题目链接:https://cn.vjudge.net/problem/POJ-2318 题意 在一个矩形内,给出n-1条线段,把矩形分成n快四边形 问某些点在那个四边形内 思路 二分+判断点与位置关系 提交过程 WA*n x1和x2,y1和y2在复制的时候没分清(哭 WA 可能存在二分问题? AC 代码 #define PI 3.1415926 #include <cmath> #include <cstdio> #include <vector> #include &…

TOYS Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 12015   Accepted: 5792 Description Calculate the number of toys that land in each bin of a partitioned toy box. Mom and dad have a problem - their child John never puts his toys away w…

题意: 给一个矩形的区域(左上角为(x1,y1) 右下角为(x2,y2)),给出n对(u,v)表示(u,y1) 和 (v,y2)构成线段将矩形切割 这样构成了n+1个多边形,再给出m个点,问每个多边形内有多少个点. 读入为n,m,x1,y1,x2,y2 n个数对(u,v),m个数对(x,y) (n,m<=5000) 题解: 很暴力的想法是对于每个点,枚举每个多边形进行检查. 但是多组数据就很江 考虑一下判断点在多边形内的射线法可知 枚举一个多边形的时候就可以知道点在多边形的左边还是右边 这样我们…

跨产品的利用率推断点线段向左或向右,然后你可以2分钟 代码: #include <cstdio> #include <cstring> #include <algorithm> using namespace std; const int N = 5005; int n, m, x1, y1, x2, y2; struct Point { int x, y; Point() {} Point(int x, int y) { this->x = x; this-&g…

题目传送门 题意:POJ 2318 有一个长方形,用线段划分若干区域,给若干个点,问每个区域点的分布情况 分析:点和线段的位置判断可以用叉积判断.给的线段是排好序的,但是点是无序的,所以可以用二分优化.用到了叉积 /************************************************ * Author :Running_Time * Created Time :2015/10/23 星期五 11:38:18 * File Name :POJ_2318.cpp ****…

题目传送门:POJ 2318 TOYS Description Calculate the number of toys that land in each bin of a partitioned toy box. Mom and dad have a problem - their child John never puts his toys away when he is finished playing with them. They gave John a rectangular bo…

TOYS Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 8661   Accepted: 4114 Description Calculate the number of toys that land in each bin of a partitioned toy box. Mom and dad have a problem - their child John never puts his toys away wh…

题目大意:给你一个矩形的左上角和右下角的坐标,然后这个矩形有 N 个隔板分割成 N+1 个区域,下面有 M 组坐标,求出来每个区域包含的坐标数.   分析:做的第一道计算几何题目....使用叉积判断方向,然后使用二分查询找到点所在的区域.   代码如下: ==========================================================================================================================…

TOYS Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 10281   Accepted: 4924 Description Calculate the number of toys that land in each bin of a partitioned toy box. Mom and dad have a problem - their child John never puts his toys away w…

<题目链接> 题目大意: 给出矩形4个点和n个挡板俩顶点的位置,这n个挡板将该矩形分成 n+1块区域,再给你m个点的坐标,然你输出每个区域内有几个点. 解题思路: 用叉乘即可简单判断点与直线的位置关系,对每一个点,遍历挡板,直到找到符合的区间为止. #include <cstdio> #include <iostream> #include <algorithm> #include <cstring> using namespace std; +…