SMU Summer 2023 Contest Round 12】的更多相关文章

我能说我比较傻么!就只能做一道签到题,没办法,我就先写下A题的题解&源码吧,日后补上剩余题的题解&源码吧!                                     A -- Niro plays Galaxy Note 7                    Time Limit:1s Memory Limit:128MByte DESCRIPTION Niro, a lovely girl, has bought a Galaxy Note 7 and wants to…
Codeforces Beta Round #12 (Div 2 Only) http://codeforces.com/contest/12 A 水题 #include<bits/stdc++.h> using namespace std; #define lson l,mid,rt<<1 #define rson mid+1,r,rt<<1|1 #define sqr(x) ((x)*(x)) #define maxn 1000010 typedef long lo…
War Time Limit: 8000/5000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 81    Accepted Submission(s): 23 Special Judge Problem Description Long long ago there are two countrys in the universe. Each country haves i…
F. Four Divisors 题目连接: http://www.codeforces.com/contest/665/problem/F Description If an integer a is divisible by another integer b, then b is called the divisor of a. For example: 12 has positive 6 divisors. They are 1, 2, 3, 4, 6 and 12. Let's def…
D. Ball Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/problemset/problem/12/D Description N ladies attend the ball in the King's palace. Every lady can be described with three values: beauty, intellect and richness. King's Master…
C. Subsequences Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/contest/597/problem/C Description For the given sequence with n different elements find the number of increasing subsequences with k + 1 elements. It is guaranteed tha…
B. Restaurant Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/contest/597/problem/B Description A restaurant received n orders for the rental. Each rental order reserve the restaurant for a continuous period of time, the i-th order…
A. Divisibility Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/contest/597/problem/A Description Find the number of k-divisible numbers on the segment [a, b]. In other words you need to find the number of such integer values x tha…
链接:http://codeforces.com/contest/665/problem/E 题意:求规模为1e6数组中,连续子串xor值大于等于k值的子串数: 思路:xor为和模2的性质,所以先预处理之后,可以枚举这种确实子串区间的方法为O(n^2): 优化?把每一个前缀xor扔到二叉树中,从根节点出发,以高位前缀值的二进制数构造一颗二叉树,这样就可以在构造的时候,实现对子树节点个数的求解:之后在线求解到当前节点的可选的前缀xor的个数, 即以k为主线 如果当前位k为1,则在前缀二叉树中只能找…
http://www.jb51.net/article/74284.htm 解释: round()函数,是四舍五入用,第一个参数是我们要被操作的数据,第二个参数是设置小数四舍五入的精度. )--32.700 numeric函数,保留小数点后有效数.2个参数,第一个表示数据长度,第二个参数表示小数点后位数. cast as numeric(5,2)函数,转换数据类型,在是为了四舍五入之后的数字能确保显示小数点. 它包括用AS关键字分隔的源值和目标数据类型将这个值转换为numeric类型      …