D,只要抓住每个点只有一个出度,那么图就能分成几个部分,而且可以发现,一个部分最多一个环. #include <iostream> #include <cstdio> #include <algorithm> #include <cstring> using namespace std; #define LL long long const int MAXN = 200005; const int MOD = 1e9 + 7; int nt[MAXN]; i…
(2015年8月5日更新:微软已经修复了Roslyn的这个bug,详见 https://github.com/dotnet/roslyn/pull/4303 ) 昨天,我们用VS2015编译了博客程序中的一个程序集并发布上线. 今天有园友反馈向我们反馈,个人博客分页显示随笔列表的页面中,“上一页”“下一页”显示乱码: 而这个地方的“上一页”“下一页”字符串恰恰是在我们昨天发布的程序集中定义的: public class Pager : Control { protected string Pre…
var h = new Array(); var j = new Array(); var xbCursor = 0; function xbinit() { xbinitName(); xbRectChoose(); xbRectChoosePic(); xbSetVisible(0); Laya.stage.on(laya.events.Event.KEY_DOWN,this,xbOnkeyDown); } function xbinitName() { var d1 = new laya.…
VS2008项目使用VS2015打开时,出现错误: error CS1012: Too many characters in character literal -------------------------------------------------------------------------------------------- 把源码文件转换成UTF-8: Save ***** as.... -> 点击Save 按钮旁边的小黑三角- > Save with Encoding.…
http://blog.csdn.net/cloudresearch/article/details/19092219 在openstack havana的release note中有如下介绍“Attached Cinder volumes can now be encrypted. Data is decrypted as needed at read and write time while presenting instances with a normal block storage d…
Codeforces Round #581(Div. 2) CF 1204 A. BowWow and the Timetable 题解:发现,$4$的幂次的二进制就是一个$1$后面跟偶数个$0$. 所以暴力判一下就好. Code: #include <bits/stdc++.h> #define N 110 using namespace std; char s[N]; int main() { scanf("%s", s + 1); int n = strlen(s +…
Freelancer's Dreams time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output Mikhail the Freelancer dreams of two things: to become a cool programmer and to buy a flat in Moscow. To become a cool p…
终于打了一场CF,不知道为什么我会去打00:05的CF比赛…… 不管怎么样,这次打的很好!拿到了Div. 2选手中的第一名,成功上紫! 以后还要再接再厉! [A]Check the string 题意: 一个合法的字符串可以这样生成: 初始是一个空串,然后小 A 同学往这个串中加入若干(大于零)个字符\(\texttt{a}\),然后小 B 同学往这个串的末尾加入若干(大于零)个字符\(\texttt{b}\),最后小 C 同学往这个串的末尾加入一些字符\(\texttt{c}\),但要满足\(…
CF#581 题解 A BowWow and the Timetable 如果不是4幂次方直接看位数除以二向上取整,否则再减一 #include<iostream> #include<cstring> #include<cstdio> #include<algorithm> #include<vector> #include<set> #include<map> using namespace std; #define M…
1Z0-053 争议题目解析330 考试科目:1Z0-053 题库版本:V13.02 题库中原题为: 330.What will be the end result of this set of RMAN commands? shutdown abort startup mount restore datafile 4 until time ,,09/30/2008:15:00:00; recover datafile 4 until time ,,09/29/2008:15:00:00; al…
