PAT 甲级【1015 Reversible Primes】】的更多相关文章

1015 Reversible Primes(20 分) A reversible prime in any number system is a prime whose "reverse" in that number system is also a prime. For example in the decimal system 73 is a reversible prime because its reverse 37 is also a prime. Now given a…
1015 Reversible Primes (20 分)   A reversible prime in any number system is a prime whose "reverse" in that number system is also a prime. For example in the decimal system 73 is a reversible prime because its reverse 37 is also a prime. Now give…
https://pintia.cn/problem-sets/994805342720868352/problems/994805495863296000 A reversible prime in any number system is a prime whose "reverse" in that number system is also a prime. For example in the decimal system 73 is a reversible prime be…
A reversible prime in any number system is a prime whose "reverse" in that number system is also a prime. For example in the decimal system 73 is a reversible prime because its reverse 37 is also a prime. Now given any two positive integers N (&…
题目 A reversible prime in any number system is a prime whose "reverse" in that number system is also a prime. For example in the decimal system 73 is a reversible prime because its reverse 37 is also a prime. Now given any two positive integers N…
PAT (Advanced Level) Practice 1015 Reversible Primes (20 分) 凌宸1642 题目描述: A reversible prime in any number system is a prime whose "reverse" in that number system is also a prime. For example in the decimal system 73 is a reversible prime because…
1015 Reversible Primes (20 分)   A reversible prime in any number system is a prime whose "reverse" in that number system is also a prime. For example in the decimal system 73 is a reversible prime because its reverse 37 is also a prime. Now give…
1015 Reversible Primes (20)(20 分)提问 A reversible prime in any number system is a prime whose "reverse" in that number system is also a prime. For example in the decimal system 73 is a reversible prime because its reverse 37 is also a prime. Now…
1015 Reversible Primes(20 分) A reversible prime in any number system is a prime whose "reverse" in that number system is also a prime. For example in the decimal system 73 is a reversible prime because its reverse 37 is also a prime. Now given a…
Reversible Primes A reversible prime in any number system is a prime whose "reverse" in that number system is also a prime. For example in the decimal system 73 is a reversible prime because its reverse 37 is also a prime. Now given any two posi…
题意: 每次输入两个正整数N,D直到N是负数停止输入(N<1e5,1<D<=10),如果N是一个素数并且将N转化为D进制后逆转再转化为十进制后依然是个素数的话输出Yes,否则输出No. trick: 判断转化后的数是不是1,1不是素数,如果转化后不是1说明转化前也不会是1(第一个测试点错误原因). AAAAAccepted code: #include<bits/stdc++.h> using namespace std; int main(){ int n,d; while…
A reversible prime in any number system is a prime whose "reverse" in that number system is also a prime. For example in the decimal system 73 is a reversible prime because its reverse 37 is also a prime. Now given any two positive integers N (&…
A reversible prime in any number system is a prime whose "reverse" in that number system is also a prime. For example in the decimal system 73 is a reversible prime because its reverse 37 is also a prime. Now given any two positive integers N (&…
题目 A reversible prime in any number system is a prime whose "reverse" in that number system is also a prime. For example in the decimal system 73 is a reversible prime because its reverse 37 is also a prime. Now given any two positive integers N…
简单题. #include<iostream> #include<cstring> #include<cmath> #include<algorithm> #include<cstdio> #include<map> #include<queue> using namespace std; int a,b; ],tot; bool f(int x) { ) ; ;i*i<=x;i++) ) ; ; } int mai…
先判断n是否为素数然后把n转化成d进制下再反转,转化为十进制的num判断num是否为素数 注意n为0和1时,不是素数!!!注意反转后的num也有可能为1,不是素数!!! #include <iostream> #include <cstdio> #include <algorithm> #include <cstring> #include <cmath> using namespace std; int n,d; bool isprime(in…
转换进制&&逆序可以在一起进行,有一点技巧,不要用十进制数来表示低进制,容易溢出. #include <iostream> #include <vector> using namespace std; bool isPrime(int n) { if(n < 2) return false; if(n == 2) return true; if(n % 2 == 0) return false; for(int i = 3; i < n; i += 2)…
the problem is from PAT,which website is http://pat.zju.edu.cn/contests/pat-a-practise/1015 this problem is relatively easy.if there must be something which need to be noticed, i think "1 is not a prime" could be one of them. #include<stdio.h…
problem A reversible prime in any number system is a prime whose "reverse" in that number system is also a prime. For example in the decimal system 73 is a reversible prime because its reverse 37 is also a prime. Now given any two positive integ…
A reversible prime in any number system is a prime whose "reverse" in that number system is also a prime. For example in the decimal system 73 is a reversible prime because its reverse 37 is also a prime. Now given any two positive integers N (&…
题目分析: 本题计算过程简单,但翻译令我迷茫:题意读清楚很重要(反正我是懵逼了)对于一个10进制的数,如果它是一个素数,把它转换成d进制,再将这个序列逆序排,这个逆序的d进制数的10进制表示如果也是素数,则输出Yes,否则No #include<iostream> #include<cmath> using namespace std; ]; //存放n转换成的d进制数的每一位 int cnt; //存放d进制的位数 bool isPrime(int x){ ) return fa…
1. 题目 2. 抽象建模 无 3. 方法 无 4. 注意点 素数判断(1不是素数) 数值的倒转 5. 代码 #include<stdio.h> #include<math.h> int isPrime(int num){ if(num < 2){ return 0; } for(int i=2;i<=num/2;i++){ if(num%i == 0){ return 0; } } return 1; } int reverse(int num, int d, int…
博主欢迎转载,但请给出本文链接,我尊重你,你尊重我,谢谢~http://www.cnblogs.com/chenxiwenruo/p/6102219.html特别不喜欢那些随便转载别人的原创文章又不给出链接的所以不准偷偷复制博主的博客噢~~ 时隔两年,又开始刷题啦,这篇用于PAT甲级题解,会随着不断刷题持续更新中,至于更新速度呢,嘿嘿,无法估计,不知道什么时候刷完这100多道题. 带*的是我认为比较不错的题目,其它的难点也顶多是细节处理的问题~ 做着做着,发现有些题目真的是太水了,都不想写题解了…
准备每天刷两题PAT真题.(一句话题解) 1001 A+B Format  模拟输出,注意格式 #include <cstdio> #include <cstring> #include <iostream> #include <algorithm> using namespace std; string ans = ""; int main() { ; cin >> a >> b; c = a + b; ) {…
题目:1013 Battle Over Cities 思路:城市数也就1000, 对于每次询问暴力bfs一下看一下有多少连通块就行了.答案就是联通块数减一. #include<stdio.h> #include<stdlib.h> #include<map> #include<set> #include<iostream> #include<cstring> #include<algorithm> #include<…
树(23) 备注 1004 Counting Leaves   1020 Tree Traversals   1043 Is It a Binary Search Tree 判断BST,BST的性质 1053 Path of Equal Weight   1064 Complete Binary Search Tree 完全二叉树的顺序存储,BST的性质 1066 Root of AVL Tree 构建AVL树,模板题,需理解记忆 1079 Total Sales of Supply Chain…
进制转换题 PAT (Advanced Level) Practice 进制转换题 目录 <算法笔记> 重点摘要 1015 Reversible Primes (20) 1019 General Palindromic Number (20) 1027 Colors in Mars (20) 1058 A+B in Hogwarts (20) 1100 Mars Numbers (20) <算法笔记> 3.5 进制转换 重点摘要 P进制转换为Q进制,分两步 P进制转换为10进制 /…
1015. Reversible Primes (20) 时间限制 400 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue A reversible prime in any number system is a prime whose "reverse" in that number system is also a prime. For example in the decimal system 73 is a…
Source: PAT A1015 Reversible Primes (20 分) Description: A reversible prime in any number system is a prime whose "reverse" in that number system is also a prime. For example in the decimal system 73 is a reversible prime because its reverse 37 i…
专题一  字符串处理 A1001 Format(20) #include<cstdio> int main () { ]; int a,b,sum; scanf ("%d %d",&a,&b); sum=a+b; ) { printf ("-"); sum=-sum; } ; ) { s[top++]=; } ) { s[top++]=sum%; sum/=; } ;i>=;i--) { printf ("%d"…