．Happiness Chicken brother is very happy today, because he attained N pieces of biscuits whose tastes are A or B. These biscuits are put into a box. Now, he can only take out one piece of biscuit from the box one time. As we all know, chicken brothe…

华中农业大学第五届程序设计大赛网络同步赛-K

K．Deadline There are N bugs to be repaired and some engineers whose abilities are roughly equal. And an engineer can repair a bug per day. Each bug has a deadline A[i]. Question: How many engineers can repair all bugs before those deadlines at least?…

华中农业大学第五届程序设计大赛网络同步赛-G

G. Sequence Number In Linear algebra, we have learned the definition of inversion number: Assuming A is a ordered set with n numbers ( n > 1 ) which are different from each other. If exist positive integers i , j, ( 1 ≤ i < j ≤ n and A[i] > A[j])…

华中农业大学第五届程序设计大赛网络同步赛-D

Problem D: GCD Time Limit: 1 Sec Memory Limit: 1280 MBSubmit: 179 Solved: 25[Submit][Status][Web Board] Description XiaoMingfoundthecomputetimeof Input The first line is an positive integer T. ( Output In each test case, output the compute result o…

华中农业大学第五届程序设计大赛网络同步赛-A

Problem A: Little Red Riding Hood Time Limit: 1 Sec Memory Limit: 1280 MBSubmit: 860 Solved: 133[Submit][Status][Web Board] Description Once upon a time, there was a little girl. Her name was Little Red Riding Hood. One day, her grandma was ill. Li…

[HZAU]华中农业大学第四届程序设计大赛网络同步赛

听说是邀请赛啊,大概做了做…中午出去吃了个饭回来过掉的I.然后去做作业了…… #include <algorithm> #include <iostream> #include <iomanip> #include <cstring> #include <climits> #include <complex> #include <fstream> #include <cassert> #include <…

(hzau)华中农业大学第四届程序设计大赛网络同步赛 G: Array C

题目链接:http://acm.hzau.edu.cn/problem.php?id=18 题意是给你两个长度为n的数组,a数组相当于1到n的物品的数量,b数组相当于物品价值,而真正的价值表示是b[i]*k*k(k表示取的数量),给你m表示最少取m个物品.然后让你求取m个的最小的价值和. 一个物品的价值是b[i] , 两个物品的价值是b[i] * 3 + b[i] ... 所以每个物品的价值是b[i] , b[i] * 3 , b[i] * 5 , b[i] * 7 ... 每个物品数量a[i]…