HDU ACM 2845 Beans->动态规划】的更多相关文章

意甲冠军: 1. 对于每一行是,对不相邻的同一时间数取: 2.它是相同的列,相邻行不能同时服用: 3.因此,我们可以得到状态方程:dp[i]=dp[i-1]>(dp[i-2]+a[i])?dp[i-1]:dp[i-2]+a[i].先对每一行运用,在对每一行求出的和作为一组运用.可得终于结果. #include<iostream> using namespace std; int col[200001]; int dp[200001]; int GetMaxRow(int a[],int…
HDU 1074 Doing Homework (动态规划,位运算) Description Ignatius has just come back school from the 30th ACM/ICPC. Now he has a lot of homework to do. Every teacher gives him a deadline of handing in the homework. If Ignatius hands in the homework after the d…
Ignatius and the Princess III Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 11810    Accepted Submission(s): 8362 Problem Description "Well, it seems the first problem is too easy. I will let…
hdu 3037 Saving Beans 题目大意:n个数,和不大于m的情况,结果模掉p,p保证为素数. 解题思路:隔板法,C(nn+m)多选的一块保证了n个数的和小于等于m.可是n,m非常大,所以用到Lucas定理. #include <cstdio> #include <cstring> #include <algorithm> using namespace std; typedef long long ll; ll n, m, p; ll qPow (ll a…
HDU 1176 免费馅饼 (动态规划) Description 都说天上不会掉馅饼,但有一天gameboy正走在回家的小径上,忽然天上掉下大把大把的馅饼.说来gameboy的人品实在是太好了,这馅饼别处都不掉,就掉落在他身旁的10米范围内.馅饼如果掉在了地上当然就不能吃了,所以gameboy马上卸下身上的背包去接.但由于小径两侧都不能站人,所以他只能在小径上接.由于gameboy平时老呆在房间里玩游戏,虽然在游戏中是个身手敏捷的高手,但在现实中运动神经特别迟钝,每秒种只有在移动不超过一米的范围…
Beans Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 3521    Accepted Submission(s): 1681 Problem Description Bean-eating is an interesting game, everyone owns an M*N matrix, which is filled w…
Beans Time Limit:1000MS     Memory Limit:32768KB     64bit IO Format:%I64d & %I64u Submit Status Practice HDU 2845 Description Bean-eating is an interesting game, everyone owns an M*N matrix, which is filled with different qualities beans. Meantime,…
题目:http://acm.hdu.edu.cn/showproblem.php?pid=2845 题意:吃豆子游戏 , 当你吃了一个格子的豆子 , 该格子左右两个和上下两行就不能吃了 , 输入每个格子的豆子数 , 求你最多能吃多少颗豆子? 在最大连续数列的基础上,改变了,求最大不连续和? 我们可以先求单独的每一行的的最大不连续和,相当于对矩阵进行压缩,将n列压缩成了一列.然后再求,这一列的最大不连续和. dp方程: m[j]=max(m[j-1],m[j-2]+temp) 对temp两种选择…
Beans Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 2596    Accepted Submission(s): 1279 Problem Description Bean-eating is an interesting game, everyone owns an M*N matrix, which is filled w…
Beans Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 3418    Accepted Submission(s): 1629 Problem Description Bean-eating is an interesting game, everyone owns an M*N matrix, which is filled wi…