hdu1866 A + B forever!(面积并)题解】的更多相关文章

A + B forever! Time Limit: 5000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 1295    Accepted Submission(s): 326 Problem Description As always, A + B is the necessary problem of this warming-up contest. But…
https://www.lydsy.com/JudgeOnline/problem.php?id=2178 给出N个圆,求其面积并. simpson,将圆劈成两半,假设上面的叫上壳,下面的叫下壳,对这两个壳分别做一遍simpson,相减就是答案. 当然优化时间可以去掉完全包含的圆. 以及相减的时候注意同一坐标的不同解,我们要求他的并. 另外精度死活调不对,参考了:https://www.cnblogs.com/SfailSth/p/6360277.html的代码才过orz #include<cm…
Bayan 2015 Contest Warm Up http://codeforces.com/contest/475 A - Bayan Bus B - Strongly Connected City C - Kamal-ol-molk's Painting A. Bayan Bus 题意:输入人数k,输出一辆公交车!优先坐最后,同一排优先坐左边. 题解:暴力找地方坐啊! //#pragma comment(linker, "/STACK:102400000,102400000")…
 描述 There are several ancient Greek texts that contain descriptions of the fabled island Atlantis. Some of these texts even include maps of parts of the island. But unfortunately, these maps describe different regions of Atlantis. Your friend Bill ha…
Triangle Time Limit: 3000MS   Memory Limit: 30000K Total Submissions: 9060   Accepted: 2698 Description Given n distinct points on a plane, your task is to find the triangle that have the maximum area, whose vertices are from the given points. Input…
题目链接   题意:给出n个矩形,求能覆盖所有矩形的最小的矩形的面积. 题解:对所有点求凸包,然后旋转卡壳,对没一条边求该边的最左最右和最上的三个点. 利用叉积面积求高,利用点积的性质求最左右点和长度,更新面积最小值即可. #include<iostream> #include<cstdio> #include<cmath> #include<algorithm> #define MAX 50010 using namespace std; struct P…
题面 题意:给你一个半圆,和另一个多边形(可凹可凸),求面积交 题解:直接上板子,因为其实这个多边形不会穿过这个半圆,所以他和圆的交也就是和半圆的交 打的时候队友说凹的不行,不是板题,后面想想,圆与多边形面积交本来就是拆成有向三角形做的,所以无论凹凸了 #include<bits/stdc++.h> #define inf 1000000000000 #define M 100009 #define eps 1e-12 #define PI acos(-1.0) using namespace…
题目链接 https://pintia.cn/problem-sets/994805046380707840/problems/994805046577840128 题意:给定n个点求三角形最小面积: 题解:该题两个难点: 1.该怎么遍历(正常枚举会超时). 2.用什么方法计算三角形面积. 解决方案:利用极角排序(先向量后叉积)来遍历,同时利用向量积来计算三角形面积. Ac 代码: #include<bits/stdc++.h> using namespace std; const int m…
题目链接 题意:一个机器人打扫卫生,URDL代表初始时机器人面对的方向上右下左. ' . ' 代表可以打扫的, ' * ' 代表家具,如果机器人遇到家具就顺时针转90度,问机器人能打扫多少面积. 题解:记录机器人走过每个点时所面对的方向,如果走过了这个点走过的方向就不用走了,模拟机器人的行走过程即可.只记录机器人第一次走过某点时面对的方向也可以.数据范围较小,开个三维vis数组也行. #include <cstdio> #include <iostream> #include &l…
A. Vanya and Table time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output Vanya has a table consisting of 100 rows, each row contains 100 cells. The rows are numbered by integers from 1 to 100 fr…