PAT A1059 标签(空格分隔): PAT 解题思路 :先打印出素数表.利用结构体数组来存贮质因子的值和个数 strcut factor{ int x; //值 int cnt; //个数 }fac[20]; 如果i是x的质因子,就令fac[index].x = i(index是某个下标), fac[index].cnt = 0,然后 n = n / i.若又遇到i是x的质因子,则cnt++. 进行完上述操作后,n != 1,则说明n还有一个大于sqrt(n)的质因子(可能就是sqrt(n)…
Source: PAT A1059 Prime Factors (25 分) Description: Given any positive integer N, you are supposed to find all of its prime factors, and write them in the format N = p1k1×p2k2×⋯×pmkm. Input Specification: Each input file co…
Given any positive integer N, you are supposed to find all of its prime factors, and write them in the format N = p1k1×p2k2×⋯×pmkm. Input Specification: Each input file contains one test case which gives a positive integer …
原题连接:https://pta.patest.cn/pta/test/16/exam/4/question/677 题目如下: The ranklist of PAT is generated from the status list, which shows the scores of the submissions. This time you are supposed to generate the ranklist for PAT. Input Specification: Each…