http://codeforces.com/contest/220/problem/B 题意:给出一个数组,给出m组询问,问区间中出现a[i] 次的有多少个. sl: 很显然的离线问题了. 大视野菜花的加强版. 可以这么搞,假设当前走到了a 看看之前是不是有a个a有的话就在a-k处 减1 同时补上上次的操作就行.具体键代码. http://codeforces.com/contest/220/submission/6948720…

二次联通门 : Codeforces 221d D. Little Elephant and Array /* Codeforces 221d D. Little Elephant and Array 题意 : 询问一段区间中出现次数等于自身的数的个数 正解是dp 莫队水过, 作为我莫队的入门题 myj的思路 66 把所有需查询的区间排序 当前查询区间的答案为上一个区间的答案通过多次的区间移动得出 */ #include <algorithm> #include <cstdio>…

D. Little Elephant and Array time limit per test 4 seconds memory limit per test 256 megabytes input standard input output standard output The Little Elephant loves playing with arrays. He has array a, consisting of n positive integers, indexed from…

Little Elephant and Array Time Limit: 4000ms Memory Limit: 262144KB This problem will be judged on CodeForces. Original ID: 221D64-bit integer IO format: %I64d      Java class name: (Any) The Little Elephant loves playing with arrays. He has array a,…

221D - Little Elephant and Array 思路: 莫队: 代码: #include <cmath> #include <cstdio> #include <cstring> #include <iostream> #include <algorithm> using namespace std; #define maxn 100005 struct QueryType { int l,r,id; }; struct Que…

B. Little Elephant and Array time limit per test 4 seconds memory limit per test 256 megabytes input standard input output standard output The Little Elephant loves playing with arrays. He has array a, consisting of n positive integers, indexed from…

vjudge上莫队专题 真的是要吐槽自己(自己的莫队手残写了2个bug) s=sqrt(n) 是元素的个数而不是询问的个数(之所以是sqrt(n)使得左端点每个块左端点的范围嘴都是sqrt(n)) 在重载<是将q[i].l/s<q2[i].l/s 写成q1[i].l<s<q2[i].l<s 导致一下午都在调bug疯了 Sona 比小Z的袜子简单,直接维护区间频度的^3 需要离散化(离散化化的标号应提前准备好,如果用时在二分查找会增加复杂度) 还有比较坑的一点是多case,但样…

B. Little Elephant and Array time limit per test 4 seconds memory limit per test 256 megabytes input standard input output standard output The Little Elephant loves playing with arrays. He has array a, consisting of n positive integers, indexed from…

The Little Elephant loves playing with arrays. He has array a, consisting of npositive integers, indexed from 1 to n. Let's denote the number with index i as ai. Additionally the Little Elephant has m queries to the array, each query is characterised…

This problem can be solve in simpler O(NsqrtN) solution, but I will describe O(NlogN) one. We will solve this problem in offline. For each x (0 ≤ x < n) we should keep all the queries that end in x. Iterate that x from 0 to n - 1. Also we need to kee…