A  Currency System in Geraldion Time Limit:2000MS     Memory Limit:262144KB     64bit IO Format:%I64d & %I64u   Description A magic island Geraldion, where Gerald lives, has its own currency system. It uses banknotes of several values. But the proble…
A. Currency System in Geraldion Time Limit: 1 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/contest/560/problem/A Description A magic island Geraldion, where Gerald lives, has its own currency system. It uses banknotes of several values. But th…
A. Currency System in Geraldion Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/contest/560/problem/A Description A magic island Geraldion, where Gerald lives, has its own currency system. It uses banknotes of several values. But t…
[CF简单介绍] 提交链接:http://codeforces.com/contest/560/problem/A 题面: A. Currency System in Geraldion time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output A magic island Geraldion, where Gerald lives,…
A  Currency System in Geraldion Time Limit:2000MS     Memory Limit:262144KB     64bit IO Format:%I64d & %I64u   Description A magic island Geraldion, where Gerald lives, has its own currency system. It uses banknotes of several values. But the proble…
A. Currency System in Geraldion time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output A magic island Geraldion, where Gerald lives, has its own currency system. It uses banknotes of several valu…
time limit per test2 seconds memory limit per test256 megabytes inputstandard input outputstandard output A magic island Geraldion, where Gerald lives, has its own currency system. It uses banknotes of several values. But the problem is, the system i…
standard output A magic island Geraldion, where Gerald lives, has its own currency system. It uses banknotes of several values. But the problem is, the system is not perfect and sometimes it happens that Geraldionians cannot express a certain sum of…
题目: Description A magic island Geraldion, where Gerald lives, has its own currency system. It uses banknotes of several values. But the problem is, the system is not perfect and sometimes it happens that Geraldionians cannot express a certain sum of…
A题,超级大水题,根据有没有1输出-1和1就行了.我沙茶,把%d写成了%n. B题,也水,两个矩形的长和宽分别加一下,剩下的两个取大的那个,看看是否框得下. C题,其实也很简单,题目保证了小三角形是正三角形,一个正三角的面积=l*l*(1/2)*cos(30),由于只要算三角形个数,把六边形扩成一个大三角,剪掉三个小三角,除一下系数就没了.就变成了平方相减. D题,根据定义递归.然后注意奇数就行了.我沙茶,没加第一种判断dfs(a+len,len,b+len) && dfs(a,len,b…
Description A magic island Geraldion, where Gerald lives, has its own currency system. It uses banknotes of several values. But the problem is, the system is not perfect and sometimes it happens that Geraldionians cannot express a certain sum of mone…
A. Currency System in Geraldion time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output A magic island Geraldion, where Gerald lives, has its own currency system. It uses banknotes of several valu…
A题: 题目地址:Currency System in Geraldion 题意:给出n中货币的面值(每种货币有无数张),要求不能表示出的货币的最小值.若全部面值的都能表示,输出-1. 思路:水题,就是看看有没有面值为1的货币,假设有的话,全部面值的货币都能够通过1的累加得到,假设没有的话.最小的不能表示的就当然是1辣. #include <stdio.h> #include <math.h> #include <string.h> #include <stdli…
A. Currency System in Geraldion: 题意:有n中不同面额的纸币,问用这些纸币所不能加和到的值的最小值. 思路:显然假设这些纸币的最小钱为1的话,它就能够组成随意面额. 假设这些纸币的最小值大于1,那么它所不能组成的最小面额就是1.所以自学求最小值就可以. 我的代码: #include <set> #include <map> #include <cmath> #include <stack> #include <queue…
题目链接   A. Currency System in Geraldion 有1时,所有大于等于1的数都可由1组成.没有1时,最小不幸的数就是1. #include<iostream> #include<cstdio> #include<algorithm> using namespace std; void solve(){ int n,x; scanf("%d",&n); ; ; i<=n; i++){ scanf("%…
Beautiful Currency Time Limit: 1 Sec Memory Limit: 256 MB 题目连接 http://acm.hust.edu.cn/vjudge/contest/view.action?cid=93265#problem/F Description KM country has N kinds of coins and each coin has its value a_i. The king of the country, Kita_masa, thou…
System.Data.DbType 与其它DbType的映射关系 有如下类型的映射对照: System.Data.SqlClient.SqlDbType System.Data.OleDb.OleDbType System.Data.Odbc.OdbcType System.Data.OracleClient.OracleType 格式: DbType.枚举名(枚举值) = DbType.枚举名(枚举值) =========== System.Data.SqlClient.SqlDbType…
有如下类型的映射对照: System.Data.SqlClient.SqlDbType  System.Data.OleDb.OleDbType System.Data.Odbc.OdbcType System.Data.OracleClient.OracleType 格式: DbType.枚举名(枚举值) = DbType.枚举名(枚举值) =========== System.Data.SqlClient.SqlDbType ========= System.Data.SqlClient.S…
F. Beautiful Currency Time Limit: 5000ms Case Time Limit: 5000ms Memory Limit: 65536KB 64-bit integer IO format: %lld      Java class name: Main cid=6641#" class="submitprob button ui-button ui-widget ui-state-default ui-corner-all ui-button-tex…
http://poj.org/problem?id=3260   Description Farmer John has gone to town to buy some farm supplies. Being a very efficient man, he always pays for his goods in such a way that the smallest number of coins changes hands, i.e., the number of coins he…
B1022. D进制的A+B (20) Description: 输入两个非负10进制整数A和B(<=230-1),输出A+B的D (1 < D <= 10)进制数. Input: 输入在一行中依次给出3个整数A.B和D. Output: 输出A+B的D进制数. Sample Input: 123 456 8 Sample Output: 1103 #include <cstdio> int main() { int a, b, d; scanf("%d%d%d&q…
The Fewest Coins Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 6299   Accepted: 1922 Description Farmer John has gone to town to buy some farm supplies. Being a very efficient man, he always pays for his goods in such a way that the sm…
The trouble of Xiaoqian Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 1472 Accepted Submission(s): 502 Problem Description In the country of ALPC , Xiaoqian is a very famous mathematician. She i…
The Fewest Coins DescriptionFarmer John has gone to town to buy some farm supplies. Being a very efficient man, he always pays for his goods in such a way that the smallest number of coins changes hands, i.e., the number of coins he uses to pay plus…
Description Farmer John has gone to town to buy some farm supplies. Being a very efficient man, he always pays for his goods in such a way that the smallest number of coins changes hands, i.e., the number of coins he uses to pay plus the number of co…
1058. A+B in Hogwarts (20) 时间限制 50 ms 内存限制 32000 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue If you are a fan of Harry Potter, you would know the world of magic has its own currency system -- as Hagrid explained it to Harry, "Seventeen silver Sickle…
 变量 1.变量就是数据存储空间的表示. 2.标识符命名规则:变量名=首字母+其余部分 ①首字母:字母.下划线.“$”符号(开头) ②其余部分:数字.字母.下划线“$” ③应避开关键字:int int = 10;(不可) ④符合驼峰命名法:若名字由多个单词组成,从第二个单词开始,首字母均大写:myShoolScore ⑤不能使用保留字来命名(51个关键字)如下: 数据类型: Boolean    int    long    short    byte    float    double   …
1058. A+B in Hogwarts (20) 时间限制 50 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue If you are a fan of Harry Potter, you would know the world of magic has its own currency system -- as Hagrid explained it to Harry, "Seventeen silver Sickle…
1058 A+B in Hogwarts (20 分)   If you are a fan of Harry Potter, you would know the world of magic has its own currency system -- as Hagrid explained it to Harry, "Seventeen silver Sickles to a Galleon and twenty-nine Knuts to a Sickle, it's easy enou…
If you are a fan of Harry Potter, you would know the world of magic has its own currency system -- as Hagrid explained it to Harry, "Seventeen silver Sickles to a Galleon and twenty-nine Knuts to a Sickle, it's easy enough." Your job is to write…