An Unfair Game-[ACdream1035]】的更多相关文章

Problem Description There are n people and n target, everyone should get one target, no two people get the same target, the last one who get the target should be punished, there is only one person will be punished, so if more than one person are the…
C. Unfair Poll time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output On the Literature lesson Sergei noticed an awful injustice, it seems that some students are asked more often than others. Seat…
C. Unfair Poll time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output On the Literature lesson Sergei noticed an awful injustice, it seems that some students are asked more often than others. Seat…
C. Unfair Poll time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output On the Literature lesson Sergei noticed an awful injustice, it seems that some students are asked more often than others. Seat…
Unfair Poll 题意:一共有n排同学每排同学有m个人, 老师问问题有一个顺序, 先从第一排开始问,问完第一排的所有同学之后,再问第2排的,对于所有排的访问顺序为 1,2,3……n-1,n,n-1,n-2,……,2,1,2,然后每次访问到新的一排先要问完这一排的所有人才会往下一(目标)排走. 题解:先声明我们开一个数组来记录这一排被询问的总次数,先将k  /= m, 这个代表的是完全访问的次数,即一整排m位同学都问完有几次,如果  完全访问的次数< n, 我们就将前几排全访问次数的人都加上…
http://codeforces.com/problemset/problem/758/C C. Unfair Poll time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output On the Literature lesson Sergei noticed an awful injustice, it seems that some…
基本的状态压缩,想明白怎么dp还是挺简单的.显然对n个数字进行状态压缩,dp[i][j]表示第i位状态j表示的位向高位产生了进位. /* 4317 */ #include <iostream> #include <sstream> #include <string> #include <map> #include <queue> #include <set> #include <stack> #include <ve…
题意: On the Literature lesson Sergei noticed an awful injustice, it seems that some students are asked more often than others. Seating in the class looks like a rectangle, where n rows with m pupils in each. The teacher asks pupils in the following or…
http://codeforces.com/contest/758/problem/C 需要一个能够找到任意一个位置的步数的方法,就能解决三个问题. 预处理出one(row, col)表示第一次经过这个点,需要的步数. sec(row, col),thr(row, col)分别是第二.三步. 那么,循环节就会产生,记录步数为X, Y, Z,那么,第一二步的差距,和第二三步的差距,分别代表了从下走上去和从上走下来. 那么第4次,就会和第一二步的差距相等 就比如是5.17.23,那么下一步就是35.…
time limit per test1 second memory limit per test256 megabytes inputstandard input outputstandard output On the Literature lesson Sergei noticed an awful injustice, it seems that some students are asked more often than others. Seating in the class lo…
http://codeforces.com/problemset/problem/758/C 题意:教室里有n列m排,老师上课点名从第一列第一排开始往后点,直到点到第一列第m排,就从第二列第一排开始点,当点完第n列的名之后,接着点第n-1列的名.以此类推,就是从列上来看的话:1,2,3,4,……,n,n-1,n-2,……,1 ,2,…….这样的顺序点名.老师上课总共点k次名,问该课堂最多可以点同一个同学多少次,最少可以点同一个同学多少次,点了位置为(x,y)的同学多少次名. 思路:一遇到这种题目…
题意: 给定一个长度为m的序列$A$,你有一个长度为n的棋盘,可以任选一个位置x作为起点. 在时刻$[1,m+1]$你可以向左或向右移动一格. 设时刻i你移动后所在的位置为$B_i$,你需要满足对于任意$1\leq i\leq m$,$A_{i}\neq B_{i}$. 求有多少对有序数对$(x,y)$,使得以x为起点且以y为终点的合法移动路径存在. $n,m\leq 10^{5},1\leq A_{i}\leq n$. 题解: 首先观察出一个性质:设x向左最远走到l,向右最远走到r,则$[l,…
传送门 首先可以注意到对于固定的起点 $S$ ,它最终能走到的终点一定是一段区间 这个用反证法容易证明,假设合法区间存在断点,这个点左右都可以作为终点 那么分成区间断点在起点左边和起点右边讨论一下即可,起点本身显然一定可以作为终点 然后现在只要考虑从每个起点出发能走到的最左和最右的位置即可算出答案 首先考虑往右(以下为了方便把第 $i$ 次询问说成第 $i$ 天) 设起点为 $x$ 那么我们可以一直往右走直到遇到某一天刚好询问原本要走的下一个位置,那么此时就要停一次 设连续走了 $y$ 天遇到这…
题意: 老师点名,顺序是1 -- n -- 1 排为一个循环,每列为1 -- m的顺序, 问点到最多次数和最少次数的人的次数以及(x,y)被点的次数. 分析: 由于点名有循环,故可先判断出每一个循环每个人被点名的次数,再乘以循环数,为答案一部分. 最后一个循环结束后k还有余数,从(1,1)暴力模拟,因为n*m才10000, 再加上前面的,就能得出答案. 注意 n=1 需要特判. #include <bits/stdc++.h> using namespace std; #define LL l…
题意:老师点名顺序规则如下:第1排,第2排,……,第n-1排,第n排,第n-1排,……,第2排,第1排,第2排,……,第n-1排,第n排,……对于每排都是从左到右依次点名,问点名k个人后,所有人中最多的点名次数,最少的点名次数,以及位于x排y列处的同学的点名次数. 分析: 1.由于k很大,将第1排,第2排,……,第n-1排,第n排,第n-1排,……,第2排看成一个循环. 2.这个循环中有2*(n-1)*m个人,注意当n=1时,这个循环中有m个人,将这个循环人数记为tmp. 3.利用k/tmp,算…
题:https://codeforces.com/contest/1236/problem/E 粗自:https://www.cnblogs.com/YSFAC/p/11715522.html #include<bits/stdc++.h> using namespace std; #define lson root<<1,l,midd #define rson root<<1|1,midd+1,r typedef long long ll; ; ll a[M],tre…
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传送门 A. Ariel time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output King Triton really likes watching sport competitions on TV. But much more Triton likes watching live competitions. So Triton de…
jdk1.5并发包中ReentrantLock的创建可以指定构造函数的boolean类型来得到公平锁或非公平锁,关于两者区别,java并发编程实践里面有解释 公平锁:   Threads acquire a fair lock in the order in which they requested it非公平锁:a nonfair lock permits barging: threads requesting a lock can jump ahead of the queueof wait…
Problem Description There is an old country and the king fell in love with a devil. The devil always asks the king to do some crazy things. Although the king used to be wise and beloved by his people. Now he is just like a boy in love and can’t refus…
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