POJ1458 Common Subsequence】的更多相关文章

Common Subsequence Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 37614   Accepted: 15058 Description A subsequence of a given sequence is the given sequence with some elements (possible none) left out. Given a sequence X = < x1, x2, ..…
Common Subsequence Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 44464 Accepted: 18186 Description A subsequence of a given sequence is the given sequence with some elements (possible none) left out. Given a sequence X = < x1, x2, -, xm…
题目链接:http://poj.org/problem?id=1458 Common Subsequence Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 55099   Accepted: 22973 Description A subsequence of a given sequence is the given sequence with some elements (possible none) left ou…
link:http://poj.org/problem?id=1458 最基础的那种 #include <iostream> #include <cstdio> #include <cstdlib> #include <cstring> #include <cmath> #include <cctype> #include <algorithm> #include <queue> #include <de…
题目链接:http://poj.org/problem?id=1458 分析:最大公共子序列模板 1 #include<iostream> 2 #include<sstream> 3 #include<cstdio> 4 #include<cstdlib> 5 #include<string> 6 #include<cstring> 7 #include<algorithm> 8 #include<functiona…
POJ1458 Common Subsequence(最长公共子序列LCS) http://poj.org/problem?id=1458 题意: 给你两个字符串, 要你求出两个字符串的最长公共子序列长度. 分析: 本题不用输出子序列,非常easy,直接处理就可以. 首先令dp[i][j]==x表示A串的前i个字符和B串的前j个字符的最长公共子序列长度为x. 初始化: dp全为0. 状态转移: IfA[i]==B[j] then dp[i][j]= dp[i-1][j-1]+1 else dp[…
Problem Description A subsequence of a given sequence is the given sequence with some elements (possible none) left out. Given a sequence X = <x1, x2, ..., xm> another sequence Z = <z1, z2, ..., zk> is a subsequence of X if there exists a stri…
Common Subsequence Descriptions: A subsequence of a given sequence is the given sequence with some elements (possible none) left out. Given a sequence X = < x1, x2, ..., xm > another sequence Z = < z1, z2, ..., zk > is a subsequence of X if th…
1. 问题描述 子串应该比较好理解,至于什么是子序列,这里给出一个例子:有两个母串 cnblogs belong 比如序列bo, bg, lg在母串cnblogs与belong中都出现过并且出现顺序与母串保持一致,我们将其称为公共子序列.最长公共子序列(Longest Common Subsequence, LCS),顾名思义,是指在所有的子序列中最长的那一个.子串是要求更严格的一种子序列,要求在母串中连续地出现.在上述例子的中,最长公共子序列为blog(cnblogs, belong),最长公…
原题链接在这里:http://www.lintcode.com/en/problem/longest-common-subsequence/ 题目: Given two strings, find the longest common subsequence (LCS). Your code should return the length of LCS. Clarification What's the definition of Longest Common Subsequence? htt…
Problem Introduction In this problem, your goal is to compute the length of a longest common subsequence of three sequences. Problem Description Task.Given three sequences \(A=(a_1,a_2,\cdots,a_n)\); \(B = (b_1, b_2,\cdots,b_m)\), and \(C=(c_1,c_2,\c…
最长公共子序列 英文缩写为LCS(Longest Common Subsequence).其定义是,一个序列 S ,如果分别是两个或多个已知序列的子序列,且是所有符合此条件序列中最长的,则 S 称为已知序列的最长公共子序列.而最长公共子串(要求连续)和最长公共子序列是不同的 应用 最长公共子序列是一个十分实用的问题,它可以描述两段文字之间的“相似度”,即它们的雷同程度,从而能够用来辨别抄袭.对一段文字进行修改之后,计算改动前后文字的最长公共子序列,将除此子序列外的部分提取出来,这种方法判断修改的…
Given two strings, find the longest common subsequence (LCS). Your code should return the length of LCS. Clarification What's the definition of Longest Common Subsequence? https://en.wikipedia.org/wiki/Longest_common_subsequence_problem http://baike.…
题目传送门 题意:输出两字符串的最长公共子序列长度 分析:LCS(Longest Common Subsequence)裸题.状态转移方程:dp[i+1][j+1] = dp[i][j] + 1; (s[i] == t[i])dp[i+1][j+1] = max (dp[i][j+1], dp[i+1][j]); (s[i] != t[i]) 代码: #include <cstdio> #include <cstring> #include <iostream> #in…
题目链接:http://acm.hust.edu.cn/vjudge/contest/view.action?cid=87730#problem/F 题目: Description A subsequence of a given sequence is the given sequence with some elements (possible none) left out. Given a sequence X = < x1, x2, ..., xm > another sequence…
Common Subsequence Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 46387   Accepted: 19045 Description A subsequence of a given sequence is the given sequence with some elements (possible none) left out. Given a sequence X = < x1, x2, ..…
最长上升公共子序列(Longest Increasing Common Subsequence,LICS)也是经典DP问题,是LCS与LIS的混合. Problem 求数列 a[1..n], b[1..m]的LICS的长度, a[], b[]数组的元素均为正整数. Solution 考虑如何定义DP状态,定义DP状态就是定义所谓的最优子问题(optimal subproblem),而DP状态要能转移,就是所谓最优子问题要具有重叠子结构. 将DP状态定义为 DP[i][j]:a[1..i], b[…
Common Subsequence Time Limit: 2 Sec  Memory Limit: 64 MBSubmit: 951  Solved: 374 Description A subsequence of a given sequence is the given sequence with some elements (possible none) left out. Given a sequence X = <X1, x2, ..., xm>another sequence…
Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 9595    Accepted Submission(s): 3923 Problem Description A subsequence of a given sequence is the given sequence with some elements (possible none…
Given two strings, find the longest common subsequence (LCS). Your code should return the length of LCS. Example For "ABCD" and "EDCA", the LCS is "A" (or "D", "C"), return 1. For "ABCD" and &quo…
Common Subsequence Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 18765    Accepted Submission(s): 7946 Problem Description A subsequence of a given sequence is the given sequence with some ele…
HDU 1159 题目大意:给定两个字符串,求他们的最长公共子序列的长度 解题思路:设字符串 a = "a0,a1,a2,a3...am-1"(长度为m), b = "b0, b1, b2, b3 ... bn-1"(长度为n), 它们的最长公共子序列为c = "c0, c1, c2, ... ck-1",长度为k, dp[i][j]定义为子串 "a0,a1,...,ai-1" 和 子串"b0,b1,...,bj-1…
1.链接地址: http://poj.org/problem?id=1458 http://bailian.openjudge.cn/practice/1458/ 2.题目: Common Subsequence Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 35411   Accepted: 14080 Description A subsequence of a given sequence is the given…
Common Subsequence Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 20815    Accepted Submission(s): 8954 Problem Description A subsequence of a given sequence is the given sequence with some ele…
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1159 Common Subsequence Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 18201    Accepted Submission(s): 7697 Problem Description A subsequence of…
Common Subsequence Time Limit: 2 Seconds      Memory Limit: 65536 KB A subsequence of a given sequence is the given sequence with some elements (possible none) left out. Given a sequence X = <x1, x2, ..., xm> another sequence Z = <z1, z2, ..., zk…
Common Subsequence Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 43132   Accepted: 17472 Description A subsequence of a given sequence is the given sequence with some elements (possible none) left out. Given a sequence X = < x1, x2, ..…
Common Subsequence Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 18387    Accepted Submission(s): 7769 Problem Description A subsequence of a given sequence is the given sequence with some el…
Common Subsequence Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 24919    Accepted Submission(s): 11035 Problem Description A subsequence of a given sequence is the given sequence with some e…
D - Common Subsequence Time Limit:1000MS     Memory Limit:10000KB     64bit IO Format:%I64d & %I64u Submit Status Description A subsequence of a given sequence is the given sequence with some elements (possible none) left out. Given a sequence X = <…