仅有两个要注意的点: 如果系数为0,则不输出,所以输入结束以后要先遍历确定系数不为零的项的个数 题目最后一句,精确到小数点后一位,如果这里忽略了,会导致样例1,3,4,5都不能通过…

This time, you are supposed to find A+B where A and B are two polynomials. Input Each input file contains one test case. Each case occupies 2 lines, and each line contains the information of a polynomial: K N1 aN1 N2 aN2 ... NK aNK, where K is the nu…

1002 A+B for Polynomials (25)(25 分) This time, you are supposed to find A+B where A and B are two polynomials. Input Each input file contains one test case. Each case occupies 2 lines, and each line contains the information of a polynomial: K N1 a~N1…

从今天起每天刷1-2题PAT甲级 第一天 A1001 A+B Format (20 分) 题目内容 Calculate a+b and output the sum in standard format -- that is, the digits must be separated into groups of three by commas (unless there are less than four digits). Input Specification: Each input fi…

AC代码 转载自https://www.cnblogs.com/zjutJY/p/9413766.html #include <stdio.h> #include<string.h> //输入:两行数据,每行表示一个多项式:第一个数字表示非零项的数目, //后面每两个数表示一项,分别表示幂次和系数. //输出:两个多项式的和,格式与输入一样 int main(){ const int MAX_N=1111; double a=0.0; int k,n=0,count=0,i;//k…

多项式相加,按非零项个数,指数,系数输入两个n项多项式,合并同类项之后输出. 用数组编号保存指数,编号对应的数组值保存系数,相加之后用count记录非零项的个数,最后输出. 数组最大1000个,如果有10000个呢?是否能用链表做? #include<cstdio> int main(){ ]={0.0}; ; double coe; scanf("%d",&n); ;i<n;i++){ scanf("%d%lf", &exp,&a…

This time, you are supposed to find A+B where A and B are two polynomials. Input Specification: Each input file contains one test case. Each case occupies 2 lines, and each line contains the information of a polynomial: K N​1​​ a​N​1​​​​ N​2​​ a​N​2​…

B1018. 锤子剪刀布 (20) Discription: 大家应该都会玩"锤子剪刀布"的游戏:两人同时给出手势,胜负规则如图所示: 现给出两人的交锋记录,请统计双方的胜.平.负次数,并且给出双方分别出什么手势的胜算最大. Input: 输入第1行给出正整数N(<=105),即双方交锋的次数.随后N行,每行给出一次交锋的信息,即甲.乙双方同时给出的的手势.C代表"锤子".J代表"剪刀".B代表"布",第1个字母代表甲方…

部分常见ORACLE面试题以及SQL注意事项 一.表的创建: 一个通过单列外键联系起父表和子表的简单例子如下: CREATE TABLE parent(id INT NOT NULL, PRIMARY KEY (id) ) CREATE TABLE child(id INT, parent_id INT, INDEX par_ind (parent_id), FOREIGN KEY (parent_id) REFERENCES parent(id) ON DELETE CASCADE ) 建表时…

SQL> select * from (select * from t1 order by id ) where rownum<20; ID A1 A2 A3 ---------- ---------- ---------- ---------- 1 1 1 a1 10 10 10 a10 100 100 100 a100 1000 1000 1000 a1000 10000 10000 10000 a10000 1001 1001 1001 a1001 1002 1002 1002 a100…