【POJ 2406】Power Strings（KMP循环节）

【【POJ 2406】Power Strings（KMP循环节）】的更多相关文章

poj 2406 Power Srings (kmp循环节) (经典)

<题目链接> 题目大意: 给出一个字符串,求其字串在该字符串中循环的最大周期. 解题分析: length=len-Next[len],len为该字符串的最小循环节,如果len%length==0,那么周期就为len/lenght,如果不能整除,则说明该字符串的字串不具有周期性,输出1. KMP最小循环节的证明 >>> #include <cstdio> #include <cstring> + ; char str[maxn]; int Next[ma…

POJ 2406 Power Strings (KMP)

Power Strings Time Limit: 3000MSMemory Limit: 65536K Total Submissions: 29663Accepted: 12387 Description Given two strings a and b we define a*b to be their concatenation. For example, if a = "abc" and b = "def" then a*b = "abcdef…

poj 2406 Power Strings (kmp 中 next 数组的应用||后缀数组)

http://poj.org/problem?id=2406 Power Strings Time Limit: 3000MS Memory Limit: 65536K Total Submissions: 27003 Accepted: 11311 Description Given two strings a and b we define a*b to be their concatenation. For example, if a = "abc" and b = &q…

POJ 2406 - Power Strings - [KMP求最小循环节]

题目链接:http://poj.org/problem?id=2406 Time Limit: 3000MS Memory Limit: 65536K Description Given two strings a and b we define a*b to be their concatenation. For example, if a = "abc" and b = "def" then a*b = "abcdef". If we thi…

poj 2406 Power Strings(KMP变形)

Power Strings Time Limit: 3000MS Memory Limit: 65536K Total Submissions: 28102 Accepted: 11755 Description Given two strings a and b we define a*b to be their concatenation. For example, if a = "abc" and b = "def" then a*b = "…

poj 2406 Power Strings kmp算法

点击打开链接 Power Strings Time Limit: 3000MS Memory Limit: 65536K Total Submissions: 27368 Accepted: 11454 Description Given two strings a and b we define a*b to be their concatenation. For example, if a = "abc" and b = "def" then a*b =…

POJ 2406 Power Strings KMP求周期

传送门 http://poj.org/problem?id=2406 题目就是求循环了几次. 记得如果每循环输出为1.... #include<cstdio> #include<cstring> const int MAXN=1000000+10; char P[MAXN]; int f[MAXN]; int n,m; void getFail() { int i,j; f[0]=f[1]=0; for(i=1;i<n;i++) { j=f[i]; while(j &…

POJ 2406 Power Strings KMP运用题解

本题是计算一个字符串能完整分成多少一模一样的子字符串. 原来是使用KMP的next数组计算出来的,一直都认为是能够利用next数组的.可是自己想了非常久没能这么简洁地总结出来,也仅仅能查查他人代码才恍然大悟,原来能够这么简单地区求一个周期字符串的最小周期的. 有某些大牛建议说不应该參考代码或者解题报告,可是这些大牛却没有给出更加有效的学习方法,比方不懂KMP.难倒不应该去看?要自己想出KMP来吗?我看不太可能有哪位大牛能够直接自己"又一次创造出KMP"来吧. 好吧.不说"创造…

POJ 2406 Power Strings KMP算法之next数组的应用

题意:给一个字符串,求该串最多由多少个相同的子串相接而成. 思路:只要做过poj 1961之后,这道题就很简单了.poj 1961 详细题解传送门. 假设字符串的长度为len,如果 len % (len - next[len])不为0,说明该字符串不能由其他更短的字符串反复相接而成,结果输出1,否则答案为len / (len - next[len]). #include<stdio.h> #include<string.h> #define maxn 1000010 char s[…

poj 2406 Power Strings KMP匹配

对于数组s[0~n-1],计算next[0~n](多计算一位). 考虑next[n],如果t=n-next[n],如果n%t==0,则t就是问题的解,否则解为1. 这样考虑: 比方字符串"abababab", a b a b a b a b * next -1 0 1 2 3 4 5 6 7 考虑这种模式匹配,将"abababab#"当做主串."abababab*"当做模式串.于是进行匹配到n(n=8)时,出现了不匹配: 主串 …

KMP POJ 2406 Power Strings

题目传送门 /* 题意:一个串有字串重复n次产生,求最大的n KMP:nex[]的性质应用,感觉对nex加深了理解 */ /************************************************ * Author :Running_Time * Created Time :2015-8-10 10:51:54 * File Name :POJ_2406.cpp ************************************************/ #incl…

poj 2406 Power Strings 后缀数组解法

连续重复子串问题 poj 2406 Power Strings http://poj.org/problem?id=2406 问一个串能否写成a^n次方这种形式. 虽然这题用kmp做比较合适,但是我们还是用后缀数组做一做,巩固后缀数组的能力. 对于一个串,如果能写出a^n这种形式,我们可以暴力枚举循环节长度L,那么后缀suffix(1)和suffix(1 + L)的LCP应该就是 lenstr - L.如果能满足,那就是,不能,就不是. 这题的话da算法还是超时,等我学了DC3再写上来. 其实这…

KMP + 求最小循环节 --- POJ 2406 Power Strings

Power Strings Problem's Link: http://poj.org/problem?id=2406 Mean: 给你一个字符串,让你求这个字符串最多能够被表示成最小循环节重复多少次得到. analyse: KMP之next数组的运用.裸的求最小循环节. Time complexity: O(N) Source code: ;; ;); ) ;}/* */…

poj 2406 Power Strings【字符串+最小循环节的个数】

Power Strings Time Limit: 3000MS Memory Limit: 65536K Total Submissions: 38038 Accepted: 15740 Description Given two strings a and b we define a*b t…

POJ 2406 Power Strings next数组循环节应用、

题意:就给出个字符串做*的定义.a^0 = "" (the empty string) and a^(n+1) = a*(a^n). 题目要求n的最大值. 思路: 化简上面的等式之后就知道是求a的n次方,也就是说求所给字符串的最大循环次数,想一想. 如果可以求出所给字符串的最小循环节, 那么是不是就可以求出它的最大循环次数了. 这是肯定的. 因为循环节最小. 循环次数也就最大 #include<iostream> #include<cstring> #…

【kmp+最小循环节】poj 2406 Power Strings

http://poj.org/problem?id=2406 [题意] 给定字符串s,s=a^n,a是s的子串,求n最大是多少 [思路] kmp中的next数组求最小循环节的应用例如 ababab next[6] = 4; 即 ababab ababab 1~4位与2~6位是相同的那么前两位就等于3.4位 3.4位就等于5.6位 …… 所以如果能整除也就循环到最后了如果不能整除就最后余下的几位不在循环内例如 1212121 1212121 最后剩余1不能等于循环节那么…

poj 2406:Power Strings（KMP算法，next[]数组的理解）

Power Strings Time Limit: 3000MS Memory Limit: 65536K Total Submissions: 30069 Accepted: 12553 Description Given two strings a and b we define a*b to be their concatenation. For example, if a = "abc" and b = "def" then a*b = "…

poj 2406 Power Strings (后缀数组 || KMP)

Power Strings Time Limit: 3000MS Memory Limit: 65536K Total Submissions: 28859 Accepted: 12045 Description Given two strings a and b we define a*b to be their concatenation. For example, if a = "abc" and b = "def" then a*b = "…

poj 2406 Power Strings（KMP入门，next函数理解）

Power Strings Time Limit: 3000MS Memory Limit: 65536K Total Submissions: 37685 Accepted: 15590 Description Given two strings a and b we define a*b to be their concatenation. For example, if a = "abc" and b = "def" then a*b = "…

POJ 2406 Power Strings

F - Power Strings Time Limit:3000MS Memory Limit:65536KB 64bit IO Format:%I64d & %I64u Submit Status Practice POJ 2406 Description Given two strings a and b we define a*b to be their concatenation. For example, if a = "abc" and b = &…

poj 2406 Power Strings【最小循环节】

Power Strings Time Limit: 3000MS Memory Limit: 65536K Total Submissions: 36926 Accepted: 15254 Description Given two strings a and b we define a*b to be their concatenation. For example, if a = "abc" and b = "def" then a*b = "…

【POJ 2406 Power Strings】

Time Limit: 3000MSMemory Limit: 65536K Description Given two strings a and b we define a*b to be their concatenation. For example, if a = "abc" and b = "def" then a*b = "abcdef". If we think of concatenation as multiplication…

POJ - 2406 Power Strings （后缀数组DC3版）

题意:求最小循环节循环的次数. 题解:这个题其实可以直接用kmp去求最小循环节,然后在用总长度除以循环节.但是因为在练后缀数组,所以写的后缀数组版本.用倍增法会超时!!所以改用DC3法.对后缀数组还不是很理解,找了很多博客也没看懂到底有些数组到底记录的是啥,但他的实现过程很好理解,等我弄懂了再来给博客加注释吧. 先求出sa数组,height数组,rank数组(因为和c++库中某个东西重了所以写成rnk数组),数组一定要开3倍.接下来从小到大枚举循环节长度 i,如果长度i的子串刚好是重复了len/…

poj 2406 Power Strings 周期问题

Power Strings Time Limit: 3000MS Memory Limit: 65536K Total Submissions: 48139 Accepted: 20040 Description Given two strings a and b we define a*b to be their concatenation. For example, if a = "abc" and b = "def" then a*b = "…

(简单) POJ 2406 Power Strings，扩展KMP。

Description Given two strings a and b we define a*b to be their concatenation. For example, if a = "abc" and b = "def" then a*b = "abcdef". If we think of concatenation as multiplication, exponentiation by a non-negative inte…

poj 2406 Power Strings（kmp应用)

题目链接:http://poj.org/problem?id=2406 题意:给出一个字符串s,求重复子串出现的最大次数. 分析:kmp的next[]数组的应用. 要求重复子串出现的最大次数,其实就是求字符串的最小循环节. 以下内容转载于:http://bbezxcy.iteye.com/blog/1377787 --------------------------------------------------------------------------------------------…