Codeforces Beta Round #17 题目链接:点击我打开题目链接 大概题意: 给你 \(b\),\(n\),\(c\). 让你求:\((b)^{n-1}*(b-1)\%c\). \(2<=b<=10^{10^6},1<=n<=10^{10^6},1<=c<=10^9\) 简明题解: 因为 \(b\) , \(n\)都太大了.关键是求 \((b)^{n-1}\%c\) 所以,我们可以利用欧拉函数 \(phi()\) 的性质. 对于\(a^{b} \% c\…

D. Notepad time limit per test 2 seconds memory limit per test 64 megabytes input standard input output standard output Nick is attracted by everything unconventional. He doesn't like decimal number system any more, and he decided to study other numb…

C. Balance 题目链接 http://codeforces.com/contest/17/problem/C 题面 Nick likes strings very much, he likes to rotate them, sort them, rearrange characters within a string... Once he wrote a random string of characters a, b, c on a piece of paper and began…

A - Noldbach problem 题面链接 http://codeforces.com/contest/17/problem/A 题面 Nick is interested in prime numbers. Once he read about Goldbach problem. It states that every even integer greater than 2 can be expressed as the sum of two primes. That got Nic…

A. Noldbach problem Nick is interested in prime numbers. Once he read about Goldbach problem. It states that every even integer greater than 2 can be expressed as the sum of two primes. That got Nick's attention and he decided to invent a problem of…

C. Balance time limit per test 3 seconds memory limit per test 128 megabytes input standard input output standard output Nick likes strings very much, he likes to rotate them, sort them, rearrange characters within a string... Once he wrote a random…

题目大意 给一个数列,长度不超过 5000,每次可以将其中的一个数加 1 或者减 1,问,最少需要多少次操作,才能使得这个数列单调不降 数列中每个数为 -109-109 中的一个数 做法分析 先这样考虑:如果操作的次数最少,那么最终得到的不降的数列,必然是由原始数列中的数组成的,具体的证明可以使用反证法 知道了上面讲述的性质,这题就好搞了 先将原始数列(设为 A,共 n 个数)中所有的数去重并从小到达排序,保存在另一个数列中(设为 B,共 m 个数) 定义状态:f[i][j] 表示将原始数列中的…

Codeforces Beta Round #80 (Div. 2 Only) A Blackjack1 题意 一共52张扑克,A代表1或者11,2-10表示自己的数字,其他都表示10 现在你已经有一个queen了,问你有多少种方案,能够得到n点 题解 其实只用考虑三种情况,都考虑一下就好了,实在不行就暴力枚举-- 代码 #include<bits/stdc++.h> using namespace std; int n; int main() { scanf("%d",&…

Codeforces Beta Round #62 A Irrational problem 题意 f(x) = x mod p1 mod p2 mod p3 mod p4 问你[a,b]中有多少个数满足f(x)=x 题解 显然直接带进去就好了-- 代码 #include<bits/stdc++.h> using namespace std; int main() { int p1,p2,p3,p4,a,b; scanf("%d%d%d%d%d%d",&p1,&am…

Codeforces Beta Round #83 (Div. 1 Only) A. Dorm Water Supply 题意 给你一个n点m边的图,保证每个点的入度和出度最多为1 如果这个点入度为0,那么这个点就是水龙头点. 如果这个点的出度为0,那么这个点就是储存点. 现在让你把所有水龙头到储存点的路径都输出出来,且输出这条路径的边权最小值 题解 显然是个仙人掌图,所以直接XJB暴力就好了 代码 #include<bits/stdc++.h> using namespace std; co…