POJ 2184 01背包+负数处理】的更多相关文章

Cow Exhibition Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 10200   Accepted: 3977 Description "Fat and docile, big and dumb, they look so stupid, they aren't much fun..." - Cows with Guns by Dana Lyons The cows want to prove to…
POJ 2184 Cow Exhibition Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 14657   Accepted: 5950 Description "Fat and docile, big and dumb, they look so stupid, they aren't much fun..." - Cows with Guns by Dana Lyons The cows want to…
POJ-2184 [题意]: 有n头牛,每头牛有自己的聪明值和幽默值,选出几头牛使得选出牛的聪明值总和大于0.幽默值总和大于0,求聪明值和幽默值总和相加最大为多少. [分析]:变种的01背包,可以把幽默度看成体积,智商看成价值,那么就转换成求体积和价值都为正值的最大值的01背包了. 以 TS 作为体积,TF作为价值,在保证体积.价值非负的情况下,求解 sum,取其所有情况的最大值. 难点: 1)体积出现负数,将区间改变 [-100000, 100000] ---> [0, 200000]. (注…
Balance Time Limit: 1000 MS Memory Limit: 30000 KB 64-bit integer IO format: %I64d , %I64u Java class name: Main [Submit] [Status] [Discuss] Description Gigel has a strange "balance" and he wants to poise it. Actually, the device is different fr…
转自:http://blog.csdn.net/liuqiyao_01/article/details/8753686 题意:这是又是一道01背包的变体,题目要求选出一些牛,使smartness和funness值的和最大,而这些牛有些smartness或funness的值是负的,还要求最终的smartness之和以及funness之和不能为负. 这道题的关键有两点:一是将smartness看作花费.将funness看作价值,从而转化为01背包:二是对负值的处理,引入一个shift来表 示“0”,…
思路: 1.01背包 先找到所有奶牛身高和与B的差. 然后做一次01背包即可 01背包的容积和价格就是奶牛们身高. 最后差值一减输出结果就大功告成啦! 2. 搜索 这思路很明了吧... 搜索的确可以过- 3. 模拟! 0到1< < n 来一遍.(状压呗) 01背包的: // by SiriusRen #include <cstdio> #include <algorithm> using namespace std; int N,B,sum=0,h[25],f[1000…
Proud Merchants Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 131072/65536 K (Java/Others)Total Submission(s): 4257    Accepted Submission(s): 1757 Problem Description Recently, iSea went to an ancient country. For such a long time, it was…
初学DP,用贪心的思想想解题,可是想了一个多小时还是想不出. //在max中的两个参数f[k], 和f[k-weight[i]]+value[i]都是表示在背包容量为k时的最大价值 //f[k]是这个意思,就不用说了. //而f[k-weight[i]]+value[i]也表示背包容量为k时的最大价值是为什么呢? //首先,f[k-weight[i]]表示的是背包容量为k-weight[i]的容量,也就是说f[k-weight[i]] //表示的是容量还差weiht[i]才到k的价值,+walu…
poj3624 Charm Bracelet 模板题 没有要求填满,所以初始化为0就行 #include<cstdio> #include<iostream> using namespace std; #define N 15010 int n,m,v[N],c[N],f[N]; int main(){ scanf("%d%d",&n,&m); ;i<=n;i++) scanf("%d%d",&v[i],&…
http://poj.org/problem?id=2184   Description "Fat and docile, big and dumb, they look so stupid, they aren't much fun..." - Cows with Guns by Dana Lyons The cows want to prove to the public that they are both smart and fun. In order to do this,…