题目连接 http://acm.hdu.edu.cn/showproblem.php?pid=1796 处男容斥原理 纪念一下 TMD看了好久才明白DFS... 先贴代码后解释 #include<cstdio> #include<cstring> using namespace std; #define LL long long #define N 11 LL num[N],ans,n; int m,cnt; LL gcd(LL a,LL b) { int t; while…
题目传送:http://acm.hdu.edu.cn/diy/contest_showproblem.php?cid=20918&pid=1002 Problem Description Now you get a number N, and a M-integers set, you should find out how many integers which are small than N, that they can divided exactly by any integers…
题目链接Hdu4135 Co-prime Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 1412 Accepted Submission(s): 531 Problem Description Given a number N, you are asked to count the number of integers betwe…
How many integers can you find Time Limit: 12000/5000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 7439 Accepted Submission(s): 2200 Problem Description Now you get a number N, and a M-integers set, you shoul…
How many integers can you find Problem Description Now you get a number N, and a M-integers set, you should find out how many integers which are small than N, that they can divided exactly by any integers in the set. For example, N=12, and M-intege…
How many integers can you find Time Limit: 12000/5000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 5664 Accepted Submission(s): 1630 Problem Description Now you get a number N, and a M-integers set, you shoul…
容斥原理练习题,忘记处理gcd 和 lcm,wa了几发0.0. #include<iostream> #include<cstdio> #include<cstring> using namespace std; typedef long long ll; ll Num[]; ll gcd(ll a,ll b) { ? a : gcd(b,a%b); } int main() { ll N, M; while(scanf("%lld%lld",&am…
How many integers can you find Time Limit: 12000/5000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Problem Description Now you get a number N, and a M-integers set, you should find out how many integers which are small than N, that…
How many integers can you find Time Limit: 12000/5000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 6434 Accepted Submission(s): 1849 Problem Description Now you get a number N, and a M-integers set, you shou…
How many integers can you find Time Limit: 12000/5000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 6630 Accepted Submission(s): 1913 Problem Description Now you get a number N, and a M-integers set, you shoul…
How many integers can you find Time Limit: 12000/5000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 5556 Accepted Submission(s): 1593 Problem Description Now you get a number N, and a M-integers set, you shou…
How many integers can you find Time Limit: 12000/5000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 6710 Accepted Submission(s): 1946 Problem Description Now you get a number N, and a M-integers set, you shou…
How many integers can you find Time Limit:5000MS Memory Limit:32768KB 64bit IO Format:%I64d & %I64u Submit Status Practice HDU 1796 Description Now you get a number N, and a M-integers set, you should find out how many integers which are sm…
题目链接:Coprime pid=5072"> 题面: Coprime Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 262144/262144 K (Java/Others) Total Submission(s): 1181 Accepted Submission(s): 471 Problem Description There are n people standing in a line. Each of t…
HDU 6321 Dynamic Graph Matching (状压DP) Problem C. Dynamic Graph Matching Time Limit: 8000/4000 MS (Java/Others) Memory Limit: 524288/524288 K (Java/Others) Total Submission(s): 1796 Accepted Submission(s): 731 Problem Description In the mathematical…
Saving HDU Time Limit: 3000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 7194 Accepted Submission(s): 3345 Problem Description 话说上回讲到海东集团面临内外交困,公司的元老也只剩下XHD夫妇二人了.显然,作为多年拼搏的商人,XHD不会坐以待毙的. 一天,当他正在苦思冥想解困良策的…
http://acm.hdu.edu.cn/showproblem.php?pid=3037 Lucas定理模板. 现在才写,noip滚粗前兆QAQ #include<cstdio> #include<cstring> #include<algorithm> using namespace std; typedef long long ll; int jc[100003]; int p; int ipow(int x, int b) { ll t = 1, w = x;…