作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 题目地址: https://leetcode.com/problems/longest-substring-with-at-least-k-repeating-characters/description/ 题目描述: Find the length of the longest substring T of a given string (consists of lowercase…
题目如下: 解题思路:题目要找出一段连续的子串内所有字符出现的次数必须要大于k,因此出现次数小于k的字符就一定不能出现,所以就可以以这些字符作为分隔符分割成多个子串,然后继续对子串递归,找出符合条件的子串. 代码如下: class Solution(object): res = 0 def splitToSubs(self,subs,k): dic = {} for i in subs: if i not in dic: dic[i] = 1 else: dic[i] += 1 exclusiv…
395. Longest Substring with At Least K Repeating Characters 我的思路是先扫描一遍,然后判断是否都满足,否则,不满足的字符一定不出现,可以作为分割符,然后不断切割,重复这个过程,我不知道运行时间,感觉会tle,然后交了,就ac了. class Solution { public: int work(string &s, int k, int x, int y) { if(y - x + 1 < k) return 0; set<…
Difficulty: Hard More:[目录]LeetCode Java实现 Description Given a string S, find the length of the longest substring T that contains at most two distinct characters.For example,Given S = “eceba”,T is "ece" which its length is 3. Intuition 方法一:假设有一个…
Find the length of the longest substring T of a given string (consists of lowercase letters only) such that every character in T appears no less than k times. Example 1: Input: s = "aaabb", k = 3 Output: 3 The longest substring is "aaa"…
Find the length of the longest substring T of a given string (consists of lowercase letters only) such that every character in T appears no less than k times. Example 1: Input: s = "aaabb", k = 3 Output: 3 The longest substring is "aaa"…
Find the length of the longest substring T of a given string (consists of lowercase letters only) such that every character in T appears no less than k times. Example 1: Input: s = "aaabb", k = 3 Output: 3 The longest substring is "aaa"…
Find the length of the longest substring T of a given string (consists of lowercase letters only) such that every character in T appears no less than k times. Example 1: Input: s = "aaabb", k = 3 Output: 3 The longest substring is "aaa"…
只能说还是太菜,抄的网上大神的做法: idea: mask 的每一位代表该位字母够不够k次,够k次为0,不够为1 对于每一位将其视为起点,遍历至末尾,找到其最大满足子串T的下标max_idx,之后从max_idx+1开始遍历. 代码如下: public int longestSubstring(String s, int k) { if (k == 1) return s.length(); int res = 0, i = 0, n = s.length(); while (i + k <=…
