BZOJ 4580: [Usaco2016 Open]248】的更多相关文章

Description 一个序列,每次可以把相邻的两个数合为一个,价值+1,求最后的最大价值. Sol 区间DP. \(f[i][j]\) 表示 \(i-j\) 中合成一个数字为多少,转移就是枚举断点,断点两边的价值一样,就合并. 复杂度 \(O(n^3)\) Code /************************************************************** Problem: 4580 User: BeiYu Language: C++ Result: Ac…
Description Bessie likes downloading games to play on her cell phone, even though she does find the small touch  screen rather cumbersome to use with her large hooves.She is particularly intrigued by the current g ame she is playing. The game starts…
Description 一个序列,每次可以将两个相同的数合成一个数,价值+1,求最后最大价值 \(n \leqslant 262144\) Sol DP. 这道题是 BZOJ 4580: [Usaco2016 Open]248 加强版. 做248的那个区间DP其实很多方案都是0,而且一个区间中只有一个合法的数字. 然后就是 一个区间合成一个数的方案的这个数字是固定的. \(f[i][j]\) 表示以 \(i\) 结尾是否能合成 \(j\),同时记录一下转移位置,每次向前找前一个指针就可以了. 复…
4580: [Usaco2016 Open]248 Time Limit: 10 Sec  Memory Limit: 128 MBSubmit: 255  Solved: 204[Submit][Status][Discuss] Description Bessie likes downloading games to play on her cell phone, even though she does find the small touch  screen rather cumbers…
http://www.lydsy.com/JudgeOnline/problem.php?id=4580 区间dp,f(i,j)表示区间[i,j]全部合成一个数,这个数是多少. 可以归纳证明[i,j]如果可以合成一个数,那么只能合成这一个数 #include<cstdio> #include<cstring> #include<algorithm> using namespace std; const int N = 253; int n, a[N], f[N][N];…
4742: [Usaco2016 Dec]Team Building Time Limit: 10 Sec  Memory Limit: 128 MBSubmit: 21  Solved: 16[Submit][Status][Discuss] Description Every year, Farmer John brings his NN cows to compete for "best in show" at the state fair. His arch -rival, F…
题目描述 Bessie likes downloading games to play on her cell phone, even though she does find the small touch  screen rather cumbersome to use with her large hooves.She is particularly intrigued by the current g ame she is playing. The game starts with a…
4506: [Usaco2016 Jan]Fort Moo Description Bessie is building a fort with her friend Elsie. Like any good fort, this one needs to start with a sturdy frame. Bessie wants to build a frame in the shape of a one-meter-wide rectangular outline, atop which…
4412: [Usaco2016 Feb]Circular Barn Description 有一个N个点的环,相邻两个点距离是1.点顺时针标号为1..N.每一个点有ci头牛,保证∑ci=N.每头牛都可以顺时针走.设一头牛走了d个单位停下了,将耗费d^2的能量.请设计一种牛的走法,使得每一个点上都正好有一头牛,且最小化耗费的能量. Input 第一行一个数N.N <= 100000接下来N行,每行一个数ci. Output 输出一个数表示耗费能量的最小值 Sample Input 10 1 0…
n<=248个数字,可以进行这样的操作:将相邻两个相同的数字合并成这个数字+1,求最大能合成多少. f(i,j)--区间i到j能合成的最大值,f(i,j)=max(f(i,k)+1),f(i,k)=f(k+1,j). #include<stdio.h> #include<string.h> #include<algorithm> #include<stdlib.h> #include<math.h> //#include<iostre…