Give you three sequences of numbers A, B, C, then we give you a number X. Now you need to calculate if you can find the three numbers Ai, Bj, Ck, which satisfy the formula Ai+Bj+Ck = X. Input There are many cases. Every data case is described as foll…
Can you find it? Give you three sequences of numbers A, B, C, then we give you a number X. Now you need to calculate if you can find the three numbers Ai, Bj, Ck, which satisfy the formula Ai+Bj+Ck = X. 你以为我是因为被$world final$打击到了而在做水题吗? 没错我就是在做水题.....…
题目描述 可爱的演演又来了,这次他想问渣渣一题... 如果给你三个数列 A[],B[],C[],请问对于给定的数字 X,能否从这三个数列中各选一个,使得A[i]+B[j]+C[k]=X? 输入 多组数据,你应处理到 EOF. 每组数据的第一行是三个数 L, M, N,分别代表数列 A[],B[],C[] 的长度,接下来三行,每行分别是L, M, N 个数,分别代表数列 A[], B[], C[]. 接下来一行包含一个数S,代表有S组询问.之后的S行每行一个数,代表这组询问的 X. 1<=L, N…
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=4190 Distributing Ballot Boxes Time Limit: 20000/10000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 1065    Accepted Submission(s): 536 Problem Description Today, bes…
题意 一个长度$n<=1e5$的数轴,$m<=1e5$个操作 有两种一些操作 $0$  $x$ 在$x$放一个食物 $1$ 一个虫子去吃最近的食物,如果有两个食物一样近,不转变方向的去吃 虫子一开始在$0$点,没吃的就不动 求最终虫子跑了多远? 解法: 用数组维护每个地点有几个食物, 用树状数组维护数轴区间和,每次对于左右进行二分区间求和,找到左右最近的那个点,取最小值即可 #include <bits/stdc++.h> #define ll long long #define…
[题目链接]click here~~ [题目大意]在给定 的数组里选两个数取模p的情况下和最大 [解题思路]: 思路见官方题解吧~~ 弱弱献上代码: Problem : 5265 ( pog loves szh II ) Judge Status : Accepted RunId : 13961817 Language : G++ Author : javaherongwei Code Render Status : Rendered By HDOJ G++ Code Render Versio…
Equal Sum Partitions Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 551    Accepted Submission(s): 409 Problem Description An equal sum partition of a sequence of numbers is a grouping of the…
Can you find it? Time Limit: 10000/3000 MS (Java/Others)    Memory Limit: 32768/10000 K (Java/Others)Total Submission(s): 9180    Accepted Submission(s): 2401 Problem Description Give you three sequences of numbers A, B, C, then we give you a number…
Problem Description Give you three sequences of numbers A, B, C, then we give you a number X. Now you need to calculate if you can find the three numbers Ai, Bj, Ck, which satisfy the formula Ai+Bj+Ck = X.   Input There are many cases. Every data cas…
Give you three sequences of numbers A, B, C, then we give you a number X. Now you need to calculate if you can find the three numbers Ai, Bj, Ck, which satisfy the formula Ai+Bj+Ck = X. Input There are many cases. Every data case is described as foll…
题目链接: Can you find it? Time Limit: 10000/3000 MS (Java/Others)    Memory Limit: 32768/10000 K (Java/Others)Total Submission(s): 38634    Accepted Submission(s): 9395 Problem Description Give you three sequences of numbers A, B, C, then we give you a…
题目传送门 /* 题意:给出一个数,问是否有ai + bj + ck == x 二分查找:首先计算sum[l] = a[i] + b[j],对于q,枚举ck,查找是否有sum + ck == x */ #include <cstdio> #include <algorithm> #include <cmath> using namespace std; typedef long long ll; ; const int INF = 0x3f3f3f3f; ll a[MA…
链接:http://acm.hdu.edu.cn/showproblem.php?pid=2141 Can you find it? Time Limit: 10000/3000 MS (Java/Others)    Memory Limit: 32768/10000 K (Java/Others)Total Submission(s): 11503    Accepted Submission(s): 3021 Problem Description Give you three seque…
Can you find it? Time Limit: 10000/3000 MS (Java/Others)    Memory Limit: 32768/10000 K (Java/Others)Total Submission(s): 17036    Accepted Submission(s): 4337 Problem Description Give you three sequences of numbers A, B, C, then we give you a number…
题目连接 http://acm.hdu.edu.cn/showproblem.php?pid=2141 Can you find it? Description Give you three sequences of numbers A, B, C, then we give you a number X. Now you need to calculate if you can find the three numbers Ai, Bj, Ck, which satisfy the formu…
Can you find it? Time Limit: 10000/3000 MS (Java/Others)    Memory Limit: 32768/10000 K (Java/Others)Total Submission(s): 8506    Accepted Submission(s): 2216 Problem Description Give you three sequences of numbers A, B, C, then we give you a number…
题目传送门 /* 贪心/二分查找:首先对ai%=p,然后sort,这样的话就有序能使用二分查找.贪心的思想是每次找到一个aj使得和为p-1(如果有的话) 当然有可能两个数和超过p,那么an的值最优,每次还要和an比较 注意:不能选取两个相同的数 反思:比赛时想到了%p和sort,lower_bound,但是还是没有想到这个贪心方法保证得出最大值,还是题目做的少啊:( */ #include <cstdio> #include <algorithm> #include <cst…
O - Can you find it? Time Limit:3000MS     Memory Limit:10000KB     64bit IO Format:%I64d & %I64u Description Give you three sequences of numbers A, B, C, then we give you a number X. Now you need to calculate if you can find the three numbers Ai, Bj…
Description Give you three sequences of numbers A, B, C, then we give you a number X. Now you need to calculate if you can find the three numbers Ai, Bj, Ck, which satisfy the formula Ai+Bj+Ck = X. Input There are many cases. Every data case is descr…
Description Give you three sequences of numbers A, B, C, then we give you a number X. Now you need to calculate if you can find the three numbers Ai, Bj, Ck, which satisfy the formula Ai+Bj+Ck = X.    Input There are many cases. Every data case is de…
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=2141 题目大意:查找是否又满足条件的x值. 这里简单介绍一个小算法,二分查找. /* x^2+6*x-7==y 输入y 求x 精确度为10^-5 0=<x<=10000 */ #include <iostream> #include <cstdio> using namespace std; int main (void) { double y; while(cin>…
Vases and Flowers 题目链接 http://acm.hdu.edu.cn/showproblem.php?pid=4614 Problem Description Alice is so popular that she can receive many flowers everyday. She has N vases numbered from 0 to N-1. When she receive some flowers, she will try to put them…
OO's Sequence Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others) Total Submission(s): 955    Accepted Submission(s): 358 Problem Description OO has got a array A of size n ,defined a function f(l,r) represent the nu…
Doubles Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 4266    Accepted Submission(s): 2945 Problem Description As part of an arithmetic competency program, your students will be given randoml…
题意:给出一个整数nnn, 找出一个大于等于nnn的最小整数mmm, 使得mmm可以表示为2a3b5c7d2^a3^b5^c7^d2​a​​3​b​​5​c​​7​d​​. 析:预处理出所有形为2a3b5c7d2^a3^b5^c7^d2​a​​3​b​​5​c​​7​d​​即可, 大概只有5000左右个.然后用二分查找就好. 代码如下: #pragma comment(linker, "/STACK:1024000000,1024000000") #include <cstdio…
题意: 给定一个素数p(p <= 1e12),问是否存在一对立方差等于p. 分析: 根据平方差公式: 因为p是一个素数, 所以只能拆分成 1*p, 所以 a-b = 1. 然后代入a = b + 1. 求出 3a² + 3a + 1 = p 化简得a(a+1) = (p-1)/3 令(p-1)/3 = T, 问题化为是否存在整数a使得a(a+1) == T, 那么令 t = (int)sqrt(T),只要判定一下t * (t+1) == T ? 即可 另一种做法是打一个a的表(a只要打到1e6)…
解题思路:给出两个数列an,bn,求an和bn中相同元素的个数因为注意到n的取值是0到1000000,所以可以用二分查找来做,因为题目中给出的an,bn,已经是单调递增的,所以不用排序了,对于输入的每一个b[i],查找它在an数列中是否存在.存在返回值为1,不存在返回值为0 CD Time Limit: 12000/6000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 627…
题目链接:http://acm.split.hdu.edu.cn/showproblem.php?pid=5652 Problem Description A long time ago there are no himalayas between India and China, the both cultures are frequently exchanged and are kept in sync at that time, but eventually himalayas rise…
http://acm.hdu.edu.cn/showproblem.php?pid=4750 题意: 定义f(u,v)为u到v每条路径上的最大边的最小值..现在有一些询问..问f(u,v)>=t的点对有所少对,注意(1,2)和(2,1)是不同的点对 分析: 原来最小生成树有一个很鬼畜的结论,那就是一个图的最小生成树中任意两个点的路径中的最大边一定最小.(妈蛋,完全不知道这个) 然后此题就变得很明朗了,用kruskal算法,加边的时候此边连接的两个集合的路径中的最大边就是这个边,存储下来,询问的时…
题目连接:http://acm.hdu.edu.cn/showproblem.php?pid=1597 find the nth digit Time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 9517    Accepted Submission(s): 2757 Problem Description 假设:S1 = 1S2 = 12S3…