Given an array nums containing n + 1 integers where each integer is between 1 and n (inclusive), prove that at least one duplicate number must exist. Assume that there is only one duplicate number, find the duplicate one. Example 1: Input: [1,3,4,2,2…

public class Solution { public int FindDuplicate(int[] nums) { ) { ]; ]]; while (slow != fast) { slow = nums[slow]; fast = nums[nums[fast]]; } fast = ; while (fast != slow) { fast = nums[fast]; slow = nums[slow]; } return slow; } ; } } https://leetco…

思路: 转换成链表之后使用floyed判环法.转换之后重复的那个数字是唯一一个有多个前驱和一个后继的节点,因此是环的起始节点. 实现: class Solution { public: int findDuplicate(vector<int>& nums) { ], q = nums[]; while (true) { p = nums[nums[p]]; q = nums[q]; if (p == q) break; } p = nums[]; while (true) { if…

Find the Duplicate Number Given an array nums containing n + 1 integers where each integer is between 1 and n (inclusive), prove that at least one duplicate number must exist. Assume that there is only one duplicate number, find the duplicate one. No…

今天操作系统课,没能安心睡懒觉23333,妹抖龙更新,可惜感觉水分不少....怀念追RE0的感觉 =================================================================== leetcode283 Move Zeroes leetcode287 Find the Duplicate Number leetcode289 Game of Life ==============================================…