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Time Limit: 1000ms Memory Limit: 128000KB 64-bit integer IO format:      Java class name: Submit Status 几年前,在孙老大担任GDUTACM集训队教练之前,集训队的日子过得非常惨淡,实验室的桌子非常老旧,动不动就塌,集训队员们也是苦不堪言.幸运的是,在孙老大的领导下,集训队的日子走向了小康,所有东西都渐渐的有了,打印机(当然是激光的)什么的,高速上网(10+M每秒的下载)什么的.更加重要的是,集…
描述 今天发现了nyoj,如获至宝.准备开刷. 括号配对问题 现在,有一行括号序列,请你检查这行括号是否配对.   输入 第一行输入一个数N(0<N<=100),表示有N组测试数据.后面的N行输入多组输入数据,每组输入数据都是一个字符串S(S的长度小于10000,且S不是空串),测试数据组数少于5组.数据保证S中只含有"[","]","(",")"四种字符 输出 每组输入数据的输出占一行,如果该字符串中所含的括号是…
--------------------------------------------- 这道题有点坑,也怪我总是有点马虎,按照正常人的思维0是表示有水池啊竟然是1表示有水池,最坑的是写反了竟然还能过样例一直以为是自己程序问题review了好多遍.... 图论基础题,染色法即可. AC代码: import java.util.Scanner; public class Main { public static void main(String[] args) { Scanner sc=new…
-----------------------------------------n-1条边的无向连通图是一棵树,又因为树上两点之间的路径是唯一的,所以解是唯一的.(注意并不一定是二叉树,所以最好采用存储图的方式存储树,我使用的是邻接表)这个时候只需要考虑如何求解两点间的路径呢?遍历就可以了.但是应该如何遍历呢?比较容易想到的办法是分别从每个点计算到S点的路径,既然它们的终点相同,那为什么不逆向一下干脆从S点向这些点出发呢?所以现在问题就转化为了从S点出发遍历树,OK,这个问题就比较简单了,只需…
-------------------------------------祭出BigInteger AC代码: import java.math.BigInteger; import java.util.Scanner; public class Main { public static void main(String[] args) { Scanner sc=new Scanner(System.in); int n=sc.nextInt(); BigInteger ans=fac(n);…
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