POJ 4046 Sightseeing】的更多相关文章

Sightseeing Time Limit: 5000ms Memory Limit: 65536KB This problem will be judged on PKU. Original ID: 404664-bit integer IO format: %lld      Java class name: Main   CC and MM arrive at a beautiful city for sightseeing. They have found a map of the c…
有n个节点的m条无向边的图,节点编号为1~n 然后有点权和边权,给出q个询问,每一个询问给出2点u,v 输出u,v的最短距离 这里的最短距离规定为: u到v的路径的所有边权+u到v路径上最大的一个点权的和(点权也可以是u,v) n<=1000 m<=20000 Q<=20000 时限:5000ms 没有点权的话,好处理 加了点权呢? 我们可以先枚举n个节点,跑n次spfa,当枚举节点u时,我们默认节点u是所有路径上点权最大的一个点 即我们枚举节点u时,我们先把点权比u大的节点删除了,在剩…
POJ 1637 Sightseeing tour 题目链接 题意:给一些有向边一些无向边,问能否把无向边定向之后确定一个欧拉回路 思路:这题的模型很的巧妙,转一个http://blog.csdn.net/pi9nc/article/details/12223693 先把有向边随意定向了,然后依据每一个点的入度出度之差,能够确定每一个点须要调整的次数,然后中间就是须要调整的边,容量为1,这样去建图最后推断从源点出发的边是否都满流就可以 代码: #include <cstdio> #includ…
Sightseeing tour Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 6986   Accepted: 2901 Description The city executive board in Lund wants to construct a sightseeing tour by bus in Lund, so that tourists can see every corner of the beauti…
http://poj.org/problem?id=3463 Sightseeing Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 6420   Accepted: 2270 Description Tour operator Your Personal Holiday organises guided bus trips across the Benelux. Every day the bus moves from…
嗯,这是我上一篇文章说的那本宝典的第二题,我只想说,真TM是本宝典……做的我又痛苦又激动……(我感觉ACM的日常尽在这张表情中了) 题目链接:http://poj.org/problem?id=1637 Time Limit: 1000MS Memory Limit: 10000K Description The city executive board in Lund wants to construct a sightseeing tour by bus in Lund, so that t…
题目链接:http://poj.org/problem?id=3621 Sightseeing Cows Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 11526   Accepted: 3930 Description Farmer John has decided to reward his cows for their hard work by taking them on a tour of the big ci…
Sightseeing Cows Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 10306   Accepted: 3519 Description Farmer John has decided to reward his cows for their hard work by taking them on a tour of the big city! The cows must decide how best to…
F - Sightseeing 传送门: POJ - 3463 分析 一句话题意:给你一个有向图,可能有重边,让你求从s到t最短路的条数,如果次短路的长度比最短路的长度多1,那么在加上次短路的条数. 这道题唯一要注意的就是次短路的求法 首先题目中说从起点到终点至少有一条路径,所以我们就不用考虑不可达的情况 我们先考虑如果a到b有一条边,b到c有一条边 那么a到c经过b的路程中次短路只有两种选择,一种是a到b的最短路+b到c的次短路,另一种是a到b的次短路+b到c的次短路 所以我们只需要记录次短路…
Sightseeing tour Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 9276   Accepted: 3924 Description The city executive board in Lund wants to construct a sightseeing tour by bus in Lund, so that tourists can see every corner of the beauti…