[LeetCode]109. Convert Sorted List to Binary Search Tree 解题报告(Python) 标签(空格分隔): LeetCode 作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.me/ 题目地址:https://leetcode.com/problems/convert-sorted-list-to-binary-search-tree/description/ 题目描述: Given a s…
108. Convert Sorted Array to Binary Search Tree Given an array where elements are sorted in ascending order, convert it to a height balanced BST. /** * Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left; * TreeNode *ri…
Given a singly linked list where elements are sorted in ascending order, convert it to a height balanced BST. For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the two subtrees of every node never diffe…
一天一道LeetCode 本系列文章已全部上传至我的github,地址:ZeeCoder's Github 欢迎大家关注我的新浪微博,我的新浪微博 欢迎转载,转载请注明出处 (一)题目 Given a singly linked list where elements are sorted in ascending order, convert it to a height balanced BST. (二)解题 本题大意:给定一个单向链表,构造出平衡二叉搜索树 解题思路:参考[一天一道Leet…
Given a singly linked list where elements are sorted in ascending order, convert it to a height balanced BST. 和上一题类似,把数组换成链表,所以可以两种做法: 1.把链表换成数组,然后用上一题的方法,这样会比较慢. 2.每次找到中间的点,作为节点,然后递归,其实原理还是二分查找. /** * Definition for singly-linked list. * public…
Given a singly linked list where elements are sorted in ascending order, convert it to a height balanced BST. 涉及到二叉树的问题用递归的方法很容易理解.这个问题要求把一个升序排序的链表转换为一颗height balanced BST.转换的方式就是把链表的中间值作为树的根节点,中间值的左半部分转换为二叉树的左子树,中间值的右半部分转换为二叉树的右子树. 递归解决问题的步骤如下: 1. 如…
Question: Given a singly linked list where elements are sorted in ascending order, convert it to a height balanced BST. For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the two subtrees of every node n…
Given a singly linked list where elements are sorted in ascending order, convert it to a height balanced BST. 解题思路: 同上题,JAVA实现如下: public TreeNode sortedListToBST(ListNode head) { ArrayList<Integer> list=new ArrayList<Integer>(); while(head!=nu…