1019 General Palindromic Number(20 分) A number that will be the same when it is written forwards or backwards is known as a Palindromic Number. For example, 1234321 is a palindromic number. All single digit numbers are palindromic numbers. Although p…
Question:Given a string S, find the longest palindromic substring in S. You may assume that the maximum length of S is 1000, and there exists one unique longest palindromic substring.(给定一个字符串S,在S中找到最长的回文子字符串,假定最长的回文字符串长度是1000,并且在这个字符串中存在唯一的一个最长回文子字符串…
转载请注明出处:z_zhaojun的博客 原文地址:http://blog.csdn.net/u012975705/article/details/50493772 题目地址:https://leetcode.com/problems/move-zeroes/ Move Zeroes Given an array nums, write a function to move all 0's to the end of it while maintaining the relative order…
Given a column title as appear in an Excel sheet, return its corresponding column number. For example: A -> 1 B -> 2 C -> 3 ... Z -> 26 AA -> 27 AB -> 28 class Solution { public: int titleToNumber(string s) { ; ; ; i &l…
Palindrome Number time=434ms 负数不是回文数 public class Solution { public boolean isPalindrome(int x) { int palindrome=0; int revers=x; if(revers<0) return false; else{ while(revers>0){ int m=revers%10; palindrome=m+palindrome*10; revers=revers/10; } if(p…
题目要求:将给出的整数进行逆序输出 注意:整数的最大范围-2147483648-2147483647,当翻转后的数超出范围后返回0 思路:对给出的整数除以10,取余和取整:然后对取整部分继续取余和取整,同时将前一次取余的部分乘10再加上该次取余...直至余数为零 public class Solution { public static void main(String[] args) { Solution sol = new Solution(); // System.out.println(…
很经典的一道题,最长回文子串,有多种方法. 首先介绍的一种方法是从中间向两边展开.注意区分aba和abba型的回文串:如果当前最长的子串已经当于两边中最长的子串了,则无需再去判断. //从中间向两边展开 string expandAroundCenter(string s, int c1, int c2) { int l = c1, r = c2; int n = s.length(); && r <= n - && s[l] == s[r]) { l--; r++;…
1019 General Palindromic Number (20 分) A number that will be the same when it is written forwards or backwards is known as a Palindromic Number. For example, 1234321 is a palindromic number. All single digit numbers are palindromic numbers. Although…
Question: Given a roman numeral, convert it to an integer. Input is guaranteed to be within the range from 1 to 3999. 给一个罗马数字,把它转化成阿拉伯数字,可以保证罗马数字的输入在1到3999之间. 这个题和我上篇文章写的<leetcode:Integer to Roman(整数转化为罗马数字>正好相反,在上一篇文章中,我简单介绍了罗马数字的计数方法和组数规则,并举了一些例子,…
Single Number: 1. Given an array of integers, every element appears twice except for one. Find that single one. Note:Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory? 代码: class Solution { publi…
===================================================== Media Player Classic - HC 源代码分析系列文章列表: Media Player Classic - HC 源代码分析 1:整体结构 Media Player Classic - HC 源代码分析 2:核心类 (CMainFrame)(1) Media Player Classic - HC 源代码分析 3:核心类 (CMainFrame)(2) Media Play…