Bomb Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 131072/65536 K (Java/Others) Total Submission(s): 13181    Accepted Submission(s): 4725 Problem Description The counter-terrorists found a time bomb in the dust. But this time the terrorist…

/* dp[i][0|1|2]:没有49的个数|最高位是9,没有49的个数|有49的个数 dp[i][0]=10*dp[i-1][0]-dp[i-1][1] dp[i][1]=dp[i-1][0] dp[i][2]=10*dp[i-1][2]+dp[i-1][1] */ #include<bits/stdc++.h> using namespace std; #define ll long long ll dp[][],n,t; void init(){ dp[][]=; ;i<=;i+…

Bomb Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 131072/65536 K (Java/Others)Total Submission(s): 10649    Accepted Submission(s): 3758 Problem Description The counter-terrorists found a time bomb in the dust. But this time the terrorists…

数位dp简介: 数位dp常用于求区间内某些特殊(常关于数字各个数位上的值)数字(比如要求数字含62,49): 常用解法: 数位dp常用记忆化搜索或递推来实现: 由于记忆化搜索比较好写再加上博主比较蒟,所以本文基本只介绍用记忆化搜索实现的数位dp: 记搜写法: 一般记搜写法会暴力搜索每个数的每一位,如果满足特征就加入答案: 而搜索中或搜完后用一个dp数组来存某一区间的特殊数的数量,防止多次重复搜索TLE: 空口说比较苍白无力,举个例子:比如要在1到r中找含49(4和9要连在一起)的特殊数的数量:…

http://acm.hdu.edu.cn/showproblem.php?pid=3555 Bomb Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 131072/65536 K (Java/Others) Total Submission(s): 7316    Accepted Submission(s): 2551 Problem Description The counter-terrorists found a time…

Bomb Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 131072/65536 K (Java/Others)Total Submission(s): 7921    Accepted Submission(s): 2778 Problem Description The counter-terrorists found a time bomb in the dust. But this time the terrorists…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=3555 简单的数位DP入门题目 思路和hdu2089基本一样 直接贴代码了,代码里有详细的注释 代码: #include<iostream> #include<cstdlib> #include<cstdio> #include<cstring> using namespace std; ][]; void init() { dp[][]=;dp[][]=;dp[…

Description 题意就是找0到N有多少个数中含有49. \(1\leq N \leq2^{63}-1\) Solution 数位DP,与hdu3652类似 \(F[i][state]\)表示位数为i,包含49状态为state时的方案数 注意开\(long long\) Tips 注意N范围很大,位数不止10位!! Code #include <cstdio> #include <cstring> #define ll long long int d[20]; ll dp[2…

题目描述 求 1~N 内包含数位串 “49” 的数的个数. 输入 The first line of input consists of an integer T (1 <= T <= 10000), indicating the number of test cases. For each test case, there will be an integer N (1 <= N <= 2^63-1) as the description.The input terminates…

Description 题意就是找0到N有多少个数中含有49. \(1\leq N \leq2^{63}-1\) Solution 数位DP,与hdu3652类似 \(F[i][state]\)表示位数为i,包含49状态为state时的方案数 注意开\(long long\) Tips 注意N范围很大,位数不止10位!! Code #include <cstdio> #include <cstring> #define ll long long int d[20]; ll dp[2…