传送门:https://www.luogu.org/problemnew/show/P2863 思路:tarjan模板题,之前会的tarjan,一直想学缩点到底是什么操作,发现就是把同组的放在一个数组里(并查集可能又会有),或者重新建图:不知道为什么百度不到讲缩点的blog. #include <iostream> #include <cstdio> #include <algorithm> #include <cstring> #include <s…
题目描述 The N (2 <= N <= 10,000) cows are so excited: it's prom night! They are dressed in their finest gowns, complete with corsages and new shoes. They know that tonight they will each try to perform the Round Dance. Only cows can perform the Round D…
题目描述 The N (2 <= N <= 10,000) cows are so excited: it's prom night! They are dressed in their finest gowns, complete with corsages and new shoes. They know that tonight they will each try to perform the Round Dance. Only cows can perform the Round D…
P2863 [USACO06JAN]牛的舞会The Cow Prom 求点数$>1$的强连通分量数,裸的Tanjan模板. #include<iostream> #include<cstdio> #include<cstring> using namespace std; int min(int &a,int &b){return a<b?a:b;} #define N 10002 #define M 50002 int n,m,clo,df…
洛谷——P2863 [USACO06JAN]牛的舞会The Cow Prom 题目描述 The N (2 <= N <= 10,000) cows are so excited: it's prom night! They are dressed in their finest gowns, complete with corsages and new shoes. They know that tonight they will each try to perform the Round D…
P2863 [USACO06JAN]牛的舞会The Cow Prom 123通过 221提交 题目提供者 洛谷OnlineJudge 标签 USACO 2006 云端 难度 普及+/提高 时空限制 1s / 128MB 题目描述 The N (2 <= N <= 10,000) cows are so excited: it's prom night! They are dressed in their finest gowns, complete with corsages and new…
https://www.luogu.org/problem/show?pid=2863#sub 题目描述 The N (2 <= N <= 10,000) cows are so excited: it's prom night! They are dressed in their finest gowns, complete with corsages and new shoes. They know that tonight they will each try to perform th…
题目链接:https://www.luogu.org/problemnew/show/P2863 求强连通分量大小>自己单个点的 #include <stack> #include <cstdio> #include <cstring> #include <iostream> #include <algorithm> using namespace std; const int maxn = 100000 + 10; struct edge…
题目传送门 这个题还是个缩点的板子题...... 答案就是size大于1的强连通分量的个数 加一个size来统计就好了 #include <iostream> #include <cstdlib> #include <cstdio> using namespace std; const int N=1e5+5; const int M=5e5+5; struct edge{ int to,next; }e[M]; int n,m,dfn[N],low[N],cnt,he…
传送门 题目大意:形成一个环的牛可以跳舞,几个环连在一起是个小组,求几个小组. 题解:tarjian缩点后,求缩的点包含的原来的点数大于1的个数. 代码: #include<iostream> #include<cstdio> #include<cstring> #define maxn 10009 using namespace std; int n,m,sumedge,top,sumclr,tim,ans; int Stack[maxn],instack[maxn]…