在数据库查询操作过程中,子查询结果不唯一,导致外面的查询无法进行. 我的错误语句: rid = models.User.objects.filter(username=username).values('user2role__role_id_id__id') grp_bukrs = models.Role2Menufun.objects.filter(role_id=rid).values('menufun_id__bukrs').first()['menufun_id__bukrs'] 实际上…
1. 错误描述 1 queries executed, 0 success, 1 errors, 0 warnings 查询:SELECT t.id, DATE_FORMAT( t.statisTime, '%Y-%m-%d %H:%i:%s' ) statisTime, (SELECT `id` FROM t_truck_info WHERE id = t.plateId... 错误代码: 1242 Subquery returns more than 1 row 执行耗时 : 0.009 s…
http://blog.csdn.net/c517984604/article/details/7052186 [Err] 1242 - Subquery returns more than 1 row   --表示子查询返回了多行数据 例如: select * from table1 where table1.colums=(select columns from table2) 解决方法 1,select * from table1 where column=any(select colum…
我的SQL语句是这样写的. mysql> select 1,2,3 and updatexml(1,concat(1,(select user from mysql.user),1),1);ERROR 1242 (21000): Subquery returns more than 1 row 报错翻译就是:子查询返回超过1行 子查询是不能超过一行的,那么我们直接将其组合即可. 可以使用limit 1 或者group_concat() 即可.…
watch_course_sql ) , '%%Y-%%m-%%d %%T') regtime, a.username FROM bskuser a where a.UserName in (select username from bskchapterlist where lessonid = (select id from bsklesson a WHERE a.lessonname like \'%s\') ) limit """ ) 前台传来的coursename应该…
Subquery returns more than 1 row表示子查询返回了多行数据 例如: select * from table1 where table1.colums=(select columns from table2) 解决方法 select * from table1 where table1.colums=any(select columns from table2)…
Subquery returns more than 1 row表示子查询返回了多行数据 例如: select * from table1 where table1.colums=(select columns from table2) 解决方法 select * from table1 where table1.colums=any(select columns from table2)…
使用Xadmin,执行makemigrations和migrate时运行报错提示: AttributeError: 'Settings' object has no attribute 'TEMPLATE_CONTEXT_PROCESSORS' 方法一: setting.py文件添加以下信息: TEMPLATE_CONTEXT_PROCESSORS = ( 'django.contrib.auth.context_processors.auth', 'django.core.context_pr…
django增加用户认证模块时,总是提醒模块的url.py中 url(r'^login/$', 'django.contrib.auth.views.login', name='login'),出错: TypeError: view must be a callable or a list/tuple in the case of include(). 解决办法:改为下面的写法 from django.contrib.auth.views import login ... url(r'^logi…
django提交表单提示"RuntimeError: You called this URL via POST, but the URL doesn’t end in a slash and you have APPEND_SLASH set." 提示form的action地址最后不是/结尾的,而且APPEND_SLASH的值是Ture 将from的action地址改为/结尾的就可以了 或者修改settings:APPEND_SLASH=False…