[算法题] Search in Rotated Sorted Array】的更多相关文章

题目内容 题目来源:LeetCode Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand. (i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2). Write a function to determine if a given target is in the array. The array may contain…
题目内容 本题来源LeetCode Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand. (i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2). You are given a target value to search. If found in the array return its index, otherwi…
Suppose a sorted array is rotated at some pivot unknown to you beforehand. (i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2). You are given a target value to search. If found in the array return its index, otherwise return -1. You may assume no duplic…
Follow up for "Search in Rotated Sorted Array":What if duplicates are allowed? Would this affect the run-time complexity? How and why? Write a function to determine if a given target is in the array. 题解:如果没有重复的元素,那么就可以根据target是否在某一半而扔掉另外一半.但是如果有…
一.题目说明 这个题目是33. Search in Rotated Sorted Array,说的是在一个"扭转"的有序列表中,查找一个元素,时间复杂度O(logn). 二.我的解答 这是一个查找,根据复杂度,我们知道只能用二分查找.但由于这个不是一个完全的有序列表,故需要改造.先写出二分查找(来源于数据结构): 二分查找: int search(vector<int>& nums, int target){ if(nums.size()<0) return…
原题链接,点我 该题解题参考博客 和Search in Rotated Sorted Array唯一的区别是这道题目中元素会有重复的情况出现.不过正是因为这个条件的出现,出现了比较复杂的case,甚至影响到了算法的时间复杂度.原来我们是依靠中间和边缘元素的大小关系,来判断哪一半是不受rotate影响,仍然有序的.而现在因为重复的出现,如果我们遇到中间和边缘相等的情况,我们就丢失了哪边有序的信息,因为哪边都有可能是有序的结果.假设原数组是{1,2,3,3,3,3,3},那么旋转之后有可能是{3,3…
LeetCode:Search in Rotated Sorted Array Suppose a sorted array is rotated at some pivot unknown to you beforehand. (i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2). You are given a target value to search. If found in the array return its index, other…
做Leetcode题有一段时间了,但都是断断续续的,到现在才做了30题左右,感觉对自己来说还是有点难度的.希望自己能继续坚持下去,在校招前能解决超过一百题吧. 其实这些题就是用来训练你的解题思路的,做多了的话,才能在校招时面对编程题目,能立即有一个解题的流程,知道这是哪一种类型的题目,一般用什么样的套路,思路会很清晰,比如基础的字符串,数组操作会用到一些排序算法,还有一类是算法思想的题目,比如DP(动态规划),分治,回溯法,贪心等等,多练,多思考,多总结. ‘庖丁解牛,恢恢乎游刃有余’,无他,唯…
33. Search in Rotated Sorted Array Suppose a sorted array is rotated at some pivot unknown to you beforehand. (i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2). You are given a target value to search. If found in the array return its index, otherwise…
Follow up for "Search in Rotated Sorted Array":What if duplicates are allowed? Would this affect the run-time complexity? How and why? Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand. (i.e., 0 1 2 4…