hdu4686 Arc of Dream 2013 Multi-University Training Contest 9矩阵快速幂

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hdu4686 Arc of Dream 2013 Multi-University Training Contest 9矩阵快速幂

Arc of Dream Time Limit: 2000/2000 MS (Java/Others) Memory Limit: 65535/65535 K (Java/Others) Total Submission(s): 932 Accepted Submission(s): 322 Problem Description An Arc of Dream is a curve defined by following function:where a0 = A0 ai = a…

2013长沙邀请赛A So Easy!(矩阵快速幂，共轭)

So Easy! Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 2286 Accepted Submission(s): 710 Problem Description A sequence Sn is defined as:Where a, b, n, m are positive integers.┌x┐is the ceil…

poj 3735 Training little cats 矩阵快速幂+稀疏矩阵乘法优化

题目链接题意:有n个猫,开始的时候每个猫都没有坚果,进行k次操作,g x表示给第x个猫一个坚果,e x表示第x个猫吃掉所有坚果,s x y表示第x个猫和第y个猫交换所有坚果,将k次操作重复进行m轮,问最后这n个猫各自有多少坚果. 题解:构造(n+1)*(n+1)的单位矩阵,data[i][j]表示第i个猫与第j个猫进行交换,最后一列的前n项就是每个猫的坚果数目,s操作就交换对应行,矩阵快速幂时间复杂度O(n^3*log2(m))会超时,我们注意到在n*n的范围内每一行只有一个1,利用稀疏矩阵的…

POJ 3735 Training little cats<矩阵快速幂/稀疏矩阵的优化>

Training little cats Time Limit: 2000MS Memory Limit: 65536K Total Submissions: 13488 Accepted: 3335 Description Facer's pet cat just gave birth to a brood of little cats. Having considered the health of those lovely cats, Facer decides to make t…

Training little cats_矩阵快速幂

Description Facer's pet cat just gave birth to a brood of little cats. Having considered the health of those lovely cats, Facer decides to make the cats to do some exercises. Facer has well designed a set of moves for his cats. He is now asking you t…

poj 3753 Training little cats_矩阵快速幂

题意: 通过各种操作进行,给第i只猫花生,第i只猫吃光花生,第i只猫和第j只猫互换花生,问n次循环操作后结果是什么很明显是构建个矩阵,然后矩阵相乘就好了 #include <iostream> #include <cstdio> #include<cstring> using namespace std; #define LL long long #define N 110 LL n,m,d; struct node{ LL mat[N][N]; node opera…

POJ 3735 Training little cats 矩阵快速幂

http://poj.org/problem?id=3735 给定一串操作,要这个操作连续执行m次后,最后剩下的值. 记矩阵T为一次操作后的值,那么T^m就是执行m次的值了.(其实这个还不太理解,但是数据一相乘,就是ans) 构造一个0--n的单位矩阵,用第0行作为各个猫的值,这样的话,用A={1,0,0,0}一乘就是每个毛的ans. 构造单位矩阵的意义就是他们矩阵自己相乘的时候,能够保留自己的值. 这个矩阵很分散,0的那些可以特判掉不枚举多一程O(n)了.这需要你的矩阵乘法是一个一个加上去的,…