解题关键:1.直接套kmp模板即可,注意最后输出的位置,需要在索引的位置+1. 2.next用作数组名在oj中会编译错误, 3.选用g++,只有g++才会接受bits/stdc++.h OJ中g++和c++的区别: 1.输出double类型时,如果采用G++提交,scanf采用%lf,printf采用%f,否则会报错 2.使用GCC/G++的提醒: 对于64位整数, long long int 和 __int64 都是支持并且等价的.但是在读和写的时候只支持scanf("%I64d",…
Number Sequence Time Limit: 10000/5000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 17971 Accepted Submission(s): 7854 Problem Description Given two sequences of numbers : a[1], a[2], ...... , a[N], and b[1], b…
Number Sequence Time Limit: 10000/5000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 24587 Accepted Submission(s): 10436 Problem Description Given two sequences of numbers : a[1], a[2], ...... , a[N], and b[1],…
题意 找到子串在母串出现的第一个位置 解法 裸的KMP 特别的地方 第一次不看模板自己敲的KMP #include<stdio.h> const int maxn=100000; const int MAXN=1000000; int next[maxn]; int S[MAXN]; int T[maxn]; int N,M; void get_next() { for(int i=2;i<=M;i++) { int p=i-1; while(T[next[p]+1]!=T[i]&…
Number Sequence Time Limit: 10000/5000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 40053 Accepted Submission(s): 16510 Problem Description Given two sequences of numbers : a[1], a[2], ...... , a[N], and b[1],…
题目地址:http://acm.hdu.edu.cn/showproblem.php?pid=1711 题目: Problem Description Given two sequences of numbers : a[1], a[2], ...... , a[N], and b[1], b[2], ...... , b[M] (1 <= M <= 10000, 1 <= N <= 1000000). Your task is to find a number K which m…